Mechanical Engineering Chapter 4 Homework A dynamic system with input f and output x is described by

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subject Pages 9
subject Words 2332
subject Authors Bei Lu, Ramin S. Esfandiari

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120
2
12
12
(2 1) 3
(3 2) 0
ss X X F
XsX

°
®
°
¯
Solve for
1
X
:
2. A dynamic system with input
f
and output
x
is described by
1
32()xx x ft
 
(a) Find the state-space form.
(b) Find the transfer function directly from the state-space form.
(c) Decide if the system is stable by examining the state matrix in Part (a).
Solution
(a) There are two state variables:
1
xx
,
2
xx
. The state-variable equations are
12
212
63 3
xx
xxxf
®
¯
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3. A system’s transfer function is defined as
2
() 2 1
() 31
Ys s
Us ss

(a) Find the input-output equation.
(b) Find the state-space form directly from the input-output equation.
(c) Find the transfer function directly from the state-space form.
Solution
(a)
32yyy uu
 
(b) State-space form is found as
4. A system is described by its governing equations
11 21
221
3( ) ( )
3( ) 0
xx x x ft
xxx

®
¯


where
f
is the input, while
1
x
and
1
x
are the outputs.
(a) Obtain the state-space form.
(b) Find the transfer matrix directly from the state-space form.
(c) Find the transfer matrix using the governing equations, and compare with Part (b).
Solution
(a) There are four state variables: 11
xx ,
22
xx
,31
xx ,
42
xx
. The state-variable equations are
13
24
312
412
43
3 3
xx
xx
xxxf
xxx
°
°
®
°
°
¯
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122
5. A system’s input-output equation is given as
1
4
32yy yuu
 
(a) Find the state-space form.
(b) Find the transfer function directly from the state-space form.
Solution
(a) State-space form is found as
1
1
24
01 0
, , , ,
31
x
uuu
x
ªº
½ ªº
®¾ «»
«»
 ¬¼
¯¿ ¬¼
xAxB x A B
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123
6. Repeat Problem 5 for the input-output equation
21
32
yyy uu
  
.
Solution
(a) State-space form is found as
1
33 3
222 2
01 0
, , , ,
x
uuu
x
ªºªº
½
®¾ «»«»

¯¿ ¬¼¬¼
xAxB x A B
7. A system’s transfer function is given as
2
32
() ( 1)
() 231
Ys s s
Us sss

(a) Find the input-output equation.
(b) Find the state-space form directly from Part (a).
(c) Find the transfer function from Part (b).
Solution
(a)
23yyyyuu
   
(b) State-space form is found as
(c) Using the state-space form,
1
() ( )
Gs s D
CI A B
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8. Find the input-output equation of a SISO system whose state-space form is given as
u
yDu
®
¯
xAxB
Cx
with
1
2
13
3
2
0
01
, , , 1 , 0
1uu D
ªº
ªº ªº
«»
«» ¬¼

¬¼
¬¼
AB C
Solution
We will first find the transfer function, as
9. Repeat Problem 8 for
>@
01 0
, , , 1 1 , 1
23 2 uu D
ªºªº
«»«»

¬¼¬¼
AB C
Solution
We will first find the transfer function, as
10. Find all possible input-output equations for a system with state-space form
u
u
®
¯
xAxB
yCxD
where
01 0 20 0
, , , ,
14 1 01 0
uu
ª º ªº ª º ªº
« » «» « » «»

¬ ¼ ¬¼ ¬ ¼ ¬¼
AB CD
Solution
We will first find the transfer matrix, as
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11. Find the transfer function for the system in Figure 4.36 using
(a) Block diagram reduction,
(b) Mason’s rule.
Figure 4.36 Problem 11.
Solution
(a) The inner loop is replaced with
1
1
323
1
s
ss
. With this, the larger loop is replaced with
In Problems 12–15, block diagram representation of a system is provided. Find the transfer function using Mason’s
rule.
12. Figure 4.37
Figure 4.37 Problem 12.
Solution
All paths are coupled: one forward path, two feedback loops. By Mason’s rule, we have
page-pf7
sss
13. Figure 4.38
Figure 4.38 Problem 13.
Solution
There are two forward paths and four loops, as shown in Figure Review4No13:
Forward path Gain Loop Gain
12456
1123
FGGG
242
1
G
1236
24
FG
5675
3
GH
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14. Figure 4.39
Figure 4.39 Problem 14.
Solution
There are three forward paths and two loops:
Forward path gain Loop gain
14
FG
1
G
In the general case of Mason’s rule, we have
13 13
1DGGHGGH
ªº
15. Figure 4.40
Figure 4.40 Problem 15.
Solution
There are two forward paths and two loops:
Forward path gain Loop gain
14
FG
1
kG
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128
In the general case of Mason’s rule, we have
In Problems 16–19, the input-output equation or the state-space form of a system model is provided. Construct the
appropriate block diagram, and directly use it to find the transfer matrix.
16. State-space form is
u
yDu
®
¯
xAxB
Cx
with
>@
1
2
11
322
010 0
, 0 0 1 , 0 , 1 2 0 , 0 ,
11
x
xDuu
x
ªº
½ ªº
«»
°° «»
®¾ «»
«»
°° «»
«»
¬¼
¯¿ ¬¼
xA BC
Solution
The block diagram is shown in Figure Review4No16.
Figure Review4No16
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17. Input-output equation is
23xx xuu
 
.
Solution
Choosing
1
xx
,
2
xx
, we first find the state-variable equations and the output equation, as
>@
12
1
221
2
21
3
xx
xxxu
yx x
°
®
°
¯
18. Input-output equation is
23xx xuu
  
.
Solution
Choosing
1
xx
,
2
xx
, we first find the state-variable equations and the output equation, as
>@
12
1
221
2
111
21
222
3
xx
xxxu
yxxu
°
®
°
¯
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130
19. State-space form is
u
u
®
¯
xAxB
yCxD
with
1
2
01 0 10 0
, , , , ,
13 1 02 0
xuu
x
½ ª º ªº ª º ªº
®¾ « » «» « » «»

¬ ¼ ¬¼ ¬ ¼ ¬¼
¯¿
xA BC D
Solution
The block diagram is shown in Figure Review4No19.
Figure Review4No19
page-pfc
20. A system is atable if the poles of the overall transfer function lie in the left half-plane; these poles are the same
as the eigenvalues of the state matrix. Consider the block diagram representation of a system shown in Figure
4.41, where
0k!
is a parameter. Determine the range of values of
k
for which the system is stable.
Figure 4.41 Problem 20.
Solution
The overall transfer function is formed by Mason’s rule, as
2
3
2
() 3( 2)
Ys ss
21. Repeat Problem 20 for the block diagram in Figure 4.42, where
0k!
is a parameter.
Figure 4.42 Problem 21.
Solution
The overall transfer function is formed by Mason’s rule, as
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22. Derive the linearized model for a nonlinear system described by
1
111 2
2
212
(0) 2
1cos , (0) 2
1
x
xxxx t
x
xxx
°
®
°
¯
Solution
Step 1: The operating point

12
,xx
satisfies
Add
11 2
11 1
12
01
2 0
01
xx x xx x
xx
°
®
°
¯
23. Repeat Problem 22 for
12 1
32
21 2
2sin (0) 1
, (0) 0
31
xx t x
x
xx x
°
®
°
¯
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133
Solution
Step 1: The operating point

12
,xx
satisfies
2
1
3
12
0 1
031
xx
xx
°
®
°
¯

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