Pinion dedendum angle:
Gear outer addendum:
210
PROBLEM : 8-49 EXAM PLE PROBLEM: 8-3
No of teeth in pinion = 18 No of teeth in pinion = 16
Gear ratio 4.000 Gear ratio 3.000
Pitch diameter: Pinion 1.500 in Pitch diameter: Pinion 2.000 in
Nominal face width 0.928 in Nominal face width 0.949 in
Mean cone distance 2.692 in Mean cone distance 2.662 in
Pinion mean addendum 0.112 in Pinion mean addendum 0.159 in
Gear mean dedendum 0.130 in Gear mean dedendum 0.186 in
Pinion mean dedendum 0.051 in Pinion mean dedendum 0.077 in
FACE WIDTH FACE WIDTH
COMPUTED VALUES COMPUTED VALUES
BEVEL GEAR GEOMETRY
Computes values for features described in Table 8-8 in Section 8-8 of the text
GIVEN DATA GIVEN DATA
COMPUTED VALUES COMPUTED VALUES
211
PROBLEM : 8-45 PROBLEM : 8-47
No of teeth in pinion = 15 No of teeth in pinion = 25
Gear ratio 3.000 Gear ratio 2.000
Pitch diameter: Pinion 2.500 in Pitch diameter: Pinion 2.500 in
Mean cone distance 3.328 in Mean cone distance 2.345 in
Ratio Am/A o0.842 Ratio Am/A o0.839
COMPUTED VALUES COMPUTED VALUES
GIVEN DATA GIVEN DATA
COMPUTED VALUES COMPUTED VALUES
FACE WIDTH FACE WIDTH
BEVEL GEAR GEOMETRY
Computes values for features described in Table 8-8 in Section 8-8 of the text
212
PROBLEM : 8-50 PROBLEM : 8-51
No of teeth in pinion = 16 No of teeth in pinion = 12
Gear ratio 4.000 Gear ratio 3.000
Pitch diameter: Pinion 0.500 in Pitch diameter: Pinion 0.250 in
Nominal face width 0.309 in Nominal face width 0.119 in
Mean cone distance 0.881 in Mean cone distance 0.333 in
Ratio Am/A o0.854 Ratio Am/A o0.842
Pinion mean addendum 0.041 in Pinion mean addendum 0.027 in
Gear mean dedendum 0.048 in Gear mean dedendum 0.031 in
Pinion mean dedendum 0.019 in Pinion mean dedendum 0.013 in
BEVEL GEAR GEOMETRY
Computes values for features described in Table 8-8 in Section 8-8 of the text
COMPUTED VALUES
GIVEN DATA GIVEN DATA
COMPUTED VALUES
COMPUTED VALUES COMPUTED VALUES
FACE WIDTHFACE WIDTH
213
Wormgearing
Worm Gearing Given data:
Lead
Lead Angle
NOTE:
214
WORMGEARING PROBLEM: 52 WORMGEARING PROBLEM: 53A
Worm pitch diameter = 1.250 in Worm pitch diameter = 1.000 in
Circular pitch of gear = 0.3142 in Circular pitch of gear = 0.2618 in
WORMGEARING PROBLEM: 53B WORMGEARING PROBLEM: 53C
INPUT DATA
Worm pitch diameter = 1.000 in Worm pitch diameter = 1.000 in
Circular pitch of gear = 0.2618 in Circular pitch of gear = 0.2618 in
Axial pitch of worm = 0.2618 in Axial pitch of worm = 0.2618 in
Lead of the worm = 0.5236 in Lead of the worm = 1.0472 in
INPUT DATA INPUT DATA
COM PUTED RESULTS COM PUTED RESULTS
INPUT DATA
COM PUTED RESULTS COM PUTED RESULTS
215
WORMGEARING PROBLEM: 54 WORMGEARING PROBLEM: 55
Worm pitch diameter = 0.625 in Worm pitch diameter = 2.000 in
Diametral pitch = 16 Diametral pitch = 6
Circular pitch of gear = 0.1963 in Circular pitch of gear = 0.5236 in
Axial pitch of worm = 0.1963 in Axial pitch of worm = 0.5236 in
WORMGEARING PROBLEM: 56 WORMGEARING PROBLEM: 57
Worm pitch diameter = 4.000 in Worm pitch diameter = 0.333 in
Diametral pitch = 3 Diametral pitch = 48
Face width of gear = 2.000 in Face width of gear = 0.156 in
Circular pitch of gear = 1.0472 in Circular pitch of gear = 0.0654 in
INPUT DATA
COM PUTED RESULTS
INPUT DATA
COM PUTED RESULTS
INPUT DATA
COM PUTED RESULTS
COM PUTED RESULTS
INPUT DATA
216
Gear Trains Analysis
217
VELOCITY RATIO FOR GEARS PROBLEM 62 VELOCITY RATIO FOR GEARS PROBLEM 63
DESIRED VR = 3.14159 ( ) DESIRED VR = 1.7321 ( 3)
NPNGNGVR Differential = NPNGNGVR Differential =
Calc. Actual Actual Des. VR –VR Act. Calc. Actual Actual Des. V
R
–V
R
Act.
17 53.41 53 3.1176 0.02395 17 29.44 29 1.7059 0.02617
19 59.69 60 3.1579 0.01630 19 32.91 33 1.7368 0.00479
22 69.12 69 3.1364 0.00523 XX 22 38.11 38 1.7273 0.00478 XX
NPNGNGVR Differential = NPNGNGVR Differential =
Calc. Actual Actual Des. VR –VR Act. Calc. Actual Actual Des. V
R
–V
R
Act.
17 104.80 105 6.1765 0.01206 17 126.14 126 7.4118 0.00824
XX 18 110.96 111 6.1667 0.00225 XX 18 133.56 134 7.4444 0.02444
20 123.29 123 6.1500 0.01441 20 148.40 148 7.4000 0.02000
Kinematic Design of Gear Trains: Solutions to Problems 62-65 at the end of Chapter 8.
Enter data in blue-shaded cells.
XX shows combination of NP and NG with minimum differential.
218
nin = n out =
1800 rpm 2.00 rpm
[Ensure that no interference occurs for any pair of gears.]
Design:
Remaining
Factor Ratio
2 900
2 450
219
Ok
TV
Remaining
Factor Ratio
F 13.333 rpm
B
nin =
222.78 rpm
2C
B
Ok
Ok
TV TV
221
F 13.48 rpm
B
nin =
148.2 rpm
41.98 rpm
Ok
Ok
222
nin = H nout =
3600 rpm 3.984 rpm
Ok
Ok
3 3
223
Output shaft
TV
Ok
Input
shaft
A-worm
224
npPdNP
vrack =32.72 ft/min