Archives: Solution Manual

2-1 Ethics in Information Technology, Sixth Edition Chapter 2 Ethics for IT Workers and IT Users At a Glance • Quick Quizzes • Critical Thinking Exercises • Discussion Questions • Additional Projects • Additional Resources • Key Terms Instructor’s Manual […]

The remaining ones are 2, 1, 3, 4 cost = 2+6+1+4 = 13 2, 1, 4, 3 cost = 2+6+8+9 = 25 2, 3, 1, 4 cost = 2+3+5+4 = 14 2, 3, 4, 1 cost = 2+3+8+7 = 20 […]

4. Bathsheba syndrome 5. d. Misuse of company time 6. c. About 40 percent 7. False 8. False 9. c. Some 6.2 million 10. b. Code of ethics 11. c. Become familiar with various philosophers and how they dealt with […]

(a) Does the Hamming distance satisfy the three axioms of a distance metric listed in Problem 4? 6. BOdd pie fight There are ≥3people positioned in a field (Euclidean plane) so that each has a unique nearest neighbor. Each person […]

1-1 Ethics in Information Technology, Sixth Edition Chapter 1 An Overview of Ethics At a Glance • Teaching Tips • Critical Thinking Exercises • Quick Quizzes • Discussion Questions • Additional Projects • Additional Resources • Key Terms Instructor’s Manual […]

This file contains the exercises, hints, and solutions for Chapter 3 of the book ”Introduction to the Design and Analysis of Algorithms,” 3rd edition, by Exercises 3.1 1. a. Give an example of an algorithm that should not be considered […]

The initial condition is verified immediately: (1) = 12=1 b. ()=(−1) + 1 for 1(1) = 0Solving it by backward substitutions (it’s almost identical to the factorial example–see Example 1 in the section) or by applying the formula for the […]

10. Mental arithmetic A10×10 table is filled with repeating numbers on its diagonals as shown below. Calculate the total sum of the table’s numbers in your head. (after [Cra07, Question 1.33]) 2 3 3 10 10 9 9 11 12 […]

This file contains the exercises, hints, and solutions for Chapter 2 of the book ”Introduction to the Design and Analysis of Algorithms,” 3rd edition, by Exercises 2.1 1. For each of the following algorithms, indicate (i) a natural size metric […]

8. Consider the following map: a b c d 9. Design an algorithm for the following problem: Given a set of points in the Cartesian plane, determine whether all of them lie on the same circumference. 10. Write a program […]

This file contains the exercises, hints, and solutions for Chapter 1 of the book ”Introduction to the Design and Analysis of Algorithms,” 3rd edition, by Exercises 1.1 1. Do some research on al-Khorezmi (also al-Khwarizmi), the man from whose name […]

  15.044.106.05.7 15.044.106.05.7 20.008.0 jj jj jZ s    6193.0468.1 j   87.22594.1    lagging %14.9287.22cosfactor power      87.220.276 87.22594.1 0440     s s sZ V I […]

CHAPTER 17 Exercises E17.1 From Equation 17.5, we have )240cos()()120cos()()cos()( gap    tKitKitKiBc b a Using the expressions given in the Exercise statement for the currents, we have )240cos()120cos( )120cos()240cos()cos()cos( gap       tKI […]

Nm 3980.0 60 2 1200 ref , rot    π ω m T At no load, we have 0 out  T and rot dev TT  . A 2857.0 393.1 3980.0 dev  φ K T IA […]

CHAPTER 16 Exercises E16.1 The input power to the dc motor is loss outsourcesource in PPIVP  Substituting values and solving for the source current we have 335074650220  source I A 8.184 source I Also we have %76.91 335074650 […]

dt di L dt di Me 2 2 1 2         dt td dt td e 1000exp2 1.0 1000exp 2.0 1           dt td […]

CHAPTER 15 Exercises E15.1 If one grasps the wire with the right hand and with the thumb pointing north, the fingers point west under the wire and curl around to point east above the wire. E15.2 If one places the […]

and the rate of change of the output is     tV dt tdv om o ωω cos The maximum rate of change of the output is   om oV dt tdv ω max Thus, we require […]

P14.25 (a) 21 00 vRivo  R vv io 21   Since io is independent of the load, the output impedance is infinite. (b) The circuit diagram is: Writing KVL around loop #1, we have ininin RiRiv  0 […]

CHAPTER 14 Exercises E14.1 (a) A A AR v i  B B BR v i  B B A A B A FR v R v iii          B B A […]

(e) We are given )2000sin(520)()( ttiti s B  . From which we determine that A. 25 and A, 20 A, 15 maxmin μμμ  BBQBIII Then at the intersections of the load line with the respective characteristics, we determine […]

CHAPTER 13 Exercises E13.1 The emitter current is given by the Shockley equation:               1exp T BE ESEV v Ii For operation with 1exp have we , […]

Substituting values and solving we find 582.1 GSQ V V and 582.3 GSQ V V. The correct root is 582.3 GSQ V V. (As a check, we see that the device does operate in saturation because we have 8 DSQ […]

CHAPTER 12 Exercises E12.1 (a) vGS  1 V and vDS  5 V: Because we have vGS < Vto , the FET is in cutoff. (b) vGS  3 V and vDS  0.5 V: Because vGS > Vto […]

(d) The gain magnitude is constant and the phase is proportional to frequency so this amplifier produces no amplitude or phase distortion. P11.79 The sketch is The relationship between rise time and bandwidth is: B tr 35.0  Percentage tilt, […]

P11.39 The equivalent circuit is: 7 36 3 8 10667.6 50 100 1050010 10500 10       i i i ooc voc I I V V A  50 iB iRR  200 oA oRR Thus, […]

CHAPTER 11 Exercises E11.1 (a) A noninverting amplifier has positive gain. Thus )2000sin(0.5)(50)()( ttvtvAtv ii vo π (b) An inverting amplifier has negative gain. Thus )2000sin(0.5)(50)()( ttvtvAtv ii vo π E11.2 7525 oc    L o v i […]

P10.65 P10.66 37 © 2014 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, […]

P2 = (0.1375, 0.25, 0.3006, 0.3119) P3 = (0.1603, 0.2272, 0.2778, 0.3347) P4 = (0.15, 0.2477, 0.2778, 0.3244) P5 = (0.15, 0.2385, 0.2825, 0.3290) … P9 = (0.1513, 0.2406, 0.2806, 0.3276) P10 = (0.1513, 0.2406, 0.2806, 0.3276) P = (0.1513, […]

Reduce: Each processor is assigned to count a single item. • ❑ b Map: Each processor counts all local items. Reduce: Each processor is assigned to count pairs for a bucket. ▼ ❑ Section 3 • ❑ 1 {1, 2, […]

We must be careful to choose the value of R small enough so z I remains positive for all values of source voltage and load current. (Keep in mind that the Zener diode cannot supply power.) From the circuit, we […]

Computers_g (cID, proc, speed, memory, hd) Monitors_g (mID, screen, maxResX, maxResY) Systems_g (sID, mID) INSERT INTO Monitors_g SELECT number, screen, maxResX, maxResY from Monitors INSERT INTO Systems_g SELECT id, number from Systems, Monitors WHERE Systems.screenSize = Monitors.Screen (Note: We could […]

CHAPTER 10 Exercises E10.1 Solving Equation 10.1 for the saturation current and substituting values, we have 4 15 10 exp(0.600 / 0.026) 1 9.502 10 A     Then for 0.650 D v  V, we have 15 […]

emits the pair (w, i), where i is the id of the document d. The intermediate result is a list of pairs (w1, i1),(w2, i2),…. The input to reduce function is a pair (w, [i1, i2, …, in]), where the […]

APPENDIX C PC.1 Because the capacitor voltage is zero at t = 0, the charge on the capacitor is zero at t = 0. Then using Equation 3.5 in the text, we have tdx dxtitq t t 33 0)()( 0 […]

T3 rolled back since it reads C written by T2. wrote D, but no transaction has read D, so no further rollbacks are needed. T3 rolled back since it reads B written by T1. uncommitted. If lost tail starts between […]

APPENDIX A Exercises EA.1 Given ,68 and 32 21 jZjZ  we have: 310 21 jZZ  96 21 jZZ  123418122416 2 21 jjjjZZ  36.002.0 100 18241216 68 68 68 32 / 2 21 j jjj j j […]

1 2 3 4 5 6 w2(D)u2(D)u2(B)u2(C) 18.4.4 Schedule is r1(A)r1(B)w1(B)r1(C)w1(C)r1(D)w1(D)r1(E)w1(E) With locks: Ul1(A)r1(A)ul1(B)r1(B)xl1(B)w1(B)ul1(C)r1(C)xl1(C)w1(C)ul1(D)r1(D)xl1(D)w1(D)ul1(E)r1 (E)xl1(E)w1(E) (Quest: shared or update lock better for concurrency?) 18.4.5a) Requested S X M S Yes No No X No No No M No No Yes […]

CHAPTER 9 Exercises E9.1 The equivalent circuit for the sensor and the input resistance of the amplifier is shown i Figure 9.2 in the book. Thus the input voltage is in sensor in sensor in RR R vv   […]

18.1.1) r1(A); r1(B); w1(B); r1(C); w1(C); r1(D); w1(D); r1(E); w1(E) 18.1.2) Think of the interleaving as having 10 positions. The 4 actions of the first transaction occupy any 4 of the 10, so the number of interleavings is (10 choose […]

CHAPTER 8 Exercises E8.1 The number of bits in the memory addresses is the same as the address bus width, which is 20. Thus, the number of unique addresses is 220 = 1,048,576 = 1024  1024 = 1024K. E8.2 […]

BABAY  CBCBZ  P7.78 By inspection, we see that XA  The Karnaugh maps for B and C are: YXYXB  XYZZYXZYXZYXC  P7.79* (a) DBBCAF  38 © 2014 Pearson Education, Inc., Upper Saddle River, NJ. All rights […]

u = + u Write(B, u) Output(B) crash here ok t = t + u Write(A) Output(A) Write(A) u = t + 1 Write(B) Output(B) crash here ok Output(A) Database Systems: The Complete Book ▼ ❑ Chapter 17 ▼ ❑ […]

P7.52 Applying De Morgan’s Laws to the output of the circuit, we have )()())(( DCBADCBA  Thus, the circuit implemented with NOR gates is P7.53* The truth table is: A B A  B 0 0 0 0 1 1 […]

• ❑ b <Condition> ::= <Attribute> > <Attribute> <Condition> ::= <Attribute> >= <Attribute> <Condition> ::= <Attribute> < <Attribute> <Condition> ::= <Attribute> <= <Attribute> • ❑ c <Condition> ::= ( <Condition> ) • ❑ d <Condition> ::= EXISTS ( <Query> ) […]

CHAPTER 7 Exercises E7.1 (a) For the whole part, we have: Quotient Remainders 23/2 11 1 11/2 5 1 5/2 2 1 2/2 1 0 1/2 0 1 Reading the remainders in reverse order, we obtain: 2310 = 101112 For […]

R . C lo s e ( ) ; S . Open ( ) ; GetNext ( ) {xT u ple ←g e t t h e s m a l l e s t t u p l e […]

(c) At very low frequencies, with the capacitance considered to be an open circuit, no current flows and )( fH becomes very small in magnitude as shown in the plot. (d) At very high frequencies with the inductance considered as […]

r e t u r n joined c u r r T u p l e and matched tuple from H ; } / / We come here if did not find a match; read next tuple in R c […]

P6.91 (a) Applying the voltage-division principle, we have fCjR R R fH    2/1 1 )( 1 2 2 (b) A MATLAB program to produce the desired plot is R1 = 9000; R2 = 1000; C = 1e-8; […]