12-20 Soil Strength Chap. 12
12.40 The rock outcrop shown in Figure 12.42 contains an inclined fracture. The fracture is
inclined at an angle of 26° from the horizontal.
(a) Assuming the effective cohesion along the fracture is zero, compute the lowest
possible value of the effective friction angle along the fracture. Do this
computation by assuming the factor of safety against sliding is equal to 1.0.
Hint: Set the weight of the rock above the fracture equal to W and the area of the
fracture equal to A. Then compute the vector component of W that acts parallel to the
fracture, and determine what
φ′
would be required to resist this force.
(b) If the effective cohesion and friction angle along the fracture are 0 and 38°,
respectively, compute the factor of safety against sliding.
Solution
a.
A
W°
=26cos
‘
σ
b.
12.41 A grain silo, which is a very heavy structure, was recently built on a saturated clay.
Because the harvest season was fairly short and intense, the silo was completely loaded
with grain fairly quickly (i.e., within a couple of weeks). This is the first time the silo has
been loaded. The grain weighs about twice as much as the empty silo. The combined
weight of this grain and the silo has induced both compressive and shear stresses in the
soil below.