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164.4
164.4
M SE 32.88
5
=
==
4.17
410 + 0.6(450 – 410) = 434.0
434 + 0.6(495 – 434) = 470.6
4
563
470.6 + 0.6(518 – 470.6) = 499.0
64.0
5
584
499 + 0.6(563 – 499) = 537.4
46.6
Year
4
563
470.6 + 0.6(518 – 470.6) = 499.0
64.0
5
584
499 + 0.6(563 – 499) = 537.4
46.6
Year
410 + 0.9(450 – 410) = 446.0
446 + 0.9(495 – 446) = 490.1
490.1 + 0.9(518 – 490.1) = 515.2
515.2 + 0.9(563 – 515.2) = 558.2
558.2 + 0.9(584 – 558.2) = 581.4
(Refer to Solved Problem 4.1)
For = 0.3, absolute deviations for years 1–5 are 40.0, 73.0, 74.1,
0.6
0.9
MAD 51.8
MAD 38.1
=
=
=
=
Because it gives the lowest MAD, the smoothing constant of
= 0.9 gives the most accurate forecast.
50 + (50 – 50) holds for any ). Let’s pick t = 3. Then F3 = 48 =
50 + (42 – 50)
or 48 = 50 + 42 – 50
or –2 = –8
So, .25 =
4.19 Trend adjusted exponential smoothing: = 0.1, = 0.2
MAD = 24.3/6 = 4.05, MSE = 113.2/6 = 18.87. Note that all
numbers are rounded.