Chemical Engineering Chapter 5 Sgmolgg Mlm Handbook Chemistry And Physics Mlmg Fgmol Gmol Amp Gmol Amp

subject Type Homework Help
subject Pages 11
subject Words 1107
subject Authors H. Scott Fogler

Unlock document.

This document is partially blurred.
Unlock all pages and 1 million more documents.
Get Access
page-pf1
5-18
60
S
g
MW gmol
=
6
3
2.32 2.32 *10
S
g g
ml m
!
= =
(Handbook of Chemistry and Physics, 57th ed., p.B-155)
6
3
1 10
g g
ml m
!
"=
20
F
g
MW gmol
=
3 3
0.5 0.0005V dm m= =
9
1.2986 *10
!
"
=
( ) ( ) ( )
1.775
6
3
9 3
1.775
2 6
3
60
10
1.2986 *10 0.0005
20 0.2 2.3*10 100
g
gkgmol
mm
gg
m
gmol m
!
" #
" # $ %
$ % & '
$ %
=" #
$ % $ %
$ % & '
& '
0.775
3
7 1
3.224 *10 min
m
kgmol
! !
" #
=$ %
& '
Final concentration of HF
Initial concentration of HW = 0.2 (given) weight fraction = 20%
0.775
10.7
1.775
20 0
6
100
t
F
dw k dt
w MW
!
" #
$=% &
' (
) )
( )
0.775
10.7 6
7
0.775
20
1 1 10
6 3.224 *10
0.775 20 *100
t
w
!" #
" # =$ %
$ %
& ' & '
4
0.775 0.775
1 1 1 2.389 *10
0.775 10.7 20
t
!
" #
!=
$ %
& '
331t=
min
P5-14 (a)
A + 3B C + 2D + E
page-pf2
5-19
Temperature(K)
Conc. Of
A(mol/dm3)
Conc. Of
B(mol/dm3)
Conc. Of
C(mol/dm3)
Rate
(mol/dm3.min)
323
0.10
0.10
0.002
0.001
343
0.05
0.10
0.008
0.004
363
0.20
0.01
0.02
0.01
Space time for differential reactor = 2 min
0P
P
P P
v C
F
V
r r
= =
! !
2 4
2
C H
P
P
C
C
r
!
= =
Rate law:
r
C=Ae "B/T
( )
CA
xCB
y
CC
2=Ae "B T
( )
CA
xCB
y
Where, A is Arrhenius constant
B = activation energy/R
x is the order of reaction wrt A
While using polymath for solving the rate law apart from guessing the initial values of n, m, and A , we
Nonlinear regression (L-M)
Model: r = A*exp(-6500/T)*Ca^x*Cb^y
Variable Ini guess Value 95% confidence
A 3.6E+05 3.649E+06 2.928E+04
x 0.25 0.2508555 0.0032606
R^2 = 0.9323139
R^2adj = 0.8871898
page-pf3
5-20
Hence, by nonlinear regression using polymath
A = 3.649E+06(mole/dm3)-2. 6(1/s)
E = 6500R = 54.015 KJ/mol
P 5-14 (b) Individualized solution
P5-15 (a)
Model 1: Monod equation
ss
cs
g
c
CK
CC
r
dt
dC
+
== max
µ
See Polymath program P5-15-a.pol.
POLYMATH Results
Nonlinear regression (L-M)
Model: rg = (umax)*Cs*Cc/(Ks+Cs)
Variable Ini guess Value 95% confidence
umax 1 0.3284383 0.00686
Ks 1 1.694347 2.2930643
P5-15 (b)
Model 2: Tessier Equation
rg=
µ
max 1"exp "Cs
k
#
$
% &
'
(
)
*
+
,
-
.
CC
See Polymath program P5-15-b.pol.
POLYMATH Results
Nonlinear regression (L-M)
Variable Ini guess Value 95% confidence
umax 0.5 0.3258202 0.0034969
k 100 20.407487 5.7120407
R^2 = 0.9999454
R^2adj = 0.9999345
page-pf4
5-21
rg=0.33 1"exp "CS
20.4
#
$
% &
'
(
)
*
+
,
-
.
CC
g/dm3.h
P5-15 (c)
Model 3: Moser Equation
max
1
C
gy
S
C
rkC
µ
!
=+
See Polymath program P5-15-c.pol.
POLYMATH Results
Nonlinear regression (L-M)
Model: rg = umax*Cc/(1+k*Cs^(-y))
Variable Ini guess Value 95% confidence
umax 0.3 0.3265614 6.984E-04
k 1.6 162.599 34.273983
R^2 = 0.9999447
R^2adj = 0.999917
P5-16
Your values of A, E and α will depend on your initial guess. Look for the lowest s2.
Thermal decomposition of isopropyl isocynate in a differential reactor.
Run
Rate
(mol/s.dm3)
Concentration
(mol/dm3)
Temperature
-(K)
1
4.9 x 10-4
0.2
700
3
2.4 x 10-3
0.05
800
5
1.18 x 10-1
0.1
900
Rate law:
( )
/E RT n
A A
r Ae C
!
!=
Where, A is Arrhenius constant
E is the activation energy
page-pf5
5-22
POLYMATH Results
Nonlinear regression (L-M)
Model: rA = A*exp(-E/(8.314*T))*(CA)^n
Variable Ini guess Value 95% confidence
A 100 1.01E+04 327.35758
E 1000 5.805E+04 237.32096
Precision
R^2 = 0.6690419
R^2adj = 0.4484032
Rmsd = 0.0097848
Hence, by nonlinear regression using polymath
A = 10100 (mole/dm3)-2. 6(1/s)
CDP5-A
page-pf6
5-23
page-pf7
5-24
From the plot, it is evedent that linear relationship exists between (1/A - A) and time;
Therefore the reaction is second order.
CDP5-B
Determine the reaction order and specific rate constant for the isomerization reaction:
A B
Rate law:
dt
dC
kCr A
AA !==!
"
CDP5-C
Ethane hydrolysis over a commercial nickel catalyst in a stirred contained solid reactor.
H2+C2H6"2CH4
PA = CART = CA0RT(1- X) = PA0(1- X)
PB = CBRT = CA0RT(
"
B- X) = PA0 (
"
B- X)
page-pf8
5-25
X=ypFT0
2FA0
=yp
2yA0
=yp(1+
"
B)
2
"r'A="r'B=FA0X
W=
Fp
2W=
ypFA0
2W
"r'A=kP
A
#
P
B
$
ln("r'A)=ln k+
#
ln PA+
$
ln P
B
y=A0+A1X1+A2X2
FT0(gmol/h)
PA0(atm)
PB0(atm)
yCH4
X
Q
PA(atm)
PB(atm)
-
rA(gmol/kg.h)
1.7
0.5
0.5
0.05
0.05
1
0.475
0.475
1.0625
0.6
0.5
0.5
0.16
0.16
1
0.42
0.42
1.2
0.75
0.6
0.6
0.1
0.1
1
0.54
0.54
0.9375
POLYMATH Results
Nonlinear regression (L-M)
Model: ra = k*(Pa^alfa)*(Pb^beta)
Variable Ini guess Value 95% confidence
k 0.1 0.5068635 0.1124446
alfa 1 0.9828027 0.152574
beta 1 -1.9669749 0.1668241
hence, the rate law is:
'
2
0.5 / .
A
A
P
r gmol kg hr
P
!=
page-pf9
5-26
CDP5-D
CDP5-E
page-pfa
5-27
page-pfb
5-28
page-pfc
5-29
CDP5-F
page-pfd
5-30
page-pfe
5-31
page-pff
5-32
CDP5-G
From given data, find the rate law.
Given: Oxidation of propene to acrolein
Rate law:
2
a b
A P O
r kP P=
5.0=!W
g
Using Polymath non linear regression, the following results were obtained:
Nonlinear regression (L-M)
Model: ra = k*Pp^a*Po2^b
Variable Ini guess Value 95% confidence
k 5 0.006609 2.685E-05
a 1 0.9948724 0.0046367
CDP5-H
1)
So,
page-pf10
5-33
CDP5-I
CDP5-I (c) No solution
CDP5-J No solution will be given.
page-pf11
5-34
CDP5-K No solution will be given.

Trusted by Thousands of
Students

Here are what students say about us.

Copyright ©2022 All rights reserved. | CoursePaper is not sponsored or endorsed by any college or university.