641
Appendix D
D.1 Using table D–1
(a) Load case 1
P = 10 kip L = 20 ft
– 10
2
(b) Load case 3
P = 5 kip L = 20 ft
=
1
4
(c) Load case 4
w = 1000
lb
ft
L = 30 ft
(1000) (30)
12
(d) Load cases 1 and 7
P = 5 kip, L = 20 ft w = 2
kip
ft
– 5 13(20)(2)
2
5(20) 5(2)(20)
(e) Load case 5
Note: Switch nodes 1 and 2
w = 2000
lb
ft
L = 20 ft
3(2000)20
20
(f) Load case 2
f1y =
2
3
5(2) 7 2(5)
7
= – 0.99 kN
f2y =
2
3
5(5) 7 2(2)
7
= – 4.01 kN
m1 =
2
2
5(5)(2)
7
= – 2.04 kN m
2
5(5) (2)
643
kN
12
