3-21
dm
P3-16 (d)
Gas phase reaction in a constant pressure, batch reactor
Rate law (reversible reaction):
3
C
A A
C
C
r k C
K
! “
#=#
$ %
& ‘
Stoichiometry:
Combine and solve for Xe:
Equilibrium concentrations:
P3-17
Given: Gas phase reaction A + B 8C in a batch reactor fitted with a piston such that
V = 0.1P0
3-22
P3-17 (a)
0
0
0 0
0.5
A
A
A B
N
yN N
= =
+
8 1 1 6
!
=” “ =
03
A
y
! “
= =
Therefore
( )
2
0
10 1
10
V
V X
V
!
= +
or
( )
2 2
01V V X
!
= +
Therefore
P3-17 (b)
P3-18 No solution will be given.
P3-19 No solution will be given.
3-23
P3-20 No solution will be given.
CDP3-A
CDP3-B
Polanyi equation: E = C – α(-ΔHR)
We have to calculate E for the reaction
CDP3-C (a)
A B
Rate law at low temperature:
“r
A=kCA
The rate law t higher temperature must:
Here,
KC=CDe
2
CAeCBe
2
CAeCBe
2“CDe
2
KC
=0
“r
A=kACAeCBe
2“CDe
2
KC
#
$
%
%
&
‘
(
(
But it does not satisfy the irreversible rate law at low temperatures.
Hence it is not correct
CDP3-C (c)
A + B C + D
Irreversible rate law:
“r
A‘=kPAP
B
1+KAP
A+KBP
B
CDP3-D
3-25
3-27
CDP3-E
3-29
CDP3-F
CDP3-G
3-31
CDP3-H
3-33
CDP3-I
3-35
3-36
CDP3-J
Species
Symbol
Entering
Change
Leaving
SiH4
A
FA0
–3FA0
FA0(1–X)
“B=FB0
FA0
=1
CA=CA01%X
( )
1+
#
X=6.18 ,10%81%X
( )
1+2.5X
CDP3-K
3-38
