4-74
4-75
CDP4-I (a)
CDP4-I (b)
4-76
CDP4-I (c)
4-77
CDP4-I (d)
CDP4-I (e)
4-78
CDP4-J (a)
b) We know, ε = 0, so
2/1
0)1( WPP
!
“=
=>
2/1
)1(201 W
!
“=
=> α = 9.98 x 10-4
c) For conversion to be maximum, α should be minimum
Hence for minimum α, Dp and Dpipe should be increased. d) Yes, we can
increase Dp and decrease Dpipe (or vice versa) according to the above equation to get the same value of α.e)
For assumed turbulent flow,α is proportional to
f) We’re given,
2
1
12
1
~
p
p
pD
D
kk
D
k=!
Hence
4.11
044.0
5.0
1
2==
k
k
g) Rate law:
CDP4-K
4-80
b) From polymath: Maximum flow rate = 1750 mol/s
4-82
CDP4-L
4-83
4-84
CDP4-M No solution
CDP4-N
4-85
CDP4-O No solution
CDP4-P
CDP4-Q
CDP4-R
CDP4-S