Problem 13.1 no solution provided; answers will vary.
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13.2: PROBLEM DEFINITION
Situation: A straw (stagnation tube) and a water-lled, u-tube manometer are used
to measure the speed of an automobile.
Find:
a. sketch the apparatus
b. determine the lowest speed that can be measured.
Assumptions:
The straw will be situated far from the car body. Thus, the free stream velocity
will be measured; not the velocity that is inuenced by the body of the car.
A2mmwatercolumndeection is measurable.
Properties:
Water (20 C), Table A.5, γ=9790N/m3.
Air (20 C), Table A.3, ρ=1.2kg/m.
PLAN
1. To develop a concept design, select materials that are commonly available. Also,
consider a design that can be built quickly and adapted to use in an automobile.
SOLUTION
1. Concept design.
The straw will be positioned outside a window.
2
P
r
oblem 13.3
Deflection (h
)
2. Derivation
Bernoulli equation (point 1 located 10 cm in front of the straw; point 2 at tip
of straw)
Hydrostatic equation (apply to water column)
Combine Eqs. (1) and (2)
REVIEW
Measurements need to be corrected for head winds and tail winds.
A similar device is used in airplanes to measure airspeed.
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13.3: PROBLEM DEFINITION
Situation: A stagnation tube (d= 1 mm) is used to measure air speed.
Find: Velocity such that the measurement error is 2.5%.
Properties:ν=1.46 ×105m2/s.
SOLUTION Algebra using the coecient of pressure gives
Thus
s1
Thus when Cp1.05, there will be a 2.5% error in Vo.
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13.4: PROBLEM DEFINITION
Situation: A stagnation tube (d= 1 mm) is used to measure the speed of water.
Find: Velocity such that the measurement error is 1%.
SOLUTION Algebra using the coecient of pressure gives Vo=p2p/(ρCp).The
allowable error is 1%, thus
This simplies to
Thus when Cp1.02, there will be a 1% error in Vo.
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13.5: PROBLEM DEFINITION
Situation:
Astagnationtube(d=2mm) is used to measure air speed.
Manometer deection is 1 mm-H2O.
Find: Air Velocity: V
Assumptions: Neglect viscous eects
SOLUTION
Bernoulli equation applied to a stagnation tube
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13.6: PROBLEM DEFINITION
Situation:
A stagnation tube (d=2mm) is used to measure air speed
V=24m/s
Find:Deection on a water manometer: h
Assumptions: Neglect viscous eects
Properties: For air, ν=1.4×105m2/s.
SOLUTION
Ideal gas law
Bernoulli equation applied to a stagnation tube
Combine Eqs. (1) and 2)
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13.7: PROBLEM DEFINITION
Situation:
A stagnation tube (d=2mm) is used to measure air speed.
Air kinematic viscosity is 1.55 ×105
Find: Error in velocity if Cp=1is used for the calculation.
Properties: Stagnation pressure is p=5Pa.
PLAN Calculate density of air by applying the ideal gas law. Calculate speed of air
by applying the Bernoulli equation to a stagnation tube. Then calculate Reynolds
number in order to check Cp.
SOLUTION Ideal gas law
Bernoulli equation applied to a stagnation tube
Reynolds number
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13.8: PROBLEM DEFINITION
Situation: A probe for measuring velocity of a stack gas is described in the problem
statement.
Find:Stackgasvelocity:Vo
SOLUTION Pressure coecient
Calculate pressure dierence
Substituting values
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Problem 13.9 no solution provided
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13.10: PROBLEM DEFINITION
Situation:
Velocity of air is measured with an LDV.
λ=4880Å, 2φ=20
o.
On the Doppler burst, 5 peaks occur in 12 μs.
Find: Velocity (m/s).
SOLUTION
1. Fringe spacing
2. Velocity
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13.11: PROBLEM DEFINITION
Situation:
Classify the following devices as to whether they are used to measure velocity (V),
pressure (P), or discharge (Q).
a) hot-wire anemometer
b) venturi meter
c) dierential manometer
d) orice meter
e) stagnation tube
f) rotameter
g) ultrasonic ow meter
h) Bourdon-tube gage
i) weir
j) laser-Doppler anemometer
SOLUTION
The following devices are classied with a V, P or Q to indicated whether they are
used to measure
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Problem 13.12 no solution provided; answers will vary
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13.13: PROBLEM DEFINITION
Situation: In 3 minutes, 8 kN of water ows into a weigh tank.
Find:Discharge(inm3/s).
Properties:Water(20 C), Table A.5, γ=9790N/m3.
SOLUTION
1. Weight per unit time
2. Flow rate
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13.14: PROBLEM DEFINITION
Situation: In 6 minutes, 67 m3of water owsintoaweightank.
Find:Discharge:Qin units of (a) m3/s, (b) gpm and (c) cfs.
SOLUTION
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13.15: PROBLEM DEFINITION
Situation: Velocity data in a 24 inch oil pipe are given in the problem statement.
Find:
(a) Discharge.
(b) Mean velocity.
(c)Ratio of maximum to minimum velocity.
SOLUTION Numerical integration
r(m) V(m/s) 2πV r area (by trapezoidal rule)
08.7 0
0.01 8.6 0.54 0.0027
Summing the values in the last column in the above table gives Q=0.196 m3/s.
Then,
Velocity ratio
This ratio indicates the ow is laminar. The discharge is
13.16: PROBLEM DEFINITION
Situation: Velocity data in a 16 inch circular air duct are given in the problem
statement.
p=14.3psia, T=70 oF
Find:(a)Flowrate:Qin cfs and cfm.
(b) Ratio of maximum to mean velocity.
(c) Whether the ow is laminar or turbulent.
(d) Mass ow rate: ˙m.
PLAN Perform numerical integration to nd ow rate (Q). Apply the ideal gas
law to calculate density. Find mass ow rate using ˙m=ρQ.
SOLUTION Numerical integration
y(in.) r(in.) V(ft/s) 2πrV (ft2/s) area (ft3/s)
0.0 8.0 0 0
0.1 7.9 72 297.8 1.24
0.2 7.8 79 322.6 2.58
Flow rate equation
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Ideal gas law
Flow rate
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13.17: PROBLEM DEFINITION
Situation:Aheatedgasows through a cylindrical stack–additional information is
provided in the problem statement.
Find: (a) The ratio rm/D such that the areas of the ve measuring segments are
equal.
(b) The location of the probe expressed as a ratio of rc/D that corresponds to the
centroid of the segment
(c) Mass ow rate
SOLUTION (a) 1/20 = 0.223 61
b)
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c)Ideal gas law
Bernoulli equation applied to a stagnation tube
Values for each section are
Station hV
1 0.012 7.00
Mass ow rate is given by
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