Buoyancy and Stability
49
CHAPTER FIVE
BUOYANCY AND STABILITY
Buoyancy and Stability
59
5.51 From Prob. 5.30, X = 118 mm
VS = Vol. of steel bar = 9.073 104 mm3
5.52 From Prob. 5.22, Fig. 5.23: X = 600 mm
ycb = X/2 = 300 mm
Chapter 5
64
I =
4
4(11.51/ 2)
64 64
X
D
= 53.77 in4
5.63 (a) v
F = 0 = Fb Wc Wv
(b) Find
v = Specific weight of vessel material = Wv/VvT; Given Wc = 5.0 kN
Buoyancy and Stability
65
(c
)
E
v
aluate
s
t
ab
i
l
i
t
y
.
Find
m
e
t
ace
n
ter
,
y
mc
.
S
e
e
f
i
g
u
re
f
o
r
k
e
y
d
i
m
ensions.
We know from part (a): Vd = 1.502 m3; Vhs = 0.8836 m3; Vcyl-d = 0.6185 m3
5.64 Let Fs be the supporting force acting vertically upward
when the club head is suspended in the water.
v
F = 0 = Fs + Fb W; Then Fs = W Fb
5.65 DFB VF
5.66
3
2
CYL.
0.393mm 2
(0.5m)
V
Chapter 5
66
5.67 A. When hanging above the water, there is no buoyant force, so the tension in the
5.68
N 1226
s
m
9.81kg 125LiftedWeight
2
5.69 When neutrally buoyant, 0 = FBD + FBL WD – WL
V9.8178V0
N
5.70
4
m) (0.12
m
N
98102.6VF
2
3
DFB
5.71 Steel will float in any fluid that has a specific gravity higher than its own. Steel has a
Buoyancy and Stability
67
5.72 Naturally it will float since it has a specific weight less than that of water.
5.73
F
BCAM BFCAM
FFWW
5.74
F BFCAM
FWW
in 12
ft 1
in 6
4
(D)
V
2
F