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Mechanical Engineering Chapter 1 Homework Water Has Density 194 Slug ft What The
1 2 *1–12. Evaluate each of the following to three significant figures and express each answer in SI units using an appropriate prefix: (a) (b) (c) (2.68 mm)(426 Mg). 128 ms210.0458 Mm2>1348 mg2,1684 mm2>143 ms2, SOLUTION a) Ans. b) Ans. […]
Mechanical Engineering Chapter 10 Homework Determine the moment of inertia for the shaded
1010 Ans: Ix= ab3 3(3n + 1) SOLUTION Differential Element. Here x= a b 1 n to the x axis shown shaded in Fig. a is dA =(a–x)dy = a a–a b 1 n y 1 n b d y […]
Mechanical Engineering Chapter 10 Homework Differential Disk Element The Mass Rdv Rpy2
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Mechanical Engineering Chapter 10 Homework No portion of this material may be reproduced
1070 10–61. Determine the product of inertia of the shaded area with respect to the x and y axes. SOLUTION Differential Element: Here, x=2y 1 2. The area of the differential element parallel to the x axis is dA =xdy=2y […]
Mechanical Engineering Chapter 10 Homework The area of the differential element
1030 10–21. Determine the moment of inertia for the shaded area about the x axis. SOLUTION Differential Element. Here x2=y and x1= 1 2 y2. The area of the differential element parallel to the x axis shown shaded in Fig. […]
Mechanical Engineering Chapter 10 Homework The moment of inertia about the y axis for each
1050 SOLUTION Moment of Inertia. The moment of inertia about the y axis for each segment can be determined using the parallel-axis theorem, I y= I y′ +Ad x 2. Referring to Fig. a, Segment A i (in 2 ) […]
Mechanical Engineering Chapter 11 Homework Pearson Education Inc Upper Saddle River Nj
1143 *11–20. The crankshaft is subjected to a torque of Determine the horizontal compressive force Fapplied to the piston for equilibrium when u=60°. M=50 N #m. SOLUTION For Ans. Ans.F=512 N (–50 +0.09769F)du =0 dx=-0.09769 du u=60°, x=0.4405 m dU=0; […]
Mechanical Engineering Chapter 11 Homework The Datum Established Through
1159 *11–36. Determine the angle for equilibrium and investigate the stability at this position. The bars each have a mass of 3 kg and the suspended block Dhas a mass of 7 kg. Cord DC has a total length of […]
Mechanical Engineering Chapter 11 Homework When All The Weights Undergo Positive Virtual
1123 11–1. SOLUTION Free Body Diagram: The tension in cable AC can be determined by releasing cable AC .The system has only one degree of freedom defined by the independent coordinate .When undergoes a positive displacement ,only FAC and the […]
Mechanical Engineering Chapter 3 Homework Fad Equations Equilibrium Equilibrium Requires Fab
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Mechanical Engineering Chapter 3 Homework Tab Lb Referring The Fbd Shown Fig
161 3–1. SOLUTION Solving: Ans. Ans.F1=1.83 kN F2=9.60 kN 0.3420F2–0.8660F1=1.7 +c©Fy=0; F2cos 70° +5 sin 30° –F1sin 60° –3 5(7) =0 0.9397F2+0.5F1=9.930 : +©Fx=0; F2sin 70° +F1cos 60° –5 cos 30° –4 5(7) =0 F1 7 kN 4 The members […]
Mechanical Engineering Chapter 6 Homework A man having a weight of 175 lb attempts
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Mechanical Engineering Chapter 6 Homework Determine the force in members EF, BE, BC and BF
521 6–33. SOLUTION a a Ans. a Ans. Joint C: Ans.+c©Fy=0; FGC =0 FCD =6.67 kN (T) +©MG=0; 9.5(4) –2(4) –5(2) –FCD(3) =0 FGF =12.5 kN (C) +©MD=0; –4 5FGF (1.5) –2(2) +9.5(2) =0 +©MA=0; Ey(8) –2(8) –5(6) –5(4) –5(2) […]
Mechanical Engineering Chapter 6 Homework Fig And Equations Equilibrium First Consider The
561 6–69. Determine the reactions at supports Aand B. SOLUTION Member DB: a Ans. Ans. By=1.05 kip +c©Fy=0; By–3.15 +3.50a3 5b=0 Member AC: Ans. +c©Fy=0; Ay–3–3.50 a3 5b=0 Ax=2.80 kip Ans. a Ans.M A= 43.2 kip # ft +©MA=0; MA–3(6) […]
Mechanical Engineering Chapter 6 Homework Start at joint C and then proceed to join D
481 SOLUTION Method of Joints. Start at joint C and then proceed to join D. Joint C. Fig. a S + ΣF x= 0; FCB =0 Ans. + c Σ Fy=0; FCD –20 =0 FCD =20.0 kN (C) Ans. Joint […]
Mechanical Engineering Chapter 6 Homework The elongation of the spring is
596 *6–104. The hydraulic crane is used to lift the 1400-lb load. Determine the force in the hydraulic cylinder AB and the force in links AC and AD when the load is held in the position shown. 8 ft 30 […]
Mechanical Engineering Chapter 6 Homework The truss is supported by short links at A, B, D
541 6–53. The space truss supports a force . Determine the force in each member, and state if the members are in tension or compression. 400k 6 lb F=5–500i+600j+ A B C D x y z F 8ft 6ft 6ft […]
Mechanical Engineering Chapter 7 Homework Determine the internal normal force, shear force, and moment
631 Ans: NE=720 N VE=1.12 kN ME=–320 N #m NF=0 VF=–1.24 kN MF=–1.41 kN #m SOLUTION Support Reactions. Referring to the FBD of member BC shown in Fig. a, a +ΣMB=0; Cy(3) –1200 a4 5b (2) =0 C y =640 […]
Mechanical Engineering Chapter 7 Homework Education Inc Upper Saddle River Nj All
691 SOLUTION Support Reactions. Referring to the FBD of the shaft shown in Fig. a, a +ΣMA=0; NB(1) +300(0.5) –1200(1)(0.5) –600(1.5) =0 NB=1350 N a +ΣMB=0; 1200(1)(0.5) +300(1.5) –600(0.5) –A y (1) =0 A y =750 N S + ΣFx=0; […]
Mechanical Engineering Chapter 7 Homework No portion of this material may be reproduced
651 7–41. Determine the x, y, zcomponents of force and moment at point Cin the pipe assembly. Neglect the weight of the pipe. dna ekaT F 2 =5–300j+150k6lb.F 1 =5350i–400j6lb F 2 2ft 1.5fty z x C B 3ft F […]
Mechanical Engineering Chapter 7 Homework Referring to the FBD of the simply supported beam shown
671 For [FBD (e)], Ans. a Ans. M=w 18 127Lx –20L 2 –9x 2 2 M+wxax 2b–7wL 18 x–10wL 91x–L2=0+©M=0; V=w 213L–2×2 For [FBD (f)], Ans. a7wL 18 3L–x–w3L–x3L–x 2–M=0+©M=0; V=w 18 147L–18×2 V+7wL 18 –w13L–x2=0+c©F y =0; 2 2 […]
Mechanical Engineering Chapter 7 Homework Rod AB is fixed to a smooth collar D
611 7–1. Determine the shear force and moment at points Cand D. SOLUTION Support Reactions: FBD (a). a Internal Forces: Applying the equations of equilibrium to segment AC [FBD (b)], we have Ans. Ans. a Ans. Applying the equations of […]
Mechanical Engineering Chapter 8 Homework If the cow exerts a force of 250 lb on the rope
828 *8–80. If the required clamping force at the board A is to be 2 kN, determine the torque M that must be applied to the screw to tighten it down. The square-threaded screw has a mean radius of 10 […]
Mechanical Engineering Chapter 8 Homework If the loaded bin has a weight of 8500 lband center
748 8–1. Determine the maximum force P the connection can support so that no slipping occurs between the plates.There are four bolts used for the connection and each is tightened so that it is subjected to a tension of 4 […]
Mechanical Engineering Chapter 8 Homework It is required that the wheel is on the verge to rotate thus
768 8–21. A man attempts to support a stack of books horizontally by applying a compressive force of to the ends of the stack with his hands. If each book has a mass of 0.95 kg, determine the greatest number […]
Mechanical Engineering Chapter 8 Homework Neglect Rolling Resistance The Wheels The Surface
864 8–118. The pivot bearing is subjected to a parabolic pressure distribution at its surface of contact. If the coefficient of static friction is ,determine the torque Mrequired to overcome friction and turn the shaft if it supports an axial […]
Mechanical Engineering Chapter 8 Homework The coefficient of static friction between the belt
848 8–102. 50 mm 20 mm A B C D 50 mm 45° 30° M= 0.8 N⋅m The belt on the portable dryer wraps around the drum D, idler pulley A, and motor pulley B. If the motor can develop […]
Mechanical Engineering Chapter 9 Homework Also, find the tension in each of the cords used to support
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Mechanical Engineering Chapter 9 Homework Determine The Total Mass The Wheel Mggtm3
979 9–101. The water-supply tank has a hemispherical bottom and cylindrical sides. Determine the weight of water in the tank when it is filled to the top at C.Take gw=62.4 lb>ft3. SOLUTION Ans.W=gV=62.411357.172=84.7 kip V=1357.17 ft3 V=©urA =2pe3182162+4162 3pa1 4b1p21622f […]
Mechanical Engineering Chapter 9 Homework Pearson Education Inc Upper Saddle River
939 9–61. Determine the location y of the centroid C of the beam having the cross-sectional area shown. SOLUTION Centroid. The locations of the centroids measuring from the x axis for segments 1, 2 and 3 are indicated in Fig. […]
Mechanical Engineering Chapter 9 Homework The volume of the thin disk differential element is
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Mechanical Engineering Chapter 9 Homework The car rests on four scales and in this position
959 9–81. SOLUTION Ans.z=©zm ©m=9.51425(10–3) 77.7706(10–3) =0.122 m =122 mm =77.7706(10–3)Mg ©m= A 2 3 B p(0.160)3(7.80) +p(0.2)(0.08)2(2.70) =9.51425(10–3)Mg#m ©zm= C 0.160 –3 8(0.160) DA 2 3 B p(0.160)3(7.80) + A 0.160 +0.2 2 B p(0.2)(0.08)2(2.70) y x The assembly […]