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Chapter 17 There is enough evidence to conclude that garlic
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April 27, 2023
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Appendix 17
A17.1a
z-test of p
1
–
p
2
(case 1)
H
0
: p
1
–
p
2
= 0
H
1
: p
1
–
p
2
< 0
+
−
−
=
2
1
2
1
n
1
n
1
)
p
ˆ
1
(
p
ˆ
)
p
ˆ
p
ˆ
(
z
1
2
3
A
B C
D
z-Test: T
wo Proportions
Allicin Col
d?
Placebo Cold?
b. Equal-v
ariances t-test of
µ
1
− µ
2
H
0
:
µ
1
–
µ
2
= 0
1
2
3
4
5
6
A
B C
t-Test: T
wo-Sample Assuming Equal Variances
Allicin Days
Placebo Days
Mean
6.29 8.11
Variance
2.39 4.25
Observations
24 65
A17
.2
t-test o
f µ
D
H
0
: µ
D
= 0
1
2
3
4
5
6
A
B C
t-Test: Paired Two Sample for Means
Eye-level
Lower shelf
Mean
302.4 290.8
Variance
2482.2 6262.7
Observations
40 40
t = 1.35; p-
value = .0922. There is not enoug
h evidence to conclude that
placem
ent of the product at eye lev
el
significantly incr
eases sales?
A17.3 Equ
al-variances t-test of
2
1
−
)
(
:
H
2
1
0
−
= 0
1
2
3
4
5
6
A
B C
t-Test: T
wo-Sample Assuming Equal Variances
British American
Mean
6344.5 6358.3
Variance
5084.0 3104.6
Observations
28 33
t =
–
.8
4, p-value
= .2010. There is not enough eviden
ce to conclude that British courses are
shorter than American
courses.
A17.4 Chi-
squared test of a contingen
cy table
:
H
0
The two v
ariables are independent
1
2
3
4
5
6
A
B C D
E
Contingency Table
Group
Choice
1
2 TOT
AL
1
7
19 26
2
8
17 25
A17.5 t-
test of
ρ or β
1
:
H
0
= 0
0
:
H
1
2
r
1
2
n
r
t
−
−
=
1
2
3
A B
C
D
Correlation
Repair cost and Credit score
A17.6 z
-estimator of p
n
/
)
p
ˆ
1
(
p
ˆ
z
p
ˆ
2
/
−
1
2
A B
z-Estimate: Proportion
Photograph
y
Confidence in
terval estimate of the total n
umber of American adults who
participate in photography
LCL = 205.8 million
(.085) = 17.493 million
UCL = 205.8
million (.162) = 33.396 million
1
2
3
4
5
A
B C
D
z-Test: T
wo Proportions
Compression
Compression & breaths
Sample Proportions
0.221 0.0997
Observations
439 712
A17.8
Ch
-squared test of a contingen
cy table
:
H
0
The two v
ariables are independent
1
2
3
4
5
6
7
A
B C D
E
Contingency Table
Age category
Mutual fu
nd
1
2 TOT
AL
1
19
6
25
2
75
57 132
3
92
123 215
A17.9 Equ
al-variances t-test of
2
1
−
)
(
:
H
2
1
0
−
= 0
)
(
:
H
2
1
1
−
> 0
+
−
−
−
=
2
1
2
p
2
1
2
1
n
1
n
1
s
)
(
)
x
x
(
t
1
2
3
4
5
A
B C
t-Test: T
wo-Sample Assuming Equal Variances
Year 1995
Year 2005
Mean
66.37 64.67
Variance
64.24 64.71
getting smaller?
A17.10
Chi-squared test of a contingen
cy table
:
H
0
The two v
ariables are independent
1
2
3
4
5
A
B C D
E
Contingency Table
Weight category
Hip/Knee
1
2 TOTAL
1
9
6
15
A17.11
One-way analysis of variance an
d multiple comparisons
After the show
10
15
11
12
A
B
C D
E
F
G
ANOVA
Source of Vari
ation
SS
df
MS
F
P-value
F crit
Betwe
en Groups
24.71
2
12.35
5.12
0.0067
3.03
1
2
3
A
B C
D
E
Multiple Co
mparisons
LSD Omega
10
15
11
12
A
B
C D
E
F
G
ANOVA
Source of Vari
ation
SS
df
MS
F
P-value
F crit
Betwe
en Groups
36.90
2
18.45
9.06
0.0002
3.03
1
2
A
B C
D
E
Multiple Co
mparisons
A17.12
1
2
8
3
4
5
A
B
C
D E
F
SUMMARY OUTPUT
Regre
ssion
Statistics
Multi
ple R
0.8415
R Squa
re
0.7081
b The coefficien
t of determination is
2
R
= .7081; 70.81
% of the variation in electricity
consumption is explained by
the model. The
model fits reasonably well.
c
:
H
0
=
1
=
2
0
i
F = 117.6, p-
value = 0. There is enough
evidence to conclude that the model is v
alid.
d & e
1
2
3
4
5
A
B
C D
Prediction Interval
Con
s
umption
Predicted v
alue
8175
A17.13
Wages: Equal-variances t-test o
f
2
1
−
)
(
:
H
2
1
0
−
= 0
1
2
3
4
5
6
A
B C
t-Test: T
wo-Sample Assuming Equal Variances
Goods wages
Service wages
Mean
18.66 16.78
Variance
11.54 10.05
Observations
395 463
Benefits: Unequal
-variances t-test of
2
1
−
)
(
:
H
2
1
0
−
= 0
)
(
:
H
2
1
1
−
0
+
−
−
−
=
2
2
2
1
2
1
2
1
2
1
n
s
n
s
)
(
)
x
x
(
t
1
2
3
4
5
6
A
B C
t-Test: T
wo-Sample Assuming Unequal Variances
Goods benefits
Service benefits
Mean
9.82 6.34
Variance
3.91 1.03
Observations
395 463
A17.14
Multiple regression, test of
coefficients
i
b
i
i
s
b
t
−
=
The ordinary
multiple regression model fit quite
well. The coefficient of determination is .704
2 and the p
–
value of
1
2
3
4
5
6
10
11
12
13
14
20
21
22
23
24
25
26
27
M N
O
P
Q
R
S
Results of stepwise regres
sion
Step 1 – Entering
var
iable: As
t92_9
3
Summ
ary measu
res
Multipl
e R
0.77
25
ANOVA Table
Source
df
SS
MS
F p-value
Explai
ned
1
10258242603399.2000 10258242603399.
2000
71.023
2 0.0000
Unexplained
48 6932882522112.0000
144435052544.0000
Step 2 – Entering
var
iable: Goal92_93
Summ
ary measu
res
Change
% Chan
ge
Multipl
e R
0.80
86
0.0361
%4.7
R-Squa
re 0.6538
0.0571
%9.6
Adj R-Square
0
.6390
0.0507
%8.6
StErr of
Est
3558
59.937
5
-241
86.187
5
-%6.4
A17.15On
e-way analysis of variance
3
2
1
0
:
H
=
=
Weight gain
10
15
11
12
A
B
C
D
E
F G
ANOVA
Source of Vari
ation
SS
df
MS
F
P-value
F crit
Betwe
en Groups
608.6
2
304.32
10.47
3.73E-05
3.02
1
2
A
B
C D
E
Multiple Co
mparisons
Systolic blood
pressure increase
10
15
11
12
A
B
C
D
E
F G
ANOVA
Source of Vari
ation
SS
df
MS
F
P-value
F crit
Betwe
en Groups
929.6
2
464
.78
1.67
0.1898
3.02
Diastolic blood p
ressure increase
10
12
15
Betwe
en Groups
676.5
2
338.24
4.80
0.0087
3.02
11
A
B C
D
E
F G
ANOVA
Source of Vari
ation
SS
df
MS
F
P-value
F crit
1
2
3
A
B C
D
E
Multiple Co
mparisons
LSD Omega
A17.16
t-estimator of µ