721
*16–88.
SOLUTION
Kinematic Diagram: Since link AB is rotating about fixed point A,then
is always directed perpendicular to link AB and its magnitude is
.At the instant shown. vBis directed with an
angle with the horizontal. Also,block Cis moving horizontally due to the
constraint of the guide.
Instantaneous Center: The instantaneous center of zero velocity of bar BC at the
instant shown is located at the intersection point of extended lines drawn
perpendicular from and . Using law of sine, we have
vC
vB
45°
yB=vAB rAB =6(0.2) =1.20 m>s
vB
If bar AB has an angular velocity , determine
the velocity of the slider block Cat the instant shown.
vAB
30°
500 mm
200 mm
AB
=6rad/s
=45°
A
C
Ans: