Section 9.2 Compound Inequalities
88. makes sense
89. makes sense
93. false; Changes to make the statement true will vary.
A sample change is:
,3 , 2 ,3   
94. false; Changes to make the statement true will vary.
97. The domain of
,4 .f
98. The domain of g =
1,.
100. The domain of
1, 4 .
f
g
101. Let n = number of nickels.
Let d = number of dimes.
Let q = number of quarters.
320 5 10 25 545
nd q
  
102.

2
25 34
gfx gx fx
xxx


159 15
  
103.
42 8
248
24
xy
yx
yx



104.

42 454285
42 13
42 13
17 2
xx
x
x
x



 
 

31 5 2 6
44 3
1
xx x
xx
x
 
 

107. a.
235
2( 5) 3 5
x

Chapter 9 Inequalities and Problem Solving
b.
235
x
9.3 Check Points
1.
215x
Rewrite without absolute value bars.
2. First, isolate
13.x
21 3 28 0
21 3 28
13 14
x
x
x



Rewrite without absolute value bars.
3.
27 3xx
27 3or 27 (3)
xx x x
  
4.
25x
5. First, isolate the absolute value expression on one
side of the inequality.
35 2 20 19
x

Rewrite without absolute value bars.
uc means .cuc 
13 5 2 13
13 2 5 2 2 13 2
11 5 15
11 5 15
555
x
x
x
x
 
  
 

uc means or .uc uc
253x
253or 253
xx
 
Section 9.3 Equations and Inequalities Involving Absolute Value
7. 41 3.2x
Rewrite without absolute value bars.
uc means .cuc 
9.3 Concept and Vocabulary Check
1. c; c
2. v; v
3. c; c
10. B
11. D
12. F
9.3 Exercise Set
1. 8x
8or 8xx
3. 27
27or 2 7
95
x
xx
xx

 

5.
217
217or21 7
28 2 6
43
x
xx
xx
xx

 


The solutions set is
3, 4 .
6. 2311
x

4232 4232
426 426
48 4 4
21
xx
xx
xx
xx
  
 


The solutions set is
1, 2 .
8.
31
1
5
x
31 31
1or 1
xx

3

Chapter 9 Inequalities and Problem Solving
9. 8x
The solution set is . There are no values of x for
which the absolute value of x is a negative number.
12. 20
20
2
x
x
x



The solution set is
2.
14. 3512
54
y
y


54 or 5 4
19
yy
yy
 
 
The solution set is
9, 1 .
16. 23 2 14
327
x
x


630 6 26
526
6
13
3
yy
yy
y



16 14
33
yy

The solution set is 14 16
,.
33



19. 75 2 16
x

Section 9.3 Equations and Inequalities Involving Absolute Value
21. 153
12
x
x


The solution set is . By definition, absolute
values are always zero or positive.
24. 3281
32 7
y
y


The solution set is . By definition, absolute
values are always zero or positive.
The solutions set is 1.
2



27. 5832xx 
5832or
58 32
282 88 2
210 86
xx xx
xx
xx
   
 
568
84
63
xx
x


The solution set is 4,5 .
3



3

30. 639xx
639or
639
xx xx
  
Chapter 9 Inequalities and Problem Solving
31. 2525xx 
2525 or25 25
xx x x
  
32. 3535xx 
35 35
3535 or
xx
xx
 
 
33. 35xx
35 or 35
xx
xx
  
34. 36xx
36 or 3 6
xxx x
  
2

35. 26102yy 
36. 4345yy 
43 45
4345or
yy
yy
 
 
37. 223
33
xx
 
15
x
or
2
3323 33
33
xx
  

  
  
38. 1
2
22
xx
11
2or 2
xx
xx

 
Section 9.3 Equations and Inequalities Involving Absolute Value
39. 3
33
x
x
 
40. 5
55
x
x
 
The solution set is
5, 5.
43. 21
121
12 2212
31
x
x
x
x

  
    
 
The solution set is
3, 1 .
45. 268
82 68
x
x

  
The solution set is
1, 7 .
46. 3517
17 3 5 17
x
x

 
48. 5x
5or 5xx
The solution set is
,5 5, . 
49. 31x
31or 31
xx
 
Chapter 9 Inequalities and Problem Solving
52. 34x
34or 34
17
xx
xx
 

The solution set is
,1 7, 
.
54. 5213x
52 13or5213
xx
 
55.
2 148
2248
228
x
x
x

 

19 7
3
x

The solution set is
19 ,7
3
.
26
y
The solution set is
6, 0 .
79
x
 
The solution set is
7, 9 .
Section 9.3 Equations and Inequalities Involving Absolute Value
60.
33
1
x
61.
2
35
3
x

22
or
3535
33
xx
 
62.
3
39
4
x

33
or
3939
44
xx
 
63.
21x
The solution set is
.
Since all absolute values are
zero or positive, there are no values of x that will
make the absolute value of the expression less than
–1.
64.
32x
65.
610x
66.
412x
Since all absolute values are zero or positive, we
know that when simplified, the left hand side will
be a positive number. We also know that any
positive number is greater than any negative
727
72 2272
95
x
x
x
  
    
 
13
x

The solution set is
1, 3
.
69.
22 3 10 12
22 3 2
x
x
 

Chapter 9 Inequalities and Problem Solving
70.
32 1 2 8
32 1 6
212
x
x
x



71.
41 16
41 16
44
14
x
x
x




72.
25 6
25 6
22
53
x
x
x




73.
32 1
213
x
x


74.
94 7
479
x
x


479or47 9
xx
 
75.
54 11x
5 4 11 or 5 4 11
46 4 16
34
xx
xx
y
x
 
 

311 3 15
11 5
3
xx
x
x
 

The solution set is
11 ,5 .


2214
7
xx
x
 

The solution set is
7, 2 .

Section 9.3 Equations and Inequalities Involving Absolute Value
79.
|13 1|5x  
51335
x
  
80.
34 1 3
34 4 3
x
x
  
  
81.
|2 3| 1 6
|2 3| 5
x
x


82.
24618
2424
x
x


83. Let x be the number.
|4 3 | 5x
84. Let x be the number.
|5 4 | 13x
85. ||ax b c
When solving, we do not reverse the inequality
symbol from “<” to “>” when dividing by a
86. ||ax b c
ax b c

or
ax b c

87.
41x
The graphs of
4fx x
and 1y intersect
The graphs of
4fx x
is below the graph of
5y when x is between
1
and 9. Thus, the
Chapter 9 Inequalities and Problem Solving
91.
21 3
3213
321 2121321
x
x
x

 
  
92.
15 3
3153
x
x

 
93.
57 7
7577
T
T

 
94.
50 22
22 50 22
28 72
T
T
T

 

The monthly average temperature for Albany, New
York ranges from
28 F
to
72 F
, inclusive.
95.
8.6 0.01
x

96.
9.4 0.01
0.01 9.4 0.01
9.39 9.41
x
x
x



97.
50 1.645
5
h
50 1.645
h

50 1.645
h
resulted in 41 or less heads, or 59 or more heads.
98. – 104. Answers will vary.
105.
15x
The solutions are –6 and 4 and the solution set is
The solutions are –8 and 0 and the solution set is
Section 9.3 Equations and Inequalities Involving Absolute Value
108.
235x
109.
215
33
x
110.
41x
111.
217x
112.
0.1 0.4 0.4 0.6x
113.
41x
114. Answers will vary.
115. does not make sense; Explanations will vary.
Sample explanation:
25x
means
25or 25.xx  .
see that the absolute value expression must be less
than 5. This is possible so the inequality does have a
solution.
118. makes sense
119. false; Changes to make the statement true will vary.
A sample change is: Some absolute value equations,
Chapter 9 Inequalities and Problem Solving
123. a.
43x
b.
43x
124. The proportion of refunds will be
0.3% 0.2%
0.003 0.002
p
p


125. |2 5| 3 4xx 
2534
54
1
1
xx
x
x
x
 


or
25 34
25 34
55 4
59
9
xx
xx
x
x
x
 
 



128.
2fx
is the horizontal line positioned at
2.y
Mid-Chapter Check Point
2.
52 19
62 10
35
x
x
x



The solution set is
3, 5 .
4.
10 3 2 1 8 1
10 6 3 8 1
61381
13 14 1
14 14
1
1
xx
xx
xx
x
x
x
x
  
 
 
 



The solution set is
,1. 
7.
|5||58|xx
55 8
458
xx
x
 

or
558
558
xx
xx
 
 
8.
52 9
52 9
42
2
x
x
x
x




and
53 17
520
4
x
x
x



10.
5
3
232
5
636
232
318215
18 15
3
xx
xx
xx
x
x
 
 
 
 
 
 


The solution set is
,3. 
1
5
x

1
x

The solution set is
1
,1 ,
5

 


.
Chapter 9 Inequalities and Problem Solving
13.
724
2
x

14.
31
43
394
35
5
3
x
x
x
x



The solution set is
5
,.
3

 


16.
32 5 6
25 9
259
x
x
x



259
214
7
x
x
x

or
259
24
2
x
x
x



The solution set is
2,7
.
18. a.
cost fixed costs variable cost
60, 000 0.18Cx x


0.12 60,000
x

d. Let x = number of compact discs.
0.30 60,000 0.18 30,000
0.30 60,000 0.18 30,000
0.12 60, 000 30,000
0.12 90,000
750,000
xx
xx
x
x
x



The company should produce and sell at least
750,000 compact discs.
20. Let x = grade on the fifth exam.
95 79 91 86
80 90
5
351
80 90
5
400 351 450
49 99
x
x
x
x



 

49,99
Section 9.4 Llnear Inequalities In Two Variables
9.4 Check Points
1.
42 8xy
First, graph the equation 42 8xy
with a solid
line.
Set 0y to find the x -intercept.
() 0
Px
6, .
4
y

Next, use the origin as a test point.
42 8
4(0) 2(0) 8
08,false
xy

Since the statement is false, shade the half-plane
2.
3
4
yx
First, graph the equation
3
4
yx
with a dashed
line.
3(, )
4
xy x xy
3
4
3
4(0)
4
40,true
yx

Since the statement is true, shade the half-plane that
Since the inequality is of the form
,ya
shade
the half-plane above the line.
Chapter 9 Inequalities and Problem Solving
4. Point (60,20).B Check this point in each of the three inequalities for grasslands.
35 5 7 70 3 35 140
TTPTP
5.
36
23 6
xy
xy


Graph the line 36xy
with a dashed line. Graph the line 23 6xy
with a solid line.
For 36xy
use a test point such as (0, 0).
The solution set of the system is the intersection (the overlap) of the two half-planes.
6.
2
21
3
xy
x
y

 

Graph the line 2xy with a dashed line.
Graph the line
2x
with a solid line.
Section 9.4 Llnear Inequalities In Two Variables
9.4 Concept and Vocabulary Check
1. solution; x; y;
51
2. graph
3. half-plane
9.4 Exercise Set
1. 3xy
First, graph the equation 3xy. Rewrite the
equation in slope-intercept form by solving for y.
3
xy

2.
3. 5xy
First, graph the equation 5xy. Rewrite the
equation in slope-intercept form by solving for y.
5
5
5
xy
yx
yx



y -intercept = –5
slope = 1
4.
Chapter 9 Inequalities and Problem Solving
5. 24xy
First, graph the equation 24xy
. Rewrite the
equation in slope-intercept form by solving for y.
24
24
xy
yx

 
7.
36xy
First, graph the equation
36xy
. Rewrite
the equation in slope-intercept form by solving
for y.
36
36
xy
yx

 
8.
32 6
236
33
2
xy
yx
yx

 
 
y-intercept = 3 slope =
3
2
Next, use the origin as a test point.