Archives: Solution Manual
978-1107135116 Chapter 4 Part 2
Initial value problems 231 For the third equation, let y3=xso we get d = […]
978-1107135116 Chapter 4 Part 1
Nonlinear equations 199 325 %this is a vapor 326 P = vdw(V,T,a,b); 327 else 328 %this is on the horizontal part 339 ylabel(‘$P$ (MPa)’,‘FontSize’,14) 340 top = strcat(‘Isotherm for $T = $’,num2str(T),‘K’); 341 title(top,‘FontSize’,14) 342 out = h; 343 344 […]
978-1107135116 Chapter 3 Part 4
Nonlinear equations 179 53 xlabel(‘$x$’,‘FontSize’,14) 54 ylabel(‘$y$’,‘FontSize’,14) 55 title(‘Solution to s13c6p3’,‘FontSize’,14) 56 saveas(g,‘s13c6p123 solution figure3.eps‘) 67 J(1,2) = -y; 68 J(2,1) = P; 69 J(2,2) = -(1-y); 70 out = J; The two output files are: 0 0.2 0.4 0.6 […]
978-1107135116 Chapter 3 Part 3
Nonlinear equations 159 65 fprintf(‘Temperature difference at inlet is … \t%8.6f\n’,T1-T1p) 66 fprintf(‘Temperature difference at outlet is … \t%8.6f\n\n’,T2-T2p) 74 fprintf(‘*********************************************\n’) 75 end 76 77 78 h = figure; 79 semilogx(wpscan,T2scan,‘-o’,‘MarkerSize’,8) 80 xlabel(‘$w$ (kg/s)’,‘FontSize’,14) 81 ylabel(‘$T 2$ ($ˆ{\circ}$C)’,‘FontSize’,14) 82 title(‘Solution […]
978-1107135116 Chapter 3 Part 2
Nonlinear equations 139 The initial guess x(0) = 0.2 0.2 converges to x(∗)= 1 0 […]
978-1107135116 Chapter 3 Part 1
Linear equations 105 5A = [6, 1; 4, -8]; 6b = [13;0]; 7x solve = A\b; 8 19 saveas(h,‘s12c4p2 solution figure1.eps’,‘psc2’) 20 21 %make the zoom figure 22 small = 0.001; 23 axis([x solve(1)-small,x solve(1)+small,x solve(2)-small,… 24 x solve(2)+small]) 25 […]
978-1107135116 Chapter 2 Part 2
Linear equations 85 004 x3 1 which gives x1 x2 = […]
978-1107135116 Chapter 2 Part 1
Linear equations 65 (2.8) Cofactor expansion for i=3 has the most zero entries, giving det A=(−1)(−1)(3+1) det 2 1 0 1 −3214 −7234 […]
978-1107135116 Chapter 1 Part 2
Introduction 25 15 for l = 1:n 16 A(k,l) = (k+l)/(k*l); 17 end 18 end 29 output 30 31 function out = transp(A,m,n) 32 %A = original matrix with m rows and n columns. create transpose 33 Atrans = zeros(n,m); […]
978-1107135116 Chapter 1 Part 1
Numerical methods with chemical engineering applications Solutions Manual Kevin D. Dorfman and Prodromos Daoutidis Contents List of illustrations page iv List of tables v 1 Introduction 1 2 Linear equations 43 3 Nonlinear equations 115 4 Initial value problems 208 […]
978-0815360827 Chapter 22
22 – 1 CHAPTER 22 ASPHALT EQUIPMENT 1. a. 𝑚𝑖𝑛.)(9𝑠𝑞.𝑓𝑡. 𝑠𝑞.𝑦𝑑.) (12 𝑓𝑡)(0.5 𝑔𝑎𝑙. 𝑠𝑞.𝑦𝑑.)=186 𝑓𝑡. 𝐷𝑖𝑠𝑡𝑟𝑖𝑏𝑢𝑡𝑜𝑟 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦=(186 𝑓𝑡. 𝑚𝑖𝑛.)(12 𝑓𝑡.)(0.5)=1,116 𝑠𝑞.𝑓𝑡. 𝑚𝑖𝑛. 𝑇𝑖𝑚𝑒= (5,280 𝑓𝑡.)(24 𝑓𝑡.) (1,116𝑠𝑞.𝑓𝑡. 𝑚𝑖𝑛.)(60𝑚𝑖𝑛. ℎ𝑟. )=𝟏.𝟗 𝒉𝒓. 𝑚𝑖𝑛. 1. b. 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐴𝑠𝑝ℎ𝑎𝑙𝑡= (5,280 𝑓𝑡.)(24 […]
978-0815360827 Chapter 20
CHAPTER 20 Concrete Equipment 1. a. 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐶𝑜𝑛𝑐𝑟𝑒𝑡𝑒= (370 𝑓𝑡.)(110 𝑓𝑡.)(10 𝑖𝑛𝑐ℎ𝑒𝑠) (12𝑖𝑛𝑐ℎ𝑒𝑠 𝑓𝑡.)(27𝑐𝑢.𝑓𝑡. 𝑐𝑢.𝑦𝑑.)=1,256 𝑐𝑢.𝑦𝑑. 𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦= (1,256 𝑐𝑢.𝑦𝑑.) (8 ℎ𝑟.)=157𝑐𝑢.𝑦𝑑. ℎ𝑟. Therefore, select the 171-cubic-yard-per-hour pump. 1. b. 𝑀𝑖𝑥𝑒𝑟 𝑇𝑟𝑢𝑐𝑘 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦= (8 𝑐𝑢.𝑦𝑑.)(50𝑚𝑖𝑛. (25 𝑚𝑖𝑛.)=16𝑐𝑢.𝑦𝑑. ℎ𝑟. 𝑁𝑢𝑚𝑏𝑒𝑟 […]
978-0815360827 Chapter 18
18 – 1 CHAPTER 18 Shaft Drilling and Pile Driving 1. 𝑇𝑖𝑚𝑒 = (48 𝑝𝑖𝑙𝑒𝑠)(60 𝑓𝑡. 𝑝𝑖𝑙𝑒) 2. a. 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦 = (120𝑓𝑡. (60𝑚𝑖𝑛. ℎ𝑟. )=48𝑓𝑡. ℎ𝑟. 𝑇𝑖𝑚𝑒 = (90 𝑝𝑖𝑙𝑒𝑠)(85 𝑓𝑡. 𝑝𝑖𝑙𝑒) (48𝑓𝑡. ℎ𝑟.)(8ℎ𝑟. 𝑑𝑎𝑦)=20 𝑑𝑎𝑦𝑠 ℎ𝑟.)(24𝑚𝑖𝑛. ℎ𝑟. ) 𝑆𝑒𝑡 […]
978-0815360827 Chapter 17
CHAPTER 17 Cranes 1. a. 𝑀𝑎𝑥𝑖𝑚𝑢𝑚 𝐿𝑜𝑎𝑑 @ 15 𝑓𝑒𝑒𝑡 = 30,700 𝑙𝑏.− 450 𝑙𝑏.= 𝟑𝟎,𝟐𝟓𝟎 𝒍𝒃. 1. b. 𝑀𝑎𝑥𝑖𝑚𝑢𝑚 𝐿𝑜𝑎𝑑 @ 35 𝑓𝑒𝑒𝑡 = 12,080 𝑙𝑏.− 350 𝑙𝑏.= 𝟏𝟏,𝟕𝟑𝟎 𝒍𝒃. 2. 𝑀𝑎𝑥𝑖𝑚𝑢𝑚 𝑂𝑝𝑒𝑟𝑎𝑡𝑖𝑛𝑔 𝑅𝑎𝑑𝑖𝑢𝑠 = √(60)2−(41)2= √1,919 = 𝟒𝟑 […]
978-0815360827 Chapter 16
16 – 1 CHAPTER 16 Lifting and Loading Equipment 1. a. Maximum Load @ 4 feet is 4,000 lb. 1. b. Maximum Load @ 16 feet is 2,500 lb. 2. a. Determine rated load from Figure 6.3. Maximum Load @ […]
978-0815360827 Chapter 15
15 – 1 CHAPTER 15 Soil Compactors 1. 𝐸𝑓𝑓𝑒𝑐𝑡𝑖𝑣𝑒 𝑊𝑖𝑑𝑡ℎ = 6.5 𝑓𝑡.− 0.7 𝑓𝑡.= 5.8 𝑓𝑡. 𝑓𝑡.)(27 𝑐𝑢.𝑓𝑡. 𝑐𝑢.𝑦𝑑.)(4 𝑝𝑎𝑠𝑠𝑒𝑠) =𝟓𝟔𝟕𝑪𝑪𝒀 2. 𝐸𝑓𝑓𝑒𝑐𝑡𝑖𝑣𝑒 𝑊𝑖𝑑𝑡ℎ = 7.2 𝑓𝑡.− 0.5 𝑓𝑡.= 6.7 𝑓𝑡. 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦 = (6.7 𝑓𝑡.)(3𝑚𝑖. ℎ𝑟.)(5,280 𝑓𝑡. 𝑚𝑖.)(6 𝑖𝑛.)(0.83) […]
978-0815360827 Chapter 14
CHAPTER 14 Soil Stabilizers 1. a. 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦=(26 𝑓𝑡. 𝑚𝑖𝑛.)(8 𝑓𝑡.)(12 𝑖𝑛.)(0.83)(60 𝑚𝑖𝑛. ℎ𝑟. ) 𝒉𝒓. (12𝑖𝑛. 𝑓𝑡.)(27𝑐𝑢.𝑓𝑡. 𝑐𝑢.𝑦𝑑.)=𝟑𝟖𝟑𝑩𝑪𝒀 1. b. 𝑉𝑜𝑙𝑢𝑚𝑒= (140 𝑓𝑡.)(400 𝑓𝑡.)(12 𝑖𝑛.) (12𝑖𝑛. 𝑓𝑡.)(27𝑐𝑢.𝑓𝑡. 𝑐𝑢.𝑦𝑑.)=2,074 𝐵𝐶𝑌 𝑇𝑖𝑚𝑒= 2,074 𝐵𝐶𝑌 (383𝐵𝐶𝑌 ℎ𝑟. )(8ℎ𝑟. 𝑑𝑎𝑦)=𝟎.𝟕 𝒅𝒂𝒚𝒔 2. a. 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦=(18 […]
978-0815360827 Chapter 13
CHAPTER 13 Graders 1. a. 𝐴𝑟𝑒𝑎 𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦=(3.3 𝑚𝑝ℎ)(10 𝑓𝑡.)(45 𝑚𝑖𝑛. 𝒉𝒓. ℎ𝑟. )(5,280 𝑓𝑡. 𝑚𝑖𝑙𝑒) (1 𝑝𝑎𝑠𝑠)(9 𝑠𝑞.𝑓𝑡. 𝑠𝑞.𝑦𝑑.)(60 𝑚𝑖𝑛. ℎ𝑟. )=𝟏𝟒,𝟓𝟐𝟎𝒔𝒒.𝒚𝒅. 1. b. 𝑇𝑖𝑚𝑒=(10 𝑓𝑡.)(10 𝑚𝑖.)(3 𝑝𝑎𝑠𝑠𝑒𝑠)(5,280 𝑓𝑡. 𝑚𝑖𝑙𝑒) (9 𝑠𝑞.𝑓𝑡. 𝑠𝑞.𝑦𝑑.)(14,520 𝑠𝑞.𝑦𝑑. ℎ𝑟. )=𝟏𝟐 𝒉𝒓. 2. 𝐶𝑦𝑐𝑙𝑒 𝑇𝑖𝑚𝑒= […]
978-0815360827 Chapter 12
12 – 1 CHAPTER 12 Trucks and Haulers 1. a. 𝐶𝐶𝐹)(27𝑐𝑢.𝑓𝑡. 𝑐𝑢.𝑦𝑑.)(0.85𝐶𝐶𝑌 𝐵𝐶𝑌) From Table 12.1: Turn and Dump Time = 1.3 min.; Spotting Time = 0.15 min 𝐹𝑖𝑥𝑒𝑑 𝑇𝑖𝑚𝑒 = 3 𝑚𝑖𝑛.+ 1.3 𝑚𝑖𝑛.+ 0.15 𝑚𝑖𝑛.= 4.45 𝑚𝑖𝑛. Resisting […]
978-0815360827 Chapter 10
10 – 1 CHAPTER 10 Excavators, Draglines, and Clamshells 1. Fill factor for front shovel for common earth is found in Table 10.1 to be 1.025 by taking the average for earth. 𝑚𝑖𝑛.)(60𝑚𝑖𝑛. ℎ𝑟. ) 2. a. Fill factor for […]
978-0815360827 Chapter 9
CHAPTER 9 Scrapers 1. 𝐿𝑜𝑎𝑑 𝑊𝑒𝑖𝑔ℎ𝑡=(17 𝐿𝐶𝑌)(2,600 𝑙𝑏. 𝐵𝐶𝑌) (1.25 𝐿𝐶𝑌 𝐵𝐶𝑌)=35,360 𝑙𝑏. 𝐿𝑜𝑎𝑑𝑒𝑑 𝑊𝑒𝑖𝑔ℎ𝑡=35,360 𝑙𝑏.+ 56,450 𝑙𝑏.=91,810 𝑙𝑏. 𝑀𝑎𝑥𝑖𝑚𝑢𝑚 𝑈𝑠𝑒𝑎𝑏𝑙𝑒 𝑅𝑖𝑚𝑝𝑢𝑙𝑙 (𝑒𝑚𝑝𝑡𝑦)=(0.6)(0.66)(56,450 𝑙𝑏.)= 22,354 𝑙𝑏. 𝑀𝑎𝑥𝑖𝑚𝑢𝑚 𝑈𝑠𝑒𝑎𝑏𝑙𝑒 𝑅𝑖𝑚𝑝𝑢𝑙𝑙 (𝑙𝑜𝑎𝑑𝑒𝑑)=(0.6)(0.51)(91,810 𝑙𝑏.)= 28,093 𝑙𝑏. Resisting Force (loaded) = [(55 𝑙𝑏. 𝑡𝑜𝑛)(45.9 […]
978-0815360827 Chapter 6
CHAPTER 6 Fundamentals of Earthmoving 1. A contractor is planning to use a Caterpillar D6R tracked dozer with angle blade to clear and grub a construction site. The ground conditions are very muddy with an estimated rolling resistance of 250 […]
978-0815360827 Chapter 5
5 – 1 CHAPTER 5 Fundamentals of Soils 1. A contractor is excavating fill material from a borrow site to be used to construct a compacted fill foundation for a parking garage. She has determined that 5,000 compacted cubic yards […]
978-0815360827 Chapter 4
CHAPTER 4 Ownership and Operating Costs 1. A tracked dozer is used about 1,500 hours per year. It cost $500,000 new and has a useful life of 15,000 hours. Estimated salvage value after 15,000 hours of use is $95,000. Minimum […]
978-0815360827 Chapter 3
3 – 1 CHAPTER 3 Depreciation Accounting Techniques 1. A contractor purchased a tractor for $180,000 and anticipates using it for nine years. The salvage value of the tractor at the end of the nine years is estimated to be […]
978-0815360827 Chapter 2
2 – 1 CHAPTER 2 Time Value of Money 1. A contractor borrowed $250,000 from a bank at an interest rate of 6% to purchase new construction equipment. What annual payment must the contractor make if the loan is to […]
978-0534948849 Chapter 23
978-0534948849 Chapter 22
978-0534948849 Chapter 21
978-0534948849 Chapter 20
978-0534948849 Chapter 19 Part 2
978-0534948849 Chapter 19 Part 1
978-0534948849 Chapter 18 Part 2
978-0534948849 Chapter 18 Part 1
978-0534948849 Chapter 17 Part 3
978-0534948849 Chapter 17 Part 2
978-0534948849 Chapter 17 Part 1
978-0534948849 Chapter 16 Part 3
978-0534948849 Chapter 16 Part 2
978-0534948849 Chapter 16 Part 1
978-0534948849 Chapter 15 Part 7
978-0534948849 Chapter 15 Part 6
978-0534948849 Chapter 15 Part 5
978-0534948849 Chapter 15 Part 4
978-0534948849 Chapter 15 Part 3
978-0534948849 Chapter 15 Part 2
978-0534948849 Chapter 15 Part 1
978-0534948849 Chapter 14
978-0534948849 Chapter 13 Part 2
