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Solutions to Problems in
Chapter 13: Fusion Reactions
13.1. Assume an organic material comprised of H, C, O, N etc. The average atomic weight of these elements is
13.2. The nuclear radii are given (in fm) by
The following results are obtained.
13.3. (a) From equation (13.37) we have
(b) Repeating for d-t fusion we use Q = 17.6 MeV (equation 13.7) and <v> = 10-22 m3s-1 (Figure 13.3) to get
13.4. (a) The process of fusing 4 protons into a 4He nucleus must be considered in the context of atomic masses. We
add 4 me to each side of equation (13.25) to obtain
(b) The energy in each case is calculated from atomic masses – being careful with electron masses – as
( ) ( ) ( )
12 1 13 2
C H N 1.94 MeVQ m m m c
= + − =
13.5. The Q for this reaction is
13.6. Each p-p cycle produces 26.7 MeV of which 0.52 MeV is lost as neutrino energy giving a net energy which
can be observed as 26.18 MeV per p-p cycle. This represents the fission of 4 hydrogen nuclei. The observable
energy from the sun is 3.86×1026 W or
13.7. (a) One d-t fusion produces 17.6 MeV of energy. To produce 5 GW requires
922 –1
19 6
5 10 3.13 10 MeV s
1.6 10 10
−
=