Archives: Solution Manual

Chapter 9 Ratio of boundary layer thickness to width

Chapter 9 Ratio of boundary layer thickness to width

9.66: PROBLEM DEFINITION Situation: A passenger train 81 m long with a 10 m perimeter moving through air at 81.1 km/hr and 204 km/hr. Boundary layer is tripped. Find: Powerrequiredatbothspeeds. Surface resistance at both speeds. Properties: Table A.3 ν=1.41 ×10−5m2/s, […]

10 Pages | March 28, 2023
Chapter 9 Problem Definition Situation Model Airplane With Span

Chapter 9 Problem Definition Situation Model Airplane With Span

9.53: PROBLEM DEFINITION Situation: Displacement thickness for a linear velocity profile. Find: Magnitude of displacement thickness. SOLUTION The equation for displacement thickness is 0 Displacement thickness δ∗=3mm 2 δ∗=1.5mm 61 δ∗=Zδ 0µ1−ρu ρ∞U∞¶dy For constant density δ∗=Zδ 0 (1 −u […]

10 Pages | March 28, 2023
Chapter 9 Solution Flow Smooth Three Dierently Shaped Velocity

Chapter 9 Solution Flow Smooth Three Dierently Shaped Velocity

9.37: PROBLEM DEFINITION Situation: A liquid flows past a smooth flat plate at U0=2m/s. Find: Liquid velocity at a location x=1.0 m downstream from the leading edge and y= 0.8 mm from surface. Properties: ν=2×10−5.m2/s, μ=2×10−2N·s/m2,ρ= 1000 kg/m3 PLAN Calculate […]

14 Pages | March 28, 2023
Chapter 9 A viscosity measuring device is consists of measuring

Chapter 9 A viscosity measuring device is consists of measuring

9.18: PROBLEM DEFINITION Situation: A viscosity measuring device is consists of measuring torque on bearing. There is a 10-cm cylinder with 4-cm shaft and 4.5-cm bearing. A force of 0.6 N force on inner cylinder rotates system at 20 rpm. […]

14 Pages | March 28, 2023
Chapter 9 The shear stress is constant across the flow so

Chapter 9 The shear stress is constant across the flow so

9.1: PROBLEM DEFINITION Situation: In which case is the flow caused by a pressure gradient? a. Couette flow b. Hele-Shaw flow SOLUTION 1 The correct answer is b) Hele-Shaw flow 9.2: PROBLEM DEFINITION Situation: Couette flow of liquid with temperature […]

14 Pages | March 28, 2023
Chapter 8 Find The Largest Feasible Scale Ratio Solution

Chapter 8 Find The Largest Feasible Scale Ratio Solution

8.65: PROBLEM DEFINITION Situation: A model of spillway modeled in laboratory. 1 40 scale model. Vm=3.2ft/s,Qm=3.53 ft3/s. Find: Prototype velocity (ft/s) . Prototype discharge (ft/s) . PLAN UseFroudenumberscaling. SOLUTION Match Froude number Multiply both sides of Eq. (1) by Ap/Am=(Lp/Lm)2 […]

9 Pages | March 28, 2023
Chapter 8 Find Speed Air The Wind Tunnel Match

Chapter 8 Find Speed Air The Wind Tunnel Match

8.51: PROBLEM DEFINITION Situation: Forces due to wind on a building are to be modeled by using a scale model in wind tunnel. 1 500 scale model. Vp=47ft/s,Vm=300ft/s. Fm=50lbf. Find: Density needed for the air in the wind tunnel ¡slug/ft3¢. […]

10 Pages | March 28, 2023
Chapter 8 Wind tunnel test done for a Beoing 787 to simulate

Chapter 8 Wind tunnel test done for a Beoing 787 to simulate

8.36: PROBLEM DEFINITION Situation: A large venturi meter is calibrated with a scale model using a prototype liquid. 1 10 scale model, p=400kPa. Find: The discharge ratio (Qm/Qp) Pressure difference (∆pp)expected for the prototype. SOLUTION Match Reynolds number Multiply both […]

14 Pages | March 28, 2023
Chapter 8 From The Internet Given Ratio Pulsatile Transient

Chapter 8 From The Internet Given Ratio Pulsatile Transient

Collecting like powers gives 21 µ˙m2 D4ρ∆p¶d =µμD ˙m¶c A functional relationship is ˙m √ρ∆pD2=fµμD ˙m¶ 8.19: PROBLEM DEFINITION Situation: A torpedo-like device travels just below the water surface. Find: Identify which π−groups are significant. Justify the answer. SOLUTION •Viscous […]

14 Pages | March 28, 2023
Chapter 8 Qis the flow rate produced by the fan

Chapter 8 Qis the flow rate produced by the fan

8.1: PROBLEM DEFINITION Situation: Dimensions of density, viscosity and pressure. Find: Primary dimensions of density, viscosity and pressure. SOLUTION Density 1 [ρ]=M L3 Viscosity [μ]= M LT Pressure [p]= M LT 2 8.2: PROBLEM DEFINITION Situation: Application of the Buckingham […]

14 Pages | March 28, 2023
Chapter 7 Let the velocity in the 6 inch pipe be V6

Chapter 7 Let the velocity in the 6 inch pipe be V6

7.83: PROBLEM DEFINITION Situation: A reservoir discharges into a pipe. Find: Draw the HGL and EGL. SOLUTION 120 37.2 m 42.6 m 2000 m 80 m 7.84: PROBLEM DEFINITION Situation: Water discharges through a turbine. Q=1000cfs, η=85%. hL=4ft,H=100ft. Find: Power […]

12 Pages | March 28, 2023
Chapter 7 Find the head loss by applying the sudden

Chapter 7 Find the head loss by applying the sudden

7.70: PROBLEM DEFINITION Situation: An abrupt expansion dissipates high energy flow. D1=5ft,p1=5psig. V=25ft/s,D2=10ft. Find: (a) Horsepower lost (hp). (b) Pressure at section 2 (psig). (c) Force needed to hold expansion (lbf). Assumptions: α=1.0. Properties: Water, γ=62.4lbf/ft3. PLAN Find the head […]

13 Pages | March 28, 2023
Chapter 7 Find electrical power using the efficiency equation

Chapter 7 Find electrical power using the efficiency equation

7.55: PROBLEM DEFINITION Situation: Q=500cfs, η=90%. hL=1.5V2 2g,D=7ft. z1=35ft,z2=0ft. Find: Power output from turbine. Assumptions: α=1.0. PLAN Apply the energy equation from the upstream water surface to the downstream water surface. Then apply the power equation. SOLUTION Energy equation: Power […]

14 Pages | March 28, 2023
Chapter 7 Apply the energy equation between the top of 

Chapter 7 Apply the energy equation between the top of 

7.44: PROBLEM DEFINITION Situation: Apumpfills a tank with water from a river. Dtank =5m,Dpipe =5cm. hL=10V2 2/2g,hp=20−4×104Q2. Find: Time required to fill tank to depth of 10 m. Assumptions: α=1.0. SOLUTION Energy equation (locate 1 on the surface of the […]

14 Pages | March 28, 2023
Chapter 7 Find Head Loss Between Reservoir Surface And

Chapter 7 Find Head Loss Between Reservoir Surface And

41 p2=16.9psig 7.32: PROBLEM DEFINITION Situation: Water flows from a pressurized tank, through a valve and out a pipe. p1=100kPa,z1=8m. p2=0kPa,z 2=0m. hL=KLV2 2g,V2=10m/s. Find: The minor loss coefficient (KL). Assumptions: Steady flow. Outlet flow is turbulent so that α2=1.0. […]

14 Pages | March 28, 2023
Chapter 7 Problem Definition Situation Water Ows Vertical Pipe

Chapter 7 Problem Definition Situation Water Ows Vertical Pipe

7.17: PROBLEM DEFINITION Situation: The velocity distribution in a pipe with turbulent flow is given by V Vmax =µy r0¶n Find: Derive a formula for αas a function of n. Find αfor n=1/7. SOLUTION Flow rate equation Upon integration Q=2πVmaxr2 […]

14 Pages | March 28, 2023
Chapter 7 Find Minimum Electrical Power Watts Assumptions Neglect

Chapter 7 Find Minimum Electrical Power Watts Assumptions Neglect

Problem 7.1 Fill in the blank. Show your work. b. ____ ft ·lbf = energy to lift 10 N weight through elevation difference of 125 m. Recall that energy and work have the same dimensions. Here we are asked to […]

14 Pages | March 28, 2023
Chapter 6 The Downward Load The Head Due The

Chapter 6 The Downward Load The Head Due The

where Mis the mass of the cart (mass of water moving with cart is negligible) From conservation of mass Combining terms XFx=d dt(Mvc)+ ˙m(v2x−v1) 0=Mdvc dt +ρA1(vj−vc)(vc−vj) Mdvc dt =ρA1v2 j(1 −vc vj )2 =˙mvj(1 −vc vj )2 Since the […]

10 Pages | March 28, 2023
Chapter 6 Find Thrust The Turbofan Engine Assumptions Neglect

Chapter 6 Find Thrust The Turbofan Engine Assumptions Neglect

6.83: PROBLEM DEFINITION Situation: Lift and drag forces are being measured on an airfoil that is situated in a wind tunnel–additional details are provided in the problem statement. yp u 8m / s 2 12 m / s0.25 m 0.25 […]

11 Pages | March 28, 2023
Chapter 6 Assumption Given That Typical Window Withstands Force

Chapter 6 Assumption Given That Typical Window Withstands Force

6.70: PROBLEM DEFINITION Situation: Water flows through a 60oreducing bend–additional details are provided in the problem statement. Find: Horizontal force required to hold bend in place: Fx PLAN Apply the Bernoulli equation, then the momentum equation. SOLUTION Bernoulli equation Let […]

14 Pages | March 28, 2023
Chapter 6 Solution The Pressure Forces Acting The Inlet

Chapter 6 Solution The Pressure Forces Acting The Inlet

6.54: PROBLEM DEFINITION Situation: An unusual nozzle creates two jets of water. d=0.5in,v 2=v3=80.2ft/s. D=3.5in.p =50psig. Find: Force required at the flange to hold the nozzle in place: F PLAN Apply the continuity equation, then the momentum equation. SOLUTION Continuity […]

14 Pages | March 28, 2023
Chapter 6 Problem Definition Situation Clam Shell Thrust

Chapter 6 Problem Definition Situation Clam Shell Thrust

6.40: PROBLEM DEFINITION Situation: A clam shell thrust reverser is deployed on an aircraft engine. Find: (a) The thrust under normal operation. (b) the reverse thrust. Assumptions: Engine is stationary. Exit gas velocity unchanged at deployment. Pressure is atmospheric at […]

14 Pages | March 28, 2023
Chapter 6 A water jet strikes a block and the block is held

Chapter 6 A water jet strikes a block and the block is held

6.27: PROBLEM DEFINITION Situation: A water jet strikes a block and the block is held in place by friction. v1=10m/s, ˙m=1.5 kg/s. μ=0.1,m=1kg. Find: Will the block slip? Force of the water jet on the block (N). Sketch: Assumptions: Neglect […]

14 Pages | March 28, 2023
Chapter 6 Problem Definition Situation Gravel Ows Into Barge

Chapter 6 Problem Definition Situation Gravel Ows Into Barge

2. The forces (F1and F2)are each about 40 lbf. This magnitude of force may be 21 too large for users of a toy. Or, this magnitude of force may lead to material failure (it breaks!). It is recommended that the […]

14 Pages | March 28, 2023
Chapter 6 A surface force because the wing must touch

Chapter 6 A surface force because the wing must touch

6.1: PROBLEM DEFINITION Situation: Identify the surface and body forces acting on a glider in flight. Also, sketch a free body diagram and explain how Newton’s laws of motion apply. Find: Surface and body forces acting on a glider in […]

14 Pages | March 28, 2023
Chapter 5 Solution Let The Pressure The Streamline Upstream

Chapter 5 Solution Let The Pressure The Streamline Upstream

5.103: PROBLEM DEFINITION Situation: Air flows through constant area, heated pipe. D=4in,V=10m/s. p2=80kPa,p 1=100kPa. Find: Velo city at exit. Determine if the Bernoulli equation be used to relate the pressure and velocity changes. Properties: T1=20◦C,T2=50◦C. PLAN Apply the continuity equation. […]

9 Pages | March 28, 2023
Chapter 5 Therefore The Atomizer Operate All The Pressure

Chapter 5 Therefore The Atomizer Operate All The Pressure

5.94: PROBLEM DEFINITION Situation: Water flows in a pipe with a contraction. Q=60ft 3/s,d=2ft,D=6ft. Find: Pressure at point B. Assumptions: Water temperature is 50 ◦F. Properties: Water (50 ◦F),Table A.5: γ=62.4lbf/ft3. pA=3200psf. PLAN Apply the Bernoulli equation and the continuity […]

9 Pages | March 28, 2023
Chapter 5 Time to increase the density of the air in the

Chapter 5 Time to increase the density of the air in the

5.77: PROBLEM DEFINITION Situation: Atankisfilled with air from a compressor. V=10m 3,˙m=0.5ρ0 ρkg/s. Find: Time to increase the density of the air in the tank by a factor of 2. Properties: ρ0=2kg/m3 PLAN Apply the continuity equation. SOLUTION Continuity equation […]

14 Pages | March 28, 2023
Chapter 5 Definition Situation Nozzle Discharges Water Onto Plate

Chapter 5 Definition Situation Nozzle Discharges Water Onto Plate

5.59: PROBLEM DEFINITION Situation: A sphere is falling in a cylinder filled with water. D1=8in,D2=1ft,V1=4ft/s. Find: Velocity of water at the midsection of the sphere. Sketch: PLAN Apply the continuity equation. SOLUTION As shown in the above sketch, select a […]

14 Pages | March 28, 2023
Chapter 5 The Reynolds transport theorem is used to relate

Chapter 5 The Reynolds transport theorem is used to relate

5.39: PROBLEM DEFINITION Situation: InFig5.11in§5.2ofEFM10e, a. the CV is passing through the system. b. the system is passing through the CV. SOLUTION 41 The answer is (b), the system, which is a defined mass (think of the system as a […]

14 Pages | March 28, 2023
Chapter 5 Problem Definition Situation Water Ows Pipe 85

Chapter 5 Problem Definition Situation Water Ows Pipe 85

5.21: PROBLEM DEFINITION Situation: A rectangular channel has a 30oincline. u=8[exp(y)−1] m/s. y=1m,x=2m. Find: Discharge (m3/s). Mean velocity ( m/s). PLAN Apply the integral form of the flow rate equation becuse velocity is not constant over the area. SOLUTION Discharge. […]

14 Pages | March 28, 2023
Chapter 5 Problem Definition Situation Air Ows Rectangular Air

Chapter 5 Problem Definition Situation Air Ows Rectangular Air

5.1: PROBLEM DEFINITION Situation: Consider an automobile gas tank being filled by a nozzle. Find: (a) Discharge (gpm). (b) Time to put 50 gallons in the tank (min). (c) Cross-sectional area (ft2) of the nozzle and velocity at the exit […]

14 Pages | March 28, 2023
Chapter 4 Problem Definition Situation Fuel Tank Rotated Zero gravity

Chapter 4 Problem Definition Situation Fuel Tank Rotated Zero gravity

4.97: PROBLEM DEFINITION Situation: Stirring a liquid in a cup. Find: Report on the contour of the surface. Provide an explanation for the observed shape. SOLUTION Stirring the cup of liquid creates a surface depressed at the center and higher […]

13 Pages | March 28, 2023
Chapter 4 Problem Definition Situation Velocity And Pressure Given

Chapter 4 Problem Definition Situation Velocity And Pressure Given

4.79: PROBLEM DEFINITION Situation: A two-dimensional velocity field is represented by the vector V=10xi−10yj. Find: Is the flow irrotational? SOLUTION In a two dimensional flow in the x−yplane, the flow is irrotational if (Eq. 4.34a) 81 ∂v ∂x =∂u ∂y […]

14 Pages | March 28, 2023
Chapter 4 Two Pitot tubes are connected to air-water

Chapter 4 Two Pitot tubes are connected to air-water

4.61: PROBLEM DEFINITION Situation: A Pitot tube measures the flow direction and velocity in water. Find: Explain how to design the Pitot tube. SOLUTION Three pressure taps could be located on a sphere at an equal distance from the 61 […]

14 Pages | March 28, 2023
Chapter 4 Solution The Correct Answers Are And Review

Chapter 4 Solution The Correct Answers Are And Review

4.41: PROBLEM DEFINITION Situation: Water accelerated from rest in horizontal pipe. L=80m,D=30cm,as=5m/s2. Find: Pressure at upstream end (kPa). Properties: ρ=1000kg/m3,pdownstream =90kPa. PLAN Apply Euler’s equation. SOLUTION Euler’s equation with no change in elevation 41 ∂p ∂s =−ρas =−1,000 kg/m3×5m/s2 =−5,000 […]

14 Pages | March 28, 2023
Chapter 4 The acceleration halfway between the entrance

Chapter 4 The acceleration halfway between the entrance

4.21: PROBLEM DEFINITION Situation: In a flowing fluid, acceleration means that a fluid particle is a. changing direction b. changing speed c. changing both speed and direction d. any of the above SOLUTION 21 The correct answer is d. 4.22: […]

14 Pages | March 28, 2023
Chapter 4 Problem Definition Situation For Path lines Streak lines And

Chapter 4 Problem Definition Situation For Path lines Streak lines And

4.1: PROBLEM DEFINITION Situation: Path of a fluid particle. Find: If a light was attached to a fluid particle and take a time exposure, would the image you photographed be a pathline or streakline? SOLUTION 1 Thepathlineisdefined as the path […]

14 Pages | March 28, 2023
Chapter 3 Length of chain so that gate just on verge of opening

Chapter 3 Length of chain so that gate just on verge of opening

3.110: PROBLEM DEFINITION Situation: A submerged gate is described in the problem statement. d=25cm,W=200N. y=10m,L=1m. Find: Length of chain so that gate just on verge of opening. PLAN Apply hydrostatic force equations and then sum moments about the hinge. SOLUTION […]

10 Pages | March 28, 2023
Chapter 3 Which sphere has the largest buoyant force

Chapter 3 Which sphere has the largest buoyant force

3.95: PROBLEM DEFINITION Situation: Three spheres of the same diameter are submerged in the same body of water. One sphere is steel, one is a spherical balloon filled with water, and one is a spherical balloon filled with air. a. […]

11 Pages | March 28, 2023
Chapter 3 The Vertical Component Hydrostatic Force Will The

Chapter 3 The Vertical Component Hydrostatic Force Will The

3.82: PROBLEM DEFINITION Situation: A concrete form is described in the problem statement. y1=1.5m,θ=60◦. Find: Moment at base of form per meter of length (kN·m/m). Properties: Concrete, γ=24kN/m3. Assumptions: Assume that the form has a length of w=1meterintothepaper. PLAN Find […]

14 Pages | March 28, 2023
Management Chapter 16 Today, the opportunities and challenges presented by changes

Management Chapter 16 Today, the opportunities and challenges presented by changes

16.2 Understand ways in which management must change. 16.3 Take actions toward becoming a resonant leader. 16.4 Develop your leadership skills. Next chapter 16 explains how to continue the journey to becoming a resonant leader. A few steps include trying […]

5 Pages | March 28, 2023
Chapter 3 Solution The Length Gate Hydrostatic Force

Chapter 3 Solution The Length Gate Hydrostatic Force

Therefore, TAdoes not change with H. The correct answers are obtained by reviewing the above solution. 101 a, b, and e are valid statements. 3.70: PROBLEM DEFINITION Situation: Water exerts a load on square panel. d=1m,h=2m Find: (a) Depth of […]

14 Pages | March 28, 2023
Chapter 3 The Scale Would Linear Problem 363 Using

Chapter 3 The Scale Would Linear Problem 363 Using

3.56: PROBLEM DEFINITION Situation: A manometer is used to measure pressure at the center of a pipe. Find: Pressure at center of pipe A (kPa). Properties: Water (10 ◦C,1atm),Table A.5, γwater =9810N/m3. PLAN Since the manometer is applied to measure […]

14 Pages | March 28, 2023
Management Chapter 15 Prentice Hall Have You Ever Provided Service

Management Chapter 15 Prentice Hall Have You Ever Provided Service

1 15.5 Define social sustainability. 15.6 Define economic sustainability. 15.7 Define corporate social responsibility. 15.8 List steps companies can take to be socially responsible. 15.9 Define HR’s role in sustainability and corporate social responsibility. 15.10 Describe steps you can take […]

12 Pages | March 28, 2023
Chapter 3 Column Rise 120 Mm Due Pressure And

Chapter 3 Column Rise 120 Mm Due Pressure And

3.41: PROBLEM DEFINITION Situation: AtmosphericconditionsonMars. •Temperature at the Martian surface is T=−63 ◦C=210K The pressure at the Martian surface is p=7mbar. Find: Pressure at an elevation of 8 km. Pressure at an elevation of 30 km. Assumptions: Assume the atmosphere […]

14 Pages | March 28, 2023
Management Chapter 14 However Seen With One Member Nation Greece

Management Chapter 14 However Seen With One Member Nation Greece

1 14.3 Define the key economic factors that are affecting global business. 14.4 List factors that must be considered when developing a global business strategy. 14.5 Define and assess the opportunities and risks in a global business environment. 14.6 Learn […]

14 Pages | March 28, 2023
Chapter 3 To derive an equation for the load on the bolts

Chapter 3 To derive an equation for the load on the bolts

41 h2=4mg (S)(γwater)(πD2 1)=4(5kg)(9.81 m/s2) (0.8) (9810 N/m3)(π)(0.122m2) h2=0.553 m 3.27: PROBLEM DEFINITION Situation: An odd tank contains water, air and a liquid. . Find: Maximum gage pressure (kPa). Where will maximum pressure occur. Hydrostatic force (in kN) on top […]

14 Pages | March 28, 2023
Management Chapter 13 What Was The Nature The Diversity This

Management Chapter 13 What Was The Nature The Diversity This

13.4 Explain various types of organizational cultures. 13.5 Learn how to study organizational culture. 13.6 Assess the important aspects of organizational culture. 13.7 Learn how HR can support the development of positive organizational cultures. 13.8 Learn ways we can create […]

11 Pages | March 28, 2023
Chapter 3 Problem Definition Situation Regarding The Hydraulic Jack

Chapter 3 Problem Definition Situation Regarding The Hydraulic Jack

Assumptions: Density of air is constant. Properties: Air, ρ=1.1kg/m3. Solution: Pressure at summit: psummit =pbase +∆p= 940 mbar −µ3947 Pa 1.0¶µ10−2mbar Pa ¶ psummit = 901 mbar (absolute) d.) Situation: Pressure increases with depth in a lake. ∆z=350m. Find: Pressure […]

14 Pages | March 28, 2023