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March 29, 2020
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Pro
bl
em
9-
14B
(3
0
min
ut
es)
1.
Present
New Line
T
otal
(1)
Sales
…………………….
$22,000,000
$10,290,000
$32,290,000
(2)
Net oper
ating income
.
1,826,000
730,590
*
2,556,590
(3)
Oper
ating assets
……..
5,500,000
3,430,000
8,930,000
(4)
Margin (2) ÷
(1)
………
8.30%
7.10%
7.92 %
(5)
T
urnover (1) ÷ (
3)
……
4.00
3.00
3.62
(6)
ROI (4) ×
(5)
………….
33.20%
21.30%
28.63 %
*
Sales
…………………………………………………….
$10,290,000
V
ariabl
e expenses (65% ×
$10,290,000)
………
6,688,500
Contribution ma
rgin
…………………………………
3,601,500
Fixed e
xpenses
……………………………………….
2,870,910
Net oper
ating income
……………………………….
$ 730,590
2.
Brian Stettl
er
will be inclin
ed to reject the n
ew product line because
accepting it wou
ld reduce his divisi
on’
s ov
e
r
all rate of r
eturn.
4.
a.
Prese
nt
New Line
T
otal
Oper
ating assets
…………………
$5,500,000
$3,430,000
$8,930,000
Minimum re
quired return
………
×15 %
×15 %
×15 %
Minimum net
operating
income
$825,000
$514,500
$1,339,500
Actual net op
erating incom
e
….
$1,826,000
$ 730,590
$
2,556,590
Minimum net
operating
income
(above
)
…………………………..
825,000
514,500
1,339,500
Res
idual income
………………….
$1,001,000
$ 216,090
$1,217,090
b.
Under the resi
dual income appr
oach, Brian Stettler would
be inclined
Pro
bl
em
9-
15
B
(30
mi
nu
tes
)
1.
Breaking the
ROI computation into
two separa
te elements helps th
e
manager to s
ee important relationship
s that might remain hid
den. First,
the importance
o
f turno
ver of assets as a k
ey element to o
verall
profitabilit
y is emphasiz
ed. Prior to use of the RO
I formula, mana
gers
2.
Companies in the
Same Industry
X
Y
Z
Sales
…………………………….
$3,910,000
*
$1,390,000
*
$6,336
,000
Net oper
ating income
……….
$664,700
*
$180,700
*
$316,800
A
verage op
erating a
ssets
…..
$1,700,000
*
$2,
780,000
$2,640,000
*
Margin
…………………………..
17
%
13
%
5 %
*
T
urnover
………………………..
2.
3
0.5
2.4
*
Return
on investm
ent (ROI)
.
39.1%
6.50%
*
12
%
Problem 9-
15
B
(continue
d)
NAA R
eport No.
35
states (p.
35):
“Introducing
sales to measur
e level of
oper
ations helps to
di
sclose specifi
c areas for m
ore intensiv
e
inv
estigation.
”
Company Y’
s
margin is some
what lower than that of
Company X. Wh
y
Process tim
e ÷ Throughput tim
e
…..
Delivery cy
cle time in da
ys:
W
ait time
………………………………..
T
otal throughput t
ime
…………………
T
otal delivery cy
cle time
……………..
Problem 9-
16
B
(30 minut
es)
1.
a.
, b.
, and c.
Month
1
2
3
4
Throughput t
ime in days:
Process tim
e
…………………………..
..
0.5
0.8
0.
7
0.6
Inspection
time
…………………………
0.6
0.
7
0.5
0.5
Move t
ime
……………………………….
0.5
0.
7
0.5
0.3
Queue time
……………………………..
3.0
3.0
2.0
1.0
T
otal throughput t
ime
…………………
4.6
5.2
3.
7
2.4
Problem 9-
16
B
(continue
d)
3.
a. and b.
Month
5
6
Throughput t
ime in days:
Process tim
e
…………………………..
……..
0.
6
0.
6
Inspection
time
………………………………
0.
5
Move t
ime
…………………………………….
0.
3
0.
3
Queue time
…………………………………..
T
otal throughput t
ime
………………………
1.
4
0.9
Manuf
acturing cycle
e
fficiency
(MCE):
Process tim
e ÷ Throughput tim
e
………..
42.9%
66.
7%
As a compan
y pares a
way non-
value
-added activities, th
e manufactur
ing
cycle effic
iency impro
ves. The goal, of
course, is to hav
e an efficiency
of
100%. This wil
l be achieved when
all non-v
alue-added acti
vities have
been eliminated
and process tim
e equals through
put time.
=
12% × 2.80
= 33.60%
Net oper
ating income
………………………………….
Minimum re
quired return (
15
%
× $1,930,000)
….
Res
idual income
…………………………………………
Pro
bl
em
9-
17
B
(20
min
ut
es)
1.
Oper
ating assets do n
ot include inv
e
stments in
other companies or
in
undevelope
d land.
Ending
Balances
Beginning
Balances
Cash
…………………………………
$
13
6,0
00
$
1
39
,0
00
Accounts r
eceivab
le
……………..
4
78
,000
3
34
,00
0
Inv
entory
…………………………..
4
78
,000
5
63
,000
Plant and equi
pment (net)
…….
8
58
,000
8
74
,0
00
T
otal opera
ting assets
…………..
$1,9
50
,000
$1,910
,000
Average opera
ting assets
=
$1,950,000 + $
1,910,000
=
$1,930,000
2
Margin
=
Net operating
income
Sales
=
$648,480
=
12.00%
$5,404,000
Turnover
=
Sales
Average opera
ting
assets
=
$5,404,000
=
2.80
$1,930,000
ROI
=
Margin × Turn
over
16.71%
18.91%
Problem 9-
18
B
(30 minut
es)
1.
ROI
=
Net operating inc
ome
x
Sales
Sales
Average opera
ting assets
ROI
=
$78,0
00
x
$
990
,000
$
990
,000
$503,000
=
7.8
8%
×
1.97
=
15.542%
Problem 9-
18
B
(continue
d)
ROI
=
$157,200
x
$1,188,000
$1,188,000
$503,000
=
13.23%
×
2.36
=
31.22%
(Increase)
(Increase)
(Increase)
5.
Interest is
a financing expense
and thus is not us
e
d to co
mpute net
ROI
=
=
×
1.57
=
13.15%
(Increase)
=
×
3.08
=
24.27%
(Increase)
ROI
=
=
×
2.04
=
12.57%
(Increase)
Problem 9-
19
B
(30 minut
es)
1.
a.
, b.
, and c.
Month
1
2
3
4
Throughput t
ime in days:
Process tim
e
…………………………..
….
0.
5
0.
5
0.
5
0.5
Inspection
time
…………………………..
0.1
0.
1
0.
5
0.6
Move t
ime
…………………………………
1.4
1.3
1.
3
1.4
Queue time
……………………………….
5.6
5.
7
5.
6
5.
7
T
otal throughput t
ime
…………………..
7.
6
7.
6
7
.9
8.
2
Manuf
acturing cycle
e
fficiency
(MCE):
Process tim
e ÷ Throughput tim
e
…….
6.6%
6.6%
6.3%
6.1%
Delivery cy
cle time in da
ys:
W
ait time
………………………………….
15.6
14.5
11.8
9.
0
T
otal throughput t
ime
…………………..
7.
6
7.
6
7
.9
8.
2
T
otal delivery cy
cle time
……………….
23.2
22.1
19.
7
17
.2
2.
a.
The compan
y seems to be
improving ma
inly i
n the a
reas of qualit
y
control, mat
erial contr
o
l, on-time deliv
ery
, and total deliv
ery cycle
time. Customer
complaints, warr
anty claims
, defects, and
scrap ar
e
Problem 9-
19
B
(continue
d)
c.
While it is difficu
lt to dra
w any definitiv
e conclusions, it ap
pe
ars that
the company
has concentr
ated first on
those areas of perf
ormance
3.
a. and b.
Month
5
6
Throughput t
ime in days:
Process tim
e
…………………………..
……….
0.5
0.5
Inspection
time
………………………………..
0.6
0.0
Move t
ime
………………………………………
1.4
1.4
Queue time
…………………………………….
0.0
0.0
T
otal throughput t
ime
………………………..
2.5
1.9
Manuf
acturing cycle
e
fficiency
(MCE):
Process tim
e ÷ Throughput tim
e
………….
20.0%
26.3%
As
non-v
alue-added a
ctivities are elimina
ted, the manufact
uring cycle
efficiency im
proves.
The goal, of cours
e, is to hav
e an efficiency
of
100%. This is
achieved when all n
on-v
alue-added activiti
es hav
e
been
eliminated and
process time equa
ls throughput time.