978-1337094740 Chapter 7 Part 4

Type Homework Help

Pages 9

Words 2166

Textbook Steel Design 6th Edition

Authors William T. Segui

Unlock document.

This document is partially blurred.

Unlock all pages and 1 million more documents.

Get Access

will be used. To determine the required length of the longitudinal welds, investigate

3. 712 28. 29 in.

1. 53. 7125. 568 kips/in.

77. 16

23. 15512. 23 in.

The first option requires slightly shorter longitudinal welds. Try a 5-inch transverse

0. 6FyAgv UbsFuAnt 0. 63691. 0581. 875

303. 2 kips (controls)

7.11-6

From AISC Table J2.4, the minimum weld size is 1/8 inch (based on the angle

thickness). Maximum size 1/4 −1/16 3/16 in.

0. 6Fyt0. 6363

16 4. 05 kips/in.

2. 784 10. 2 in.

length of each longitudinal weld 10. 2

25. 1 in.

Use 1/8-in. fillet welds as shown.

0. 4Fyt0. 4363

0. 3Fut0. 3583

1. 856 10. 51 in.

length of longitudinal welds 10. 51

7.11-7

From AISC Table J2.4, the minimum weld size is 3/16 inch (based on the gusset plate

0. 6Fyt0. 6363

88. 1 kips/in.

Shear rupture strength is 0. 45Fut0. 45583

4. 176 59. 77 in.

0. 854. 1763. 550 kips/in.

and the strength of the transverse weld is

249. 6 −96. 264193. 2 kips

so the required length of the longitudinal welds is

193. 2

23. 55027. 21 in.

6. 96 35. 86 in.

1. 56. 9610. 44 kips/in.

The load to be carried by the longitudinal welds is

155. 6

25. 91613. 15 in.

Each option requires about the same length longitudinal welds. Try a 9-inch transverse

0. 6FyAgv UbsFuAnt 0. 63610. 131. 0583. 375414. 6 kips (controls)

The design strength is

Rn0. 75414. 6311. 0 kips 249.6 kips (OK)

0. 4Fyt0. 4363

0. 3Fut0. 3583

86. 525 kips/in.

4. 640 36. 21 in.

0. 854. 6403. 944 kips/in.

and the strength of the transverse weld is

1. 54. 6406. 96 kips/in.

The load to be carried by the longitudinal welds is

105. 4

23. 94413. 36 in.

Each option requires about the same length longitudinal welds. Try a 9-inch transverse

7.11-8

Tension member gross section: tPn0. 90FyAg0. 90361. 9362. 53 kips

For the net section, assume U0. 80: AeAgU1. 930. 801. 544 in.2

0. 6Fyt0. 6361

45. 4 kips/in.

4. 176 14. 97 in.

Check assumed value of U:

7.11-9

0. 5Fu

0. 5580. 828 in.2

Min. rL

300 1212

300 0. 48 in.

0. 4Fyt0. 4361

43. 6 kips/in.

1. 856 12. 93 in., try two 6½-in. longitudinal welds.

Check assumed value of U:

7.11-10

(a) LRFD solution

0. 9Fy

0. 9504. 28 in.2

Req’d AePu

0. 75Fu

192. 8

0. 75653. 96 in.2

Min. rL

300 17. 512

300 0. 7 in.

Try C10 15.3, Ag4. 48 in.24.28 in.2(OK)

0. 6Fyt0. 6363

88. 1 kips/in.

Shear rupture strength is 0. 45Fut0. 45583

2. 784 69. 25 in.

1. 52. 7844. 176 kips/in.

The load to be carried by the longitudinal welds is

151. 0

22. 36631. 91 in

The first option results in a slightly shorter connection. Use a transverse weld and two

30-inch longitudinal welds. Check assumed value of U:

0. 6FyAgv UbsFuAnt 0. 63622. 51. 0583. 75703. 5 kips

Use Rn703. 5 kips, Rn0. 75703. 5527. 6 kips 192. 8 kips (OK)

[7-60]

or posted to a publicly accessible website, in whole or in part.

0. 6Fy

0. 6504. 93 in.2

Req’d AePa

0. 5Fu

147. 8

0. 5654. 55 in.2

Min. rL

300 17. 512

300 0. 7 in.

Try C12 20.7, Ag6. 08 in.24.93 in.2(OK)

0. 4Fyt0. 4363

85. 4 kips/in.

Shear rupture strength is 0. 3Fut0. 3583

1. 856 79. 63 in.

length of longitudinal welds 79. 63 −12. 0

1. 51. 8562. 784 kips/in.

The load to be carried by the longitudinal welds is

114. 4

21. 57836. 25 in

The first option results in a shorter connection. Use a transverse weld and two 34-inch

longitudinal welds. Check assumed value of U:

0. 6FyAgv UbsFuAnt 0. 63625. 51. 0584. 5811. 8 kips

Use Rn811. 8 kips

Trusted by Thousands of
Students

Here are what students say about us.

Albert

University of Michigan

“I found almost every finance case study paper for my MBA courses.”.

Anna

University of Massachutsetts

“Wow! Solution manual for 3 out of 4 courses.”.

Collins

Jacksonville State University

“One-stop shop for college students. I passed all my exams thanks to Coursepaper”.

Jill

Boston University

“A helpful studying resources, a combination of all studying material in one place”.

Drake

Clark Atlanta University

“I graduated thanks to Coursepaper”.

Karen

College of Charleston

“I invested in Coursepaper, and it is paid off after the first semester. I got straight A”.

Hill

Concordia University Irvine

“Awesome awesome awesome site”.

Rachel

Coppin State University

“The one website that I recommend to every college students”.

978-1337094740 Chapter 7 Part 4

Unlock document.

Trusted by Thousands of
Students

Albert

Anna

Collins

Jill

Drake

Karen

Hill

Rachel

Kristopher

Resources

Company

Legal

978-1337094740 Chapter 7 Part 4

Unlock document.

Trusted by Thousands ofStudents

Albert

Anna

Collins

Jill

Drake

Karen

Hill

Rachel

Kristopher

Resources

Company

Legal

Trusted by Thousands of
Students