m = [C {d } – Em
m T
m
E
4
2
2
3.673 10 in.
0
u
v
{fT} =
66
1
2
12.5 10 10 10 1 50 1
2
2(1 0.3)
0
4
4464
8929
4464
8929
0
17857
15.14
E =70 GPa, v = 0.3
i = yj – ym = 0 – 4 = – 4,
i = xm – xj = 0 – 6 = – 6
{fT} =
66
4
6
7.0 10 30 10 1 50 F 4
0
2(1 0.3)
0
6
30,000
45,000
30,000 lb
0
0
45,000
15.16
{fT} =
2(1 )
i
i
j
j
m
m
E t T
v
j = 0.4 m
j = 0
m = 0
m = 0.4 m
69
0.4
0.4
12 10 210 10 0.01 20 C 0.4
(1)
{}
T
f
=
66
10
20
12.5 10 10 10 1 50 10
20
2(1 0.3)
0
40
(1)
{}
T
f
=
44643
89286
44643
– 89286
0
178572
(2)
{}
T
f
= 4464.3
10
20
10
20
20
0
=
44643
–89286
44643
89286
– 89286
0
(3)
{}
T
f
= 4464.3
10
20
10
20
0
40
=
44643
89286
44643
89286
0
–178572
(4)
{}
T
f
= 4464.3
10
20
10
20
20
0
=
–44643
89286
44643
89286
89286
0
10
vT
EvT
x
y
xy
67.2
0
15.19
For bar with
=
0
1x
L
1
LL
[D] =
12
2
10
10
10
(1 )(1 2 )
000 v
v v v
v v v
E
v v v
vv
(4)
1
12
0
v
15.22 Using modified CSFEP to account for thermal stress due to element temperature change.
a) Pin-roller supports at bottom
586
15.23
Data File 0
Verification.5
4, 2, 2, 0, 2, 0
1, 1
0 INPUT TABLE 1.. BASIC PARAMETERS
NUMBER OF NODAL POINTS. . . . . . . . . . . . . 4
NUMBER OF ELEMENTS. . . . . . . . . . . . . . . . . 2
NUMBER OF DIFFERENT MATERIALS. . . . . 2
NUMBER OF SURFACE LOAD CARDS . . . . . 0
1 3 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00
587
2 2 0.1000E+01 0.0000E+00 0.0000E+00 0.0000E+00
3 0 0.0000E+00 0.1000E+01 0.0000E+00 0.0000E+00
4 0 0.1000E+01 0.1000E+01 0.0000E+00 0.0000E+00
0 INPUT TABLE 4.. ELEMENT DATA
GLOBAL INDICES OR ELEMENT NODES
ELEMENT 1 2 3 4 MATERIAL TEMP
0 OUTPUT TABLE 1.. NODAL DISPLACEMENTS
NODE U = X-DISP. V = Y-DISP.
1 0.00000000E+00 0.00000000E+00
2 0.98888970E–03 0.00000000E+00
3 –0.75555370E–03 0.98888970E–03
4 0.13194460E–02 0.20750000E–02
1OUTPUT TABLE 2.. STRESSES AT ELEMENT CENTROIDS
ELEMENT X Y SIGMA(X) SIGMA(Y) TAU(X, Y)
15.24 Solve Problem 15.3 using the Autodesk Program.
15.25 For the plane truss shown in Figure P15-6, bar element 2 is subjected to a uniform
temperature drop of T = 30°C. Let E = 70 GPa, A = 4 10^–4m^2, and alpha =
mm
mm
°C
27.3 MPa (T).
Figure 2 Displacement in Y Direction
