Bioprocess Engineering: Basic Concepts 3rd Edition

ISBN 13
978-0137062706
ISBN 10
0137062702
Authors
Fikret Kargi, Matthew DeLisa, Michael L. Shuler
has exam prep Exam Prep  has homework help Homework Help
12 documents found.
573850
Homework Help
978-0137062706 Chapter 10
68 Chapter 10 Problem 10.1 C* = 7.3 mg/l Plot DO versus t: Determination of OUR: * LL L 2 dC k a (C C ) qo X dt = with air off: kLa (C*CL) = O L2 dC qo X dt = Integrating: O Ct L2 CO O2 dC qo X dt C C qo X
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 11
85 85 85 Chapter 11 Problem 11.l. a. For simplicity, neglect cell size distribution and cake resistance considerations. Assume the following relationship applies to tubular centrifuge: ( ) ( ) ( ) ( ) 2 2 Recovery % at Condition 1 Rotational speedat Condition 1 Recovery % at Condition 2 Rotational speedat Condition 2 =
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 12
92 92 92 Chapter 12 Problem 12.11 0 S 0.05 S 2g L== Glucose balance over differential height dZ yields. 0QdS kXS dV kXSA d Z = = Integration yields 0kXAdS dZSQ=( )( )0SHS00nH0nHHkXASL H kXSQ2L 1 540 30.6d 14.4h.5= = = = =
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 13
93 93 93 Chapter 13 Problem 13.1. Use eq. 9.72 to see if S > 0 at r = 0 Need rm for the bead: Mass of cells/bead = Vol. 0.25 cell 0.1 = 4/3 (0.2 cm)3 0.25 1.05g/cm3 0.1 = 0.88 mg dry wt/bead
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 14
96 96 96 Chapter 14 Problem. 14.1 What is P for a single cell or homogeneous population with the equivalent of 50 monomer plasmids at division if multimerization results in 40% of plasmid DNA as dimers and 16% as tetramers? # dimers = 0.40 50 = 20
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 15
104 104 104 Chapter 15 Problem 15.1. This derivation is very similar to the one in the text with free virus. The only eqn that changes is (15.4) which for pre bound virus is s e s dV / dt k V= For initial conditions s so VV= ; i V 0;= ene
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 16
106 106 106 Chapter 16 Problem 16.1. Data SO = 5 g glucose/l XO(g dw/l Y (g dw/g glu) m(hr1) Ks (g/l) Kd (hr1) E.coli (EC) 0.03 0.5 1.0 0.01 0.05 A.vinelandii (AV) 0.15 0.35 0.5 0.02 0.10 SO = 5 g glucose/l XO(g dw/l Y (g
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 3
1 1 1 Chapter 3 Problem 3.1 ( ) ( ) 3 15 24 k kk 2 1 kk 52 S E ES (ES) P E rate ESk + + = a.) Equilibrium approach * r values are the same as k values all are rate constants ( )( ) ( ) 12 1 r S E r ES=
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 6 Part 1
20 Chapter 6 Problem 6.1. Volume of a single cell: Vc = (3.14/4) (1))2 (2) = 1.57 um3/cell = 1.57 x10-12 cm3/cell Mass of a single cell: mc = 1.05 g/cm3 x 1.57 x10-12 cm3/cell = 1.65 x 10-12 g/cell Dry weight of a single cell: mc,dw
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 6 Part 2
32 32 32 S m D K1 SD 1 + = + a. p X S 0mDP q X Y D S D1 (D )1= = + + + SSmX S 0 X S 2mmSSX S 0 X S 02mDKKd11(DP) Y S Y DDdD 1 D11DDKK1 (1 )1Y S Y D SDD (D )1 +
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 7
43 43 43 Chapter 7 Problem 7.1. Total nitrogen in cells =(Nitrogen content of cells)(Final cell concentration)(Culture volume)=(0.12 g nitrogen/g cells) (30 g cell/liter) (1000 liters) = 3.6 kg nitrogen. MW of (NH4)2SO4 = 132; Nitrogen part is 28. Amount of (NH4)2SO4 needed =3.6 kg nitrogen (132
Bioprocess Engineering: Basic Concepts 3rd Edition
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Homework Help
978-0137062706 Chapter 9
51 51 51 Chapter 9 Problem 9.1 V 1000 l= S K 1.5 g/l= 0 S 10 g/l= 1 m0.4 h = X/S Y 0.5 g/g= F 100 l/h= a) 1 F 100 l/h D 0.1h V 1000 l = = = At steady state: 1m S S D 0.1h KS = = = + 11 S 0.1h 0.4 h 1.5 g/l S =
Bioprocess Engineering: Basic Concepts 3rd Edition

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