Archives

1 CHAPTER 1 THE NATURE OF MECHANICAL DESIGN 2

275 CHAPTER 10 HELICAL GEARS, BEVEL GEARS AND WORMGEARING K 276 pecify cast iron because of low stresses Gray cast iron  Class 20: 277 278 Specify: Ductile iron ASTM A536 60 40 18; Or Cast Iron, Class 40: 279 […]

293 294 295 WORMGEARING 296 297 Spreadsheet solution to Problem 10-18. Small differences from the solution on the preceding page are due to rounding differences and reading of data from graphs, rather than calculations. 298 Comments on the following Problems […]

CHAPTER 11 KEYS, COUPLINGS, AND SEALS Use L= 3.75 in to more nearly match hub length. Use L= 3.50 in to more nearly match hub length. 311 312 Use to more nearly match hub length. Too high for any spline […]

316 CHAPTER 12 SHAFT DESIGN GENERAL NOTES CONCERNING SOLUTIONS TO SHAFT DESIGN PROBLEMS Shafts with Only Radial Loads Applied to Them: CR Torques and Forces Acting Radial to Shaft Comprehensive Figure P12 1: Figure P12 2: Figure P12 3: Figure […]

335 At C: V (lb) V (lb) M (lb in) M (lb in) plane Specify Ok Shafts 1 and 3 can be designed similar to Problem 33. 36. Data from Figure 10-8 to 10-12 and Example Problems 10-4 and 10-5. […]

354 CHAPTER 13 TOLERANCES AND FITS 355 356 Tolerance diagrams for Problems 1 to 8 shown below Problem number B.H. B.H. B.S. B.H. B.H. B.S. B.H. B.S. B.H. = Basic Hole System; B.S. = Basic Shaft 357 Force or Shrink […]

360 CHAPTER 14 ROLLING CONTACT BEARINGS 361 C CBearing 6011 for both B and D 362 363 R T T/R e Y P 364

365 CHAPTER 16 PLAIN SURFACE BEARINGS Plain Surface Bearings Porous bronze or BU bearing Porous bronze bearing material/oil impregnated or BU or DU dry lubricated bearing. 366 Use Babbitt  high tin Hydrodynamically Lubricated Bearings Porous bronze or BU bearing […]

372 CHAPTER 17 LINEAR MOTION ELEMENTS minimum 373 Metric trapezoidal power screws Use ; Dp ¾ 2 screw required 374 P = 260.5 kW (Very high) 375 [Borderline self locking] 376

CHAPTER 18 SPRINGS 377 378  Buckling should occur ; Too high Notes concerning Problems 13 35: Sample solutions are shown. Problems 13 through 24 are compression springs. Problems 25 through 31 are extension springs. From Figure 18 9: Music […]

396 CHAPTER 19 FASTENERS Metric thread is approximately 8% larger in this size Closest standard thread is T.S. 397 TS American standard thread #10 32 is similar but not as close to measured dimensions.

3 From Eq. 2-5: 4 17) S AE (Table 2-8) ( T ab l e 2 – 9 ) (Table 2-9) from SAE 1040, 4140, 4340, 4640 s teels (Table 2 – 9 ) SAE from SAE 1040, 4140, 4340, […]

CHAPTER 20 MACHINE FRAMES, BOLTED CONNECTIONS AND WELDED JOINTS lb lb lb/in2n2 Use five 9/16 12 UNC bolts, 1 ¾ in long Figure P20-1 As lb lb/in2n2 Use  ¼ 20 UNC Bolts, 2.00 in long Figure P20-2 398 Figure […]

407 CHAPTER 21 ELECTRIC MOTORS AND CONTROLS nsf p f p 408 409 410

CHAPTER 22 MOTION CONTROL: CLUTCHES AND BRAKES C K D R L R2 411 412 413 nc n n/nc 414 A [Note: Tb/Ta= 90.2/3.48 = 25.9] W 415 416 417 418 w V g LI LII LIII D2w D2L W […]

31 32 33 34 35 Stress Concentrations [From Appendix A18-1] [ From A pp endix A18-1 ] 36 [From Appendix A18-1] [From Appendix A18- [From Appendix A18- 2] 37 Problems of a General Nature RB = 20.0 kN D 38 […]

11 CHAPTER 3 STRESS AND DEFORMATION ANALYSIS Direct Tension and Compression a) SAE 1020; b) SAE 8650; c) Ductile iron A536(60-40-18); d) Aluminum 6061-T6; e) Titanium Ti-6AL-4V; f) PVC; g) Phenolic; Note: The stress is close to the ultimate for […]

106 psi 28. psi psi psi 107 psi psi 279.56 kPa 29. Both principal stresses are compressive – same sign – 3D Solution. psi psi = 108 150.02 kPa 168.76 kPa psi 24.48 psi 30. Both principal stresses are compressive […]

90 psi psi psi 20. psi X-Axis -120 MPa 220 MPa psi psi 91 20. 3D Mohr’s Circle Solution 3D Principal Stresses: 3 1 2 3 1 220 MP a 2 0 MPa 120 MPa 92 psi psi psi psi […]

70 psi X-Axis psi psi 71 psi X-Axis 10. 3D Mohr’s Circle Solution 3D Principal Stresses: 1 113.305 MP a 2 0 MPa 3 283.305 MPa psi psi 1 2 3 72 psi 11. X-Axis psi psi 73 11. 3D […]

50 CHAPTER 4 COMBINED STRESSES AND STRESS TRANSFORMATIONS NOTES CONCERNING THE SOLUTIONS PRESENTED FOR MOHR’S CIRCLE PROBLEMS IN CHAPTER 4: 1. The objectives for all problems are to transform the given data for normal and shear 2. In general, the […]

140 2FR sin A + F = 1500 lb Use 141 800 A = d2 Ok T (N m) 400 0Time 400 142 SAE 1040 cold drawn has Aluminum 2024 T4 has 143 Ok Time Pm = 21.5 15 P […]

121 CHAPTER 5 DESIGN FOR DIFFERENT TYPES OF LOADING St Time Stress Time Stress Time 122 St Time Stress Time 123 V 1320 (lb) M (lb in) A B C D V (lb) M (lb in) V (lb) M (lb […]

158 CHAPTER 6 COLUMNS L 159 1.00 in 0.50 in 160 Ok Use 1.50 in Ok S R d/D; d= RD d= D = OD R=ID/OD = d/D d = RD 161 162 Use Ok Ok 163 Multiple designs possible. […]

178 CHAPTER 7 BELT DRIVES, CHAIN DRIVES AND WIRE ROPE V-Belt Drives CD Use  Standard Length 179 180 181 182 Roller Chain Drives Use No. 120 chain Design power rating Power Rating Use a No. 80 Chain 183 p […]

Pinion dedendum angle: Gear outer addendum: 209 Pinion outer addendum: Gear outside diameter: Pinion outside diameter: 210 PROBLEM : 8-49 EXAM PLE PROBLEM: 8-3 No of teeth in pinion = 18 No of teeth in pinion = 16 Gear ratio […]

193 CHAPTER 8 KINEMATICS OF GEARS Gear Geometry 194 195 196 197 198 199 200 201 202 Velocity Ratio 203 204 Errors in statements for Problems 29 32: Housing Dimensions in = Y Gear Trains  Analysis 205 206 Helical […]

225 CHAPTER 9 SPUR GEAR DESIGN Forces on Spur Gear Teeth 226 Problem 1 Pressure angle = 20 degrees Chapter 9 Power = 7.5 hp pinion speed = 1750 rpm Given data teeth in pinion = 20 teeth in gear […]

260 261 262 263 Connect blade wheel to output shaft Problem 77 – Produce a linear speed of blade = 375 ft/min Blade speed = perpheral speed of 9.0 in wheel vt of wheel = Dwnw/12 Input Power: P = […]

245 246 247 248 249 250 251 252 [Note that Problems 71, 72, and 73 compute the Power Transmitting Capacity.] 253 254 255 Note that Problems 74 to 79 call for the design of Double Reduction Drives. 256 Pd o […]