2.14
Situation:
Open tank of water.
T20 =20◦C,T80 =80◦C.
V=400l,d=3m.
Hint: Volumechangeisduetotemperature.
Find:
Percentage change in volume.
Water level rise for given diameter.
Properties:
From Table A.5: ρ20 = 998 kg
m3,and ρ80 =972kg
m3.
PLAN
This problem is NOT solved using the elasticity equation, because the volume change
results from a change in temperature causing a density change, NOT a change in
pressure. The tank is open, so the pressure at the surface of the tank is always
atmospheric.
SOLUTION
a. Percentage change in volume must be calculated for this mass of water at two
temperatures.
b. If the tank has D=3m,thenV=πr2h=7.68h.Therefore:
14