Problem 3.21
A bead
A
weighing
2lb
slides on a quarter-circular frictionless bar
BC
with
radius
r
. The bead is supported by a cable
AC
. For the value of
given below,
determine the force supported by cable AC .
General values of where 0ı< < 90ı.
Solution
The FBD for bead
A
is shown at the right. The reaction between
the bead and bar is constructed as follows. The bead may not move
perpendicular to the bar, therefore there is a reaction force
R
perpen-
dicular to the bar. The bead is free to move parallel to the frictionless
bar, therefore there is no reaction force in that direction. To determine
the orientation for
TAC
we consider the triangle shown below. The
hypotenuse hof this triangle is
h2D.r cos /2CŒr.1 sin /2(1)
Dr2cos2C12sin Csin2:(2)
Since cos2Csin2D1, Eq. (2) becomes
h2Dr22.1 sin /: (3)
Hence,
hDrp2.1 sin /: (4)
Summing forces in the xand ydirections provides
XFxD0W Rcos CTAC
rcos
rp2.1 sin / D0; (5)
XFyD0WRsin CTAC
r.1 sin /
rp2.1 sin / 2lb D0: (6)
Equation (5) provides
TAC DRp2.1 sin /: (7)
Substituting Eq. (7) into Eq. (6) provides