b. Flow rate = min (demand, capacity) = min (7, 8) = 7 per hour
b. Using Little’s Law solve for T: T = I/R = 200/600 = .333 hours = 20 minutes.
c. The throughput time can be decreased by either decreasing I, the number of checks in
the system, or increasing R, the flow rate.
3. The capacity of the receptionist is 4 minutes per customer or 15 customers per hour.
c. If the input to the system is random, as the flow rate approaches the capacity of the
system, the number of customers waiting will approach a very large number (infinity).
This occurs because capacity is wasted whenever the number of customers arriving in a
given time interval is less than capacity and when the arrivals later exceed capacity the
Each oven takes 30 minutes per order and can handle 2 orders per hour. There are 3
ovens so the total oven capacity is 6 cakes per hour.
The capacity of the process is 6 cakes per hour and the bottleneck is the ovens.
b. Throughput time = 2 + 8 + 30 + 60 + 2 + 3 = 105 minutes
The service manager takes 2 minutes per order and can handle 30 orders per hour.
Each chef takes 16 minutes per order and can handle 60/16 = 3.75 orders per hour. There
are 4 chefs so the kitchen can handle 4 X 3.75 = 15 orders per hour.
The bartender takes 3 minutes and can handle 20 orders per hour.
Each waiter takes 20 minutes and can handle 3 orders per hour. There are 6 waiters so