Chapter
5
5-3
6 4.64x ,’ r1/2
Q-J =4.64xrt21
P I
{Rr, \u*p )
3u”. u* (y )’
u-;-;[61
(;z
rr 3.47
x
A3:
*=; *-#-0
Chapter
5
5-4
P)
t-5
L=4 o
-r-r, =1v-t[r)’
u@ 6 e* T*-7. 2
6, Zld,
lr+
Chapter
5
5oC
= 27
8oK Air
1.5
m/sec
6d6_6l-,
d* 62_l2lr*
Pu”. Pu*
I (z+p
*(z
+* 6u
6rl
–
x
Eu{.a ‘ dx pu* )
4*(2#+(=X (#=i*G3t
*c\.*G\
=#*
fta63
=:i*cx
c=0 atx=x0 c–f 1*ot,o
(-6,–{E
gl
,-(
s)3/4l}”‘
d_
(tr*)t” _3.47x
I pu””
) JR.,
L_3 k _lt${ Prl/3
ro-r8-r 3{t.
tffr-(,r
)l
h
x=
o 3 r,
:.F- PrLt
3[t
– (?)”
o]-”’
5-6
p
– 2xloa N/*2
6
– L25
cm
=
0.0L25 m
T_
L
u-
Lttf
Chapter
5
t7
Oz
at?
atm
– 0.702
20.8
x 10-6
v-: )k
– 0.0307
Tf=250K
u-+ +02
-voz)
2tt dt
at
)=0 il=ua
/ ) \
u
=lt-41
uo (.- yo’
)
q=+#(-vo2)
21t
dx-
1,5
b
Chapter
5
AT
ay
q=
x2
,,
6t
5-9
L =
I-\ =+ ot=r^=const
0* r*\:4 u=u*=l
5-11
azu t( du dz\
8= tfa”*’ar)
#
=
+(“#.
#
*..#.
#
#)
:1″#.
#(#. #)
..#l
,=v=o
at
y-6 #-#=o #=o at
y=o
e
c (+*..’1t”
=z(
9,]t”
ot
=[;,,
\,”.J
h- k
-L( u’lr/2
q 2\m)
Nu_
3
a=*fg)t, -L(
w)t/2
‘! k 2\m) 2\ a, )
Nu”
=rffr,)”’ =:Ge
Prftz
-00
6t
lat x=
4m
=-
I
lat
ux,
v
Q= Pr
t51
Chapter
S
5-13
6, I
-:
6 l.o26Pru3
5-14
T*
– l5oc u@
– 3 m/s )(
=5 cm p -1 .13 x
l0-3 kg
Jo
5-15
I’E
Chapter
5
5-16
Tf= 75+20
– = 4’7.5oC
– 320.5
K
2p
– l.g4x
lO-s
_ Zx
lOa
– 0.029
0-3
5-17
d-7.5mm:o.oo75m p=looo lt-1.5xI
x-
ery”(+\’
=
9?ool9=?fooo’s)2
-26r
m
tt \+.0+
) 1.5
x
to-3
t 4.64
)
5-1.8
90+30
– 333
kg
m.sec
q
– (3
1.5X0.
q2(90
– 30)
=
681.3
w
l5?
Chapter
S
5-19
p = 7 kf./rnt
5*.21
N2
at2atm
v- k
– 0.03335
T*=35oC L-0.3m u@=7.5m/sec
2
25.74x
10-6
Tf=4ooK
{0o
Chapbr
5
*23
L=0.2 L=35oC p=14,000N/r’ Tn=250oC
u*=6m/sec
QsO-
*24
T,
=
55oC T*
=ZO’C p
=2O,W n/*2 x
=
0.3 m
t=0.332Rer-tt2 at x=15cm Re,
lul
5-26
Tr: oC
: 315
K
5-27
– (0.287)t0.38l(l0u)t
2
– rczs6/1061
t,ut
Chapter
5
5-28
5-29
‘.., 55
+ )7
IF= H’
-4loc-314K v-!7.g4x10-6
r2
k
– a.a273
– A.7
5-30
lL\
Chapter 5
5-31
50+to
s-32
Tr
=looi1o
=
55oc
– 3zBK p-# x
los – 0.538
7)(328)
– 0.7
f2(2)(28
107
v
u- -107v
L
122.2
xl0-6
Ir*
5-36
Chapbr 5
5-34
Z=1.0m Rer=1g7
13,
s-35
tLr
Chapter 5
s-37
u*=20 mls Airat I atm T*=27oC Tw=127″C
L=34 cm
square
L) =
5-38
,r-rL3!73=93oc=366K ,-173’6xloa fr=0.1691
w
123m.oC
s-39
? =350r v=20.76×10{ k=0.03003 Pr=0.697
trL
Chapter
5
5-40
il-=l50ny’sec Tr=l50oc l=lm T*=20″C
=2.11
5-42
hx – cx-ll5
t
5
5-43
,7, 80 +
‘I’r =
J2
Pr
= 4.81 Max
p – 990
It-6xlo-4 k-0.64
-3.3xlos
(ct
Chapter
5
5-44
5-45
d 3ry9 =
400
K v
=2O2.9x
10-6 ft
=
0.17g pr
=O.72,f =_ z
5_46
u- =
10 mi/h
=
4.47 mls T* = 27oC 4 = 347
W
l^2
Alsun
L=6.1m k=0.O262 Pr=0.71 F=1.98×10-5 p=I.177
us
Chapbr
5
5-47
L = 4O0oC Tw
= 42OoF ,t = I ft/sec
= 0.3(Xg ny’sec
5-48
,, -t’!^” =57oc=325K v=lg.23xl0{ /c=0.02g1
5-49
’11.—=287K v=l4.5lxl0{ k=O.O2S2 pr=0.71
5-50
at300K y=15.69×10{
tq
ChaPter
5
5-51
n
—
fr, AlTn
– T*\= (65.08X0’6)(0′
3X400
5-52
f : 303
K; v: 128×106;
u€: 15
28x1O1/15
: 2’r3
m
6 Q.l3X5)/(250000)t”
m
5-53
– 318
K; k
– 0’155; Pr: 0’7
q
=
(2r.45)(2’13X60
– 30)
14o
5-54
Tf 25
+ 150
= ‘ —
87.5oc
=
360.5
K
p=2.119×10-5 ft=0.0308
– 0.693 o’29–1 933
t
g/*’
p=@-‘
q
– nllr* -Tn) =
(238.6X0
‘5)2(150
-25)
=7424
W
5-55
T* =20″C
20 + 100 /’.o^ – 2-r.2 rr
Tr=+=60oC-333K
n=fr.A1T*-
L) =1s2.+71t12000
f-1 t
Chapter
5
5-56
t=300f F=1.8462xt0-s k-0.02624 h=0.71
5-57
Tf
=35OK F=l9.9lxl0{ k=O.O29g pr=0.7
(0.4s1X1.2)0-00)
5-58
15
+
139
\=-f=7’loC=350K F:9.954×10-6 k=0.2O6
(3xl:o=1I19:)
5-59
‘, =Y= 30oc v
=
0.349x
10-6 k
=
0.507 pr
=
2.01
llt