Archives: Solution Manual
978-0073380292 Chapter 3 Part 8
Statics 2e 403 Vector expressions for the forces appearing in the FBD may be written as E WD2kg 9:81 m=s2.O{/;(6) E FEF DFEF cos 20ıO{sin 20ıO|;(7) EnC 0:7500 O{C0:4330 O|0:4330 O k E RCDRC nC DRC 0:9682 ;(8) E RDDRC […]
978-0073380292 Chapter 3 Part 7
Statics 2e 383 Part (b) With the values WD300 lb , kD25 lb=in: , and rD20 in: given in the problem statement, Eq. (8) contains one unknown, namely d . Two strategies for determining the value of d that satisfies […]
978-0073380292 Chapter 3 Part 6
Statics 2e 363 November 6, 2019 This solutions manual, in any print or electronic form, remains the property of McGraw-Hill, Inc. It may be used and/or possessed only by permission of McGraw-Hill, and must be surrendered upon request of McGraw-Hill. […]
978-0073380292 Chapter 3 Part 5
Statics 2e 343 Part (c) The equation is probably very accurate for loads between 0 and 300 lb , and possibly could be used for loads as high as perhaps 400 lb . For loads less than zero, the hanger […]
978-0073380292 Chapter 3 Part 4
Problem 3.50 Repeat Part (b) of Example 3.4 on p. 140, using optimization methods of calculus. Hint: Solve Eqs. (4) and (5) in Example 3.4 for FBD as a function of ˛ . Then solve for the value of ˛ […]
978-0073380292 Chapter 3 Part 3
Statics 2e 303 Problem 3.35 Determine the largest weight W that may be supported if the failure strengths of the cables and bars are Member Strength AC 600 lb AE 250 lb CD 300 lb AB 2000 lb tension & […]
978-0073380292 Chapter 3 Part 2
Problem 3.17 Guy wire AB is used to help support the utility pole AC . If the guy wire AB can support a maximum tensile force of 500 lb , and if the pole AC can support a maximum compressive […]
978-0073380292 Chapter 3 Part 1
Solutions Manual Engineering Mechanics: Statics 2nd Edition Michael E. Plesha University of Wisconsin–Madison Gary L. Gray The Pennsylvania State University Francesco Costanzo The Pennsylvania State University With the assistance of: Chris Punshon Andrew J. Miller Justin High Chris O’Brien Chandan […]
978-0073380292 Chapter 2 Part 12
Statics 2e 249 The vector component of E Pperpendicular to the the fiber direction is then E P?DE PE PkD.10 O k/ kN .3:482 O{3:482 O|5:868 O k/ kN D.3:48 O{C3:48 O|4:13 O k/ kN:(9) As a partial check of […]
978-0073380292 Chapter 2 Part 11
Problem 2.165 The vector from point O to point P has magnitude 40 mm and has equal direction angles with the x , y , and ´ axes. Determine the smallest distance from point Pto the infinite plane containing points […]
978-0073380292 Chapter 2 Part 10
Statics 2e 213 Problem 2.153 For the triangular-shaped window of Prob. 2.109 on p. 95, use the cross product to determine the outward normal unit vector (i.e., pointing away from the origin) and the area of the window. Solution Our […]
978-0073380292 Chapter 2 Part 9
Problem 2.135 A sports car at point A drives down a straight stretch of road CD . A police car at point B uses radar to measure the speed of the car, and obtains a reading of 80 km=h . […]
978-0073380292 Chapter 2 Part 8
Problem 2.117 A cantilever I beam has a cable at end B that supports a force E F , and ErAB is the position vector from end A of the beam to end B . Position vectors Er1 and Er2 […]
978-0073380292 Chapter 2 Part 7
Statics 2e 153 Problem 2.98 A wall-mounted jib crane consists of an I beam that is supported by a pin at point A and a cable at point C , where A and C lie in the xy plane. A […]
978-0073380292 Chapter 2 Part 6
Problem 2.82 A theodolite is an instrument that measures horizontal and vertical angular orientations of a line of sight. The line of sight may be established optically, or by laser, and many forms of theodolite are used in surveying, construction, […]
978-0073380292 Chapter 2 Part 5
Problem 2.63 Repeat Prob. 2.62 if point Bis 39 mm from point C. Solution Begin by determining the vector ErCA (where point Ais the head of the vector and point Cis the tail): ErCA D.185 mm 125 mm/O{C.0 144 mm/O|D.60 […]
978-0073380292 Chapter 2 Part 4
Statics 2e 93 Problem 2.46 A Caterpillar Ultra High Demolition machine is shown. The distances between points A and B is 12:5 m, points B and C is 2:8 m, C and D is 7 m, and D and E […]
978-0073380292 Chapter 2 Part 3
Statics 2e 73 Problem 2.29 For the following problems, use an xy Cartesian coordinate system where x is horizontal, positive to the right, and y is vertical, positive upward. For problems where the answers require vector expressions, report the vectors […]
978-0073380292 Chapter 2 Part 2
Problem 2.13 Add the three vectors shown to form a resultant vector E R , and report your result using polar vector representation. Solution R 80 lb 60 lb 40 lb P 45◦ α α γ Part (a) The vector […]
978-0073380292 Chapter 1 Part 2
Problem 1.14 If the weight of a certain object on the surface of the Earth is 0.254 lb, determine its mass in kilograms. Solution We first determine the mass of the object in slugs using wDmg )mDw=g D.0:254 lb/=.32:2 ft=s2/D7:888103lb […]
978-0073380292 Chapter 1 Part 1
Solutions Manual Engineering Mechanics: Statics 2nd Edition Michael E. Plesha University of Wisconsin–Madison Gary L. Gray The Pennsylvania State University Francesco Costanzo The Pennsylvania State University With the assistance of: Chris Punshon Andrew J. Miller Justin High Chris O’Brien Chandan […]
978-0073376301 Chapter 19
Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 19 More on Variation and Decision Making Under Risk 19.1 (a) Continuous (b) Discrete (c) Discrete (d) Continuous (e) Continuous 19.2 (a) Discrete and Certainty (b) […]
978-0073376301 Chapter 18 Part 2
14 AW2.25 = –225,000(A/P,6%,10) + (–50,000)(0.1) AW2.5 = –300,000(A/P,6%,10) + (–50,000)(0.05) = –350,000(0.13587) –50,000(0.05) = $–43,261 AW3.0 = –400,000(A/P,6%,10) + (–50,000)(0.01) = –400,000(0.13587) –50,000(0.01) = $–54,848 AW3.25 = –450,000(A/P,6%,10) + (–50,000)(0.005) = –450,000(0.13587) –50,000(0.005) = $–61,392 Build a wall to […]
978-0073376301 Chapter 18 Part 1
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 18 Sensitivity Analysis and Staged Decisions 18.1 $135,000: PW = -500,000 + 135,000(P/A,15%,5) 18.2 Start family now: FW = 50,000(F/A,10%, 5)(F/P,10%,20) + 15,000(F/A,10%,20) = 50,000(6.1051)(6.7275) […]
978-0073376301 Chapter 17 Part 2
17 PWB = –22,000 + 1450(P/F,7%,1) + … + 2500(P/F,7%,10) 17.47 Alternative A Year P & S GI – OE D TI Taxes CFAT 0 -8000 – – – – -8000 1 3500 2666 834 333 3167 2 3500 3556 […]
978-0073376301 Chapter 17 Part 1
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 17 After-Tax Economic Analysis 17.1 (a) Graduated rates: higher taxable incomes pay taxes at higher rates. 17.2 (a) Taxes = 22,250 + 0.39(150,000 – 100,000) […]
978-0073376301 Chapter 16 Part 2
12 Spreadsheet solution (b) MACRS: sum d values for 3 years: 0.20 + 0.32 + 0.192 = 0.712 (71.2%) SL: sum the d values for 3 years: 0.05 + 0.1 + 0.1 = 0.25 (25%) SL depreciates much slower early […]
978-0073376301 Chapter 16 Part 1
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 16 Depreciation Methods 16.1 Depreciation increases the company’s after–tax cash flow, because depreciation reduces the 16.2 Book value is established on the basis of accepted […]
978-0073376301 Chapter 15
Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 15 Cost Estimation 15.1 Ranking most time to least time: detailed estimate, design 60-100% complete, partially designed, order of magnitude, scoping/feasibility. 15.2 Supplies: AOC Installation: FC […]
978-0073376301 Chapter 14
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 14 Effects of Inflation 14.1 (a) There is no difference. (b) Today’s dollars are inflated compared to dollars of 2 years ago. Therefore, in order […]
978-0073376301 Chapter 13
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 13 Breakeven and Payback Analysis 13.1 (a) 0 = -FC + (589 – 340)9000 13.2 (a) QBE = 800,000/(2950 – 2075) = 914 units per […]
978-0073376301 Chapter 12
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 12 Independent Projects With Budget Limitation 12.1 Bundle: a collection of independent projects 12.2 Two assumptions are: (1) The funds invested in every project will […]
978-0073376301 Chapter 11
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 11 Replacement and Retention Decisions 11.1 In taking a non-owner’s viewpoint, the analysis is done from the perspective of someone who does not own any […]
978-0073376301 Chapter 10
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 10 Project Financing and Non–economic Attributes 10.1 Risk – The higher the risk, the higher the MARR Investment Opportunity – MARR may be lowered for […]
978-0073376301 Chapter 9 Part 2
12 (b) Location E B = 500,000 – 30,000 – 50,000 = $420,000 C = 3,000,000 (0.12) = $360,000 Modified B/C = 420,000/360,000 = 1.17 Location E is justified. Incrementally compare W to E. W vs. E: ΔB = $200,000 […]
978-0073376301 Chapter 9 Part 1
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 9 Benefit/Cost Analysis and Public Sector Economics 9.1 Disbenefits are negative consequences that occur to the public and, therefore, are included 9.2 eBay – private; […]
978-0073376301 Chapter 8
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 8 Rate of Return Analysis: Multiple Alternatives 8.1 The rate of return on the incremental cash flow column represents the rate of return on the […]
978-0073376301 Chapter 7
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 7 Rate of Return Analysis: One Project 7.1 (a) The return would be -100%, if the entire initial investment were lost with no return. 7.2 […]
978-0073376301 Chapter 6
Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 6 Annual Worth Analysis 6.1 Multiply by (A/P,i%,n), where n is equal to the LCM or stated study period. 6.2 Three assumptions in the AW method […]
978-0073376301 Chapter 5
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 5 Present Worth Analysis 5.1 Mutually exclusive alternatives accomplish the same thing. Therefore, only one is to be 5.2 (a) The do-nothing alternative means that […]
978-0073376301 Chapter 4
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 4 Nominal and Effective Interest Rates 4.3 (a) six times (b) six times (c) two times 4.4 (a) one time (b) six times (c) 18 […]
978-0073376301 Chapter 3
1 Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 3 Combining Factors and Spreadsheet Functions 3.2 P = 260,000(P/A,10%,3) + 190,000(P/A,10%,2)(P/F,10%,3) = 260,000(2.4869) + 190,000(1.7355)(0.7513) = $894,331 3.3 (a) P = -120(P/F,12%,1) – 100(P/F,12%,2) […]
978-0073376301 Chapter 2
Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 2 Factors: How Time and Interest Affect Money 2.1 (1) (P/F, 6%, 8) = 0.6274 (2) (A/P, 10%,10) = 0.16275 (3) (A/G,15%,20) = 5.3651 (4) (A/F,2%,30) […]
978-0073376301 Chapter 1
Solutions to end–of–chapter problems Engineering Economy, 7th edition Leland Blank and Anthony Tarquin Chapter 1 Foundations of Engineering Economy 1.1 The four elements are cash flows, time of occurrence of cash flows, interest rates, and measure of economic worth. 1.2 […]
978-0072957167 Chapter 16
Solutions Manual for Digital Communications, 5th Edition (Chapter 16) 1 Prepared by Kostas Stamatiou March 12, 2008 1PROPRIETARY MATERIAL. c The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any […]
978-0072957167 Chapter 15 Part 2
13 10-9 10-7 10-6 10-5 10-4 10-3 10-2 10-1 100 0 5 10 15 20 Outage probability Average SNR (dB) Outage capacity is 2 bps/Hz (d) The following plots are of the “success probability” 1 −Pout vs. Cfor γ= 10,20dB, […]
978-0072957167 Chapter 15 Part 1
Solutions Manual for Digital Communications, 5th Edition (Chapter 15) 1 Prepared by Kostas Stamatiou March 12, 2008 1PROPRIETARY MATERIAL. c The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any […]
978-0072957167 Chapter 14
Solutions Manual for Digital Communications, 5th Edition (Chapter 14) 1 Prepared by Kostas Stamatiou March 9, 2008 1PROPRIETARY MATERIAL. c The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any […]
978-0072957167 Chapter 13
Solutions Manual for Digital Communications, 5th Edition (Chapter 13) 1 Prepared by Kostas Stamatiou January 20, 2008 1PROPRIETARY MATERIAL. c The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any […]
978-0072957167 Chapter 12
Solutions Manual for Digital Communications, 5th Edition (Chapter 12) 1 Prepared by Kostas Stamatiou January 29, 2008 1PROPRIETARY MATERIAL. c The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any […]