Chapter 2 Linear Equations and Inequalities in One Variable
109. Let x = number of miles driven.
80 0.25 400
x

110. Let x = the number of miles driven.
60 0.50 600

111. Let x = number of cement bags.
245 95 3000
245 95 245 3000 245
x
x

 
112. Let x = the number of cement bags.
265 65 2800
265 65 265 2800 265
x
x

 
113. – 116. Answers will vary.
117. makes sense
118. makes sense
122. false; Changes to make the statement true will vary.
A sample change is: The statement “x is at most 5”
125. Let x = number of miles driven.
Weekly cost for Basic Rental: $260.
Weekly cost for Continental: $80 + 0.25x
0.25 0.25
720
x
Basic Car Rental is a better deal if you drive more
than 720 miles in a week.
500 440 1.75xx 
Solve this inequality.
500 1.75 440 1.75 1.75
xx xx
  
out more than 80 hours a year.
127. 1.45 7.23 1.442
1.45 7.23 1.45 1.442 1.45
7.23 2.892
x
x
x



Chapter 2 Review Exercises
128. 126.8 9.4 4.8 34.5
126.8 9.4 4.8 4.8 34.5 4.8
yy
yy y y


129. A = PB, A = 8, P = 40% = 0.4
A
PB
130. Let xthe width of the rectangle.
Let 5xthe length of the rectangle.
22
34 2( 5) 2
Plw
xx


131.
5163 8
516324
5163 3243
21624
xx
xx
xxxx
x
 



132.
414
24(3)14
xy


814,false
No, the values make it a false statement.
3
y

Chapter 2 Review Exercises
The solution is set is
22 .
3.
7369
736 696
39
zz
zzzz
z
 


Chapter 2 Linear Equations and Inequalities in One Variable
4.
4 3310
412310
xx
xx
 

5.
6391573
3823
382 232
xx xx
xx
xxxx

 

6.
10
8
8810
8
80
x
x
x



The solution is set is
80 .
8.
777
777
77
11
z
z
z
The solution is set is
11 .
10.
39
5
x

11.
5
30 2
225
30
y
y


25
x

The solution is set is
25 .
13.
1
10
10 10 1
x
x




499339
424
424
44
6
x
x
x
x
 
The solution is set is
6.
Chapter 2 Review Exercises
16.
5203
5203 33
2200
zz
zzzz
z



17.
53 5
53 5
435
xx
xxxx
x

  

18.
32 98
32 8 98 8
36 9
36 3 93
xx
xx xx
x
x




19. a. 2012 is 5 years after 2007.
0.9 15
0.9(5) 15 19.5
pn
p


According to the formula, 19.5% of Americans
were religiously unaffiliated in 2012.
20.
5976 18
215 18
215 18
xxx
xx
xxxx
 

   
21.
34512
312512
xx
xx
x


The solution is set is
12 .
22.
126 3 2
112 2 3 2
13
yy
yy
y

  

The solution is set is
13 .
23. 2831522
xx x
  
Chapter 2 Linear Equations and Inequalities in One Variable
24.
2432262
2832262
510 6
yy y
yy y
yy

  

25. 21
36
xx

To clear fractions, multiply both sides by the LCD,
which is 6.
2
661
36
xx
 

 
 
26. 11
210 52
xx

Multiply both sides by the LCD, which is 10.
11
10 10
210 52
xx

 


27. Multiply both sides by 100 to clear the decimals.
0.5 8.75 13.25
100(0.5 8.75) 100(13.25)
x
x


0.1( 3) 1.1 0.25
0.1 0.3 1.1 0.25
100(0.1 0.3) 100(1.1 0.25 )
10 30 110 25
10 140 25
xx
xx
xx
xx
xx
 

 
 

330

Since 3 = 30 is a false statement, the original
equation is inconsistent and has no solution or
.
30.
42 3 4 8 8
xx
 
Chapter 2 Review Exercises
31.
0.7 220
133 0.7 220
Ha
a


32. I = Pr for r
or
IPr
PP
II
rr
PP

33. 1 for
VBhh
34. 2 2 for Plw w
222 2
22
22
22
22
or
22
Pl lwl
Pl w
Pl w
Pl Pl
ww
 



36. for TDpm m
TDDpmD
 
0.08 120
9.6
A
A

8% of 120 is 9.6
38. ; 90, 45% 0.45APBA P
90 0.45
90 0.45
0.45 0.45
B
B
40. Increase = Percent · Original
First, find the increase: 12 – 6 = 6
66
66
66
1
P
P
P

The percent increase is 100%.
Chapter 2 Linear Equations and Inequalities in One Variable
43. Investment dollars lost last year were
0.10 $10,000 $1000. This means that $10,000
$1000 = $9000 remains. Investment dollars gained
44. a.
7
77
h
r
h
r


45.
91 0.26
APB
B


46. Let x = the unknown number.
6204
6204 44
2200
xx
xxxx
x



47. Let x Buffett’s net worth.
Let
14x
Gate’s net worth.
(14)148
xx
 
193
2193
292
46
xx
x
x
x


2 2 2 100 2
298
x
x
 
50. Let xnumber of years after 2001.
7284 328 12,204
328 4920
328 4920
328 328
15
x
x
x
x

Chapter 2 Review Exercises
52. Let xthe width of the field.
Let
3x
the length of the field.
22
400 2 3 2
Plw
xx

 
53. Let xthe original price of the table.
0.25 180
0.75 180
0.75 180
0.75 0.75
240
xx
x
x
x

The table’s price before the reduction was $240.
56. Find the area of a trapezoid with bases 22 yd and 5
yd and height 10 yd.
1()
2
Ahab
57. Notice that the height of the middle rectangle is
64 12 12 40
m.
3000 4608
7608

The area is 7608 m
2
.
58. Since the diameter is 20 m, the radius is
20 10 m.
2
2 2 (10) 20 63C
ππ π
  
6
h
The height of the sail is 6 ft.
60. Area of floor:
2
(12 ft )(15 ft ) 180 ftAbh 
Chapter 2 Linear Equations and Inequalities in One Variable
61. First, find the area of a trapezoid with bases 80 ft
and 100 ft and height 60 ft.
62. The radius of the medium pizza is
114 inches 7 inches,
2
and the radius of each
small pizza is
18 inches 4 inches.
2
Medium pizza:
22
22
(7 in.)
49 in. 154 in.
Ar
ππ
π


Small pizza:
63. Find the volume of a rectangular solid with length 5
cm, width 3 cm, and height 4 cm.
534 60Alwh
The volume is 60 cm
3
.
64. Find the volume of a cylinder with radius 4 yd and
height 8 yd.
65. Find the volume of a sphere with radius 6 m.
3
4
Vr
π
66. Find the volume of each box.
3
(8m)(4m)(3m) 96mVlwh

The volume of the tank is approximately 85 ft
3
.
Divide by 5 to determine how many fish can be put
in the tank.
84.82 16.96
5
There is enough water in the tank for 16 fish. Round
down to 16, since 0.96 of a fish cannot be
purchased.
68. The sum of the measures of the angles of any
440180
4140
35
x
x
x

If x = 35, then 2x + 15 = 2(35) + 15 = 85 and x + 25
= 35 + 25 = 60. The angles measure 85 , 35 , and
60 .
supplement is
180 75 105
  .
72. Let x = the measure of the angle.
Let 90 – x = the measure of its complement.
Chapter 2 Review Exercises
73. Let x = the measure of the angle.
Let 180 – x = the measure of its supplement.
180 4 45
xx
 
74.
1x

75.
24x

78.
253
25535
28
28
22
4
x
x
x
x
x


,4

80.
35 18
35 3183
x
x


81.
465
46555
60
6606
xx
xxxx
x
x

  


6102 262
4106
41010610
416
416
44
4
xxxx
x
x
x
x
x



4,
Chapter 2 Linear Equations and Inequalities in One Variable
84.
22 4 4 2 6
48486
xx
xx
 
 
85.
24315
xxx

86. Let x = the student’s score on the third test.
42 74 60
3
42 74
3360
3
x
x





87. Let xthe number of people you invite to the
picnic.
350 55 2000
x

Chapter 2 Test
The solution set is
9.
2


525
525
55
5
x
x
x


The solution set is
5.
18 6 18 26 18
68
68
x
x
x


Chapter 2 Test
4.
32 4 9 3 1yy 
612933
yy

5.
315
4
43 4 15
34 3
20
x
x
x






The solution set is
20 .
6. 11
10 3 5 2
xx

Multiply both sides by the LCD, 30.
11
30 30
10 3 5 2
xx

 


7. 9.2 80.1 21.3 19.6xx 
To clear the equation of decimals, multiply both
sides by 10.
8. 2.4 180; 324Nx N 
2.4 180 324
2.4 180 180 324 180
2.4 144
2.4 144
2.4 2.4
60
x
x
x
x
x

 
The US population is expected to reach 324 million
60 years after 1960, in the year 2020.
9.
2
for Vrhh
π
2
22
Vrh
rr
π
ππ
11. ; 6% 0.06, 140APBP B 
0.06 140
8.4
A
A
6% of 140 is 8.4.
Chapter 2 Linear Equations and Inequalities in One Variable
12. ; A=120, 80% 0.80APB P
13. ; 12, 240APBA B
12 240
12 240
240 240
0.05
P
P
P

12 is 5% of 240.
14. Let x = the unknown number.
15. Let xthe average number of vacation days for
Americans.
Let 29xthe average number of vacation days
for Italians.
(29)55
29 55
xx
xx
 
 
17. Let x = the width of the field.
450 6
66
75
75
2 150
x
x
x
x
The field is 75 yards wide and 150 yards long.
18. Let x = the book’s original price.
height 22 meters.
11
47 22 517
22
Abh 
The area of the triangle is 517 m
2
.
20. Find the area of a trapezoid with height 15 in, lower
Chapter 2 Test
21. Notice that the height of the side rectangle is
639ft.
A
22. Find the volume of a rectangular solid with length 3
in, width 2 in, and height 3 in.
323 18Vlwh
The volume is 18 in
3
.
23. Find the volume of a cylinder with radius 5 cm and
height 7 cm.
24. The area of the floor is
2
(40ft)(50ft) 2000 ft .A
The area of each tile is
2
(2ft)(2 ft) 4ft .A
25. 56, 8Ab
1
2
A
bh
26. Let x = the measure of the second angle.
Let 3x = the measure of the first angle.
Let x − 30 = the measure of the third angle.
3 ( 30) 180
xxx
 
106
2 106
53
xx
x
x

The measure of the angle is 53 .
28.
2,
30.
2
3
223
x
x




69 6 336
927
927
99
x
x
x



Chapter 2 Linear Equations and Inequalities in One Variable
32.
422 6
42212
xx
xx
 
 
33. Let x = the student’s score on the fourth exam.
76 80 72 80
x

34. Let x = the width of the rectangle.
2(20) 2 56
40 2 56
x
x


Cumulative Review Exercises (Chapters 1-2)
1.
81216 8 4 84 4   
2.
32 246 8 2 
5. The rational numbers are
1
8.
6(4 1 5 ) 6(4 ) 6(1) 6(5 )
24 6 30
xy x y
xy
 

9.
0.9 80
An
 
62 0.9 80
18 0.9
18 0.9
n
n
n
 


76 14
76 14
77 14
77 7 147
77
77
xx
xx x x
x
x
x
x
  
 
 
  


Cumulative Review
12.
2
53
xx

Multiply both sides by the LCD, 15.
15 2 15
53
xx




13.
1 for
3
VAhA
1
3
1
33
3
3
3
33
or
VAh
VAh
VAh
VAh
hh
VV
AA
hh




15. Let x = the width of the parking lot.
Let
210x
the length of the parking lot.
22
400 2(2 10) 2
400 4 20 2
Plw
xx
xx



16. Let x = number of gallons of gasoline.
0.40 30,000
0.40 30,000
0.40 0.40
75,000
x
x
x
75,000 gallons of gasoline must be sold.
17.
1
,2

Chapter 2 Linear Equations and Inequalities in One Variable
19. 52(3 ) 2(2 5)1xx 
562 4 101
21411
xx
xx
  
 
20. Let xvalue of medical supplies sold.
600 0.04 2500
x
