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978-0073529363 Chapter 1
Solutions Manual to accomparry Heat Transfer tenth edition J. P. Holman southern Methodist tJniversity Chapter I 1-1 LT- (39oox9-022 = 625oc (0.2×0.6) l-2 1-3 ,^cll fuc q – _l…?1._ – drc nrT r-ax+b; x=0; r-0.0375 dT dT – -kw’ x-0.3, […]
978-0073529363 Chapter 10 Part 1
Chapter 10 10-1 Pipe nearly constant temperature Tn =82oC L = 30oC € = 0.g h — |s2(12 -3o)t’o = 7.27 L tG.2 q = mrcrLTn = (2)(4180X90 – 60) = 2.508 x 105 W ^4 40- 50 Lr^=;eI=44.81oC q=UALTn […]
978-0073529363 Chapter 10 Part 2
Chapter l0 10-65 ho =0.8 kg/sec To, =30″C Toz =’loc Tr, =3oC U = 55 + h* =0.75 kg/se c Co= (0.8X1005) = 804 m’ .oc s) = 1.67 5 air flow by i \TO .919– LT’=26″C – 1.7 A […]
978-0073529363 Chapter 11
Chapter 11 11-l 1t-3 T* =25oC u- = 1.5 m/sec .b= 30 cm h-*to.urlt)Re LttzPrtt3 hD= E [:rlt” L’ ‘ L’J “Ir pfcp[6r) Ig)’ t6r,/ ‘[ofJ -l’098 Prl/3-0-884 OF Tw OC hfr xl0{ cw Tf OK v xl0{ kcp Pr […]
978-0073529363 Chapter 12
Chapter 12 l2-l Air@300K k-0.a262 Vertical plate GrPr – 104 ; Nu : trllk : 54.2( TL)t t4 Fig l2-8 CrrPr – 104 Nu :6 : lOe Nu:100 l2-2, Openended problem r2-3 d : 15 mm T. : 800 K […]
978-0073529363 Chapter 2 Part 1
2-l -To Chapter 2 2-2 Assume Linear variation: k = he+ pf1 := #1, *,r, -frlq_- r, :”!,:’ ^T^:J= – – 11 + -,r| Q_=95oC, 4=62″C, Tt=35″C, Ar=ti.OiS ‘ ,b, – zs + f<oz2- rrr,] = [n, – 35 + […]
978-0073529363 Chapter 2 Part 2
Chapter 2 2_55 ri = 0.0125 m ro = 0.0129 m Assume inner surface is insulated dr__Qr+gt_oatr=n drzkrn ^ _ qr;2 q=t (a) 2_56 k=43 W m .oC Ur= = I s’o – -e’,,-“‘-.’.8f#(#) 2xro-3 + 4.3rx to-s +71.84x l0-3 […]
978-0073529363 Chapter 2 Part 3
Chapter 2 2-98 =386 t = s = (0.95X55 Xt 2-99 t =2 cm L=17 cm k = 43 h=23 lc = 18 cm / , 11/2 L,t”l+l =0.e3 4r =o.il ” \kil) q = (0.64X2X23X0.18)(230 – 25) = 1sg6 […]
978-0073529363 Chapter 3 Part 1
3.l Chapter 3 or cg = 0 If ca – 0 then have trivial soln. then, c5*c6=0andc5=-c6 0=0 at x=W 0 – (trr-Aw + ,6rlwxcs sin(,try)l .’. either c5 * c6 = 0 .’. x = 0 but it was […]
978-0073529363 Chapter 3 Part 2
Chapter S The Solution: AB ITI: 253.5476 2T2= 249.9672 3-6t * = 0.5498 + = 0.05o27 qr = (soxro6;210.0 t)2(o.oz) = 3.142 Ktz &– sr1 Li= Q)Q.s4eS) + 0.05027 =r.r4ee I ^r* = 140)[a(0.0t)2 + zr(0.01X0.0 2)] = O.0377 The […]
978-0073529363 Chapter 4 Part 1
Chapter 4 +l T*=Tm+ A*sinon Ksinrorl L2 a=l.8xl0-6 ^zft”” 2L=2.5cm 4 =150.C 4 =30oC r=l min =60 sec’Dc -./c . \2 2L=t,lil ar =r.7o5 lstfournonzeroterms n=1, 3, 5, 7 #= 11o.tsts – 7.22x l0-8 + 6.15 x 10281 = 0.231 […]
978-0073529363 Chapter 4 Part 2
Chapter 4 The Solution The EquationS ABcD ITI: <70t( I qc I Ft000f(c2-c I ))f$c$9/4485+C I LI, 2T1t: { 8000.(C I -C2 )+t000f (C3 -C2)) r$CI9/99 7 G+C2 3T3: {8000.(C2-C3F I 60f (C4-Ca ))$C$9/9jt5+C3 4TF { I 60r(${4)+ I 5sr1C5{+1;r3c$9/ […]
978-0073529363 Chapter 4 Part 3
Chapter 4 The Solution 4-101 cr – 412.5 C2 – 412.5 C3 = 825 C4 = 825 cb – 412.5 C6 = 412.5 Node I 2 3 4 5 6 A”**. 23.23 23.23 24.26 24.26 24.26 24.26 The Equations ABc […]
978-0073529363 Chapter 5 Part 1
Chapter 5 5-3 6 4.64x ,’ r1/2 Q-J =4.64xrt21 P I {Rr, \u*p ) 3u*yxllz ,*yt *t” u_ M L J -L \u*Pl du 3u*x-ly , 3tt**-tyt ar=- 46 *7 a, _ 2.32u,=[1[z)r _1(z)ol v-flil.dJ -8t.alJ at x- 6in-15.24 cm […]
978-0073529363 Chapter 5 Part 2
Chapter 5 5-60 T.-50+136=93oe=366K ‘f 45 xl03 p- = 0.0592 kel ^3 (2078X366) v – (18.53 x 10-uxt0) = 18.53 x l0-5 k – 0.63 It = 230.5 x l0-7 k – 0. I 69l Pr – 0.7 | Re […]
978-0073529363 Chapter 6 Part 1
k -,0.135 Chapter 6 L d – 40 at 120’C pr – 175 p = (0.1 24 xl0-4xs2g) \r/3 ;)= 784 6-r For L- 20 cm c p = 2’307 I st iteration lrt h-9-g(1.86) (rls,ooo)r/ t( -r ‘ u […]
978-0073529363 Chapter 6 Part 2
Chapter 6 6-54 r, =65!20 =425oc= 315.5 K ‘2 1.0132 x lOs An: p=–*=l.ll9 F=2.ol}xl0-5 k=0.0274 ‘ (287X315.5) t O ^i?’ At 90″C Pr = 1.978 Eq. (6-17) pu – 6’p”n pyl/3 prl/3 – 1.255 Eq. (6-18) lriu = (0.35 […]
978-0073529363 Chapter 6 Part 3
Chapter 6 6_8E Properties at20″C v = 0.0009 m2/s Pr = 10,400 k=o.r45 + p = 888 xgl^t cp = t88o + ‘- m.oc r — –et — tt kg.oc 6-89 ropert tes : 0-6 ^2 I, .23 =Q :1( […]
978-0073529363 Chapter 7 Part 1
Chapter 7 7-3 Show that P= I fo, an ideal gas. .T 74 Tf=4O”C=313K P=1.128 L=0.3048m F=l.9o6x l0-s Pr = 0.905 p =1.13 k =0.027 f = 0.00319 Gr d; = q0.393n-l/2(0.952+prlrta Gr-l/41= 0.014 m vl4 u=ttnax u, .6=t= Uur=0.722 […]
978-0073529363 Chapter 7 Part 2
Chapter 7 , 7-56 Tf =ry =32.5oc=305.5 K J2 Pr – 0.7 | = l6.ZSx 10-6 k – 0.0267 – I 5X4)3(0.7) Pr – 0.697 Grpr = Xo.o7t3 (0.697) (2’075x t0{ )2- h=ry3 0.07i(0. l5Xl .glx 108 )rt3 = 34.5g […]
978-0073529363 Chapter 7 Part 3
Chap|€ir 7 7_99 Tf = 35O K v = 20.76x l0{ /c = 0.03003 pr = 0.7 4.=0.04 ro=0.05 6=0.01 Gr5 pr – (s’s)(#)l+00 – :00×0’01)3(0’7) (20’76* ro 6F— = 4548 lt = p.zzt)(4548)o.226 = 1.53 k ft” = (0.03003X1.53) […]
978-0073529363 Chapter 8 Part 1
8-1 (a) T – 800’C = 1073 K br = (aXIAn)= 4292 Chapter I L{ =(0.2X1073) – 214.6 Euo-h, = oEUo-f, = 0.53131 E6 – (5.66,0 x to-811t otl)a = 7.515 x lOa w I ^’ 4trans = (0.53131X0.9X7.515 x […]
978-0073529363 Chapter 8 Part 2
Chapter I 8-45 (5.669 x lo-8xgzg)4(+.,g” tOa \ -26OoC = 533 K t3 = 1.0 Fn: o-96 €2 = 0.5 A2-A3=n(1.25)z Ar = n(2,5)(7.5) : 58.9 ,*2 =4.91 cm2 4z= q3 = +Fzt:(0.9 q( +*)=0.08 ,^r ‘ ‘\58.9) – 13,456 […]
978-0073529363 Chapter 8 Part 3
Chapter I Outer Surface: coolins _ 91,051- (}f<0l _ r.238 +e3.55)rc(0.6×1323 _643)__98,124 Wlm 8-E1 Eur=37,194 Eh=14,513 9=g.tSZ | +=0.3142 LL + =e.548 +=2.122 f- =42.44 etAt ez\, 4ryses – -” 8-82 Assume large number of pins so that array behaves […]
978-0073529363 Chapter 8 Part 4
Chapter I C) t^tl 8-130 zv * 150 Tf= = 85oQ = 358 K Pr-0.7 Re= (25X0.5) 21.58 x 10-6 r/ = 2I 58 x 10-6 – 5 .7g2x 105 k – 0.030b Nu4 = 0., * (0.62’t(s.tg LmL’.t. ,er”oooJ […]
978-0073529363 Chapter 9
Chapter 9 9-1 {4- \r/3 \kr”prF) = o’oo77Re ro’o ( ,, )r/r’8 [ortp,” ) i* _ (0.00 77fr o’6 fit 3 k rzt zlaee – Tw)ft3 @ y2 ils t e N.U d3 = l4PrkL(r, -r)1t’ o ‘1″ – L […]