Chemical Engineering Chapter 4 For assumed turbulent flow, α is proportional to

subject Type Homework Help
subject Pages 9
subject Words 190
subject Authors H. Scott Fogler

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CDP4-I (a)
CDP4-I (b)
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CDP4-I (c)
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CDP4-I (d)
CDP4-I (e)
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CDP4-J (a)
b) We know, ε = 0, so
2/1
0)1( WPP
!
"=
=>
2/1
)1(201 W
!
"=
=> α = 9.98 x 10-4
c) For conversion to be maximum, α should be minimum
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Hence for minimum α, Dp and Dpipe should be increased. d) Yes, we can
increase Dp and decrease Dpipe (or vice versa) according to the above equation to get the same value of α.e)
For assumed turbulent flow,α is proportional to
f) We’re given,
2
1
12
1
~
p
p
pD
D
kk
D
k=!
Hence
4.11
044.0
5.0
1
2==
k
k
g) Rate law:
CDP4-K
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b) From polymath: Maximum flow rate = 1750 mol/s
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CDP4-L
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CDP4-M No solution
CDP4-N
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CDP4-O No solution
CDP4-P
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CDP4-Q
CDP4-R
CDP4-S

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