CHAPTER 20 – 3
18. We can use the equation for the NPV we constructed in Problem 17. Using the sales figure of 3,420
units and solving for P, we get:
NPV = 0 = [–($73)(3,280) – ($38)(3,420 – 3,280)] + [(P – 38)(3,420) – ($73 – 38)(3,280)] / .025
19. From Problem 15, the incremental cash flow from the new credit policy will be:
Incremental cash flow = Q(P – v) – Q(P – v)
And the cost of the new policy is:
Cost of new policy = –[PQ + Q(v – v) + v(Q – Q)]
Setting the NPV equal to zero and solving for P, we get:
NPV = 0 = –[($125)(1,320) + ($98 – 96)(1,320) + ($98)(1,350 – 1,320)] + [(1,350)(P – 98) –
0 = –[$165,000 + 2,640 + 2,940] + $142,105.26P – 13,926,315.79 – 4,029,473.68
20. Since the company sells 700 suits per week, and there are 52 weeks per year, the total number of
suits sold is:
And, the EOQ is 500 suits, so the number of orders per year is:
To determine the day when the next order is placed, we need to determine when the last order was
Alternatively, we could consider that the store sells 100 suits per day (700 per week / 7 days). This