Chapter 11 Columns
11-1
11-4 F
11-6 ;
[
11-7 ;
11-8
11-9 ;
11-12
11-13
Johnson Eqn
11-14
11-15
– Tan-1(1/2.4) = 22.6°
1.0
11-16
11-17
11-18
11-20 .
11-22 ;
11-23
11-24 :
11-25
11-26 ]
11-27
11-28 [
11-29
11-30 [ ]
; ;
11-31
11-32 [ ;
;
Prob.
No. L K Le sy E Cc A r SR N Pcr Eqn. Pa
11-33 163.2 in 0.65
106.2 in 36 ksi 29E06 psi 126
1.97 in2 0.751 in 141 3 28 260
Euler 9420 lb
11-34 83.2 in 0.80
66.6 in 36 ksi 29E06 psi 126
1.97 in2 0.751 in 89 3 53 403
Johnson 17 801 lb
l 100×100x4
Member Load L Shape Size Material Pa
AC 1925 lb 40 in Circular 15/16 in ASTM A36 2253 lb
EF 2300 N 0.20 m Square 8 mm Alum. 6061-T6 2324 N
FG 550 N 0.15 m Square 5 mm Alum. 6061-T6 630 N
CF 800 N 0.16 m Square 6 mm Alum. 6061-T6 1149 N
Ay = By = 9000 lb
A = B = 9000 lb/sin 30° = 18 000 lb
Ay
By
B
A
*
**
11-47
0.75
in
150
in
0.80 120
in
50 ksi 29E06 psi 107 2.96
in2
0.841
in
143 3
41 612
lb
-92 180 6.84E+08 8143
lb
11-48
1.25
in
163.2 0.65 106.1
in
36 ksi 29E06 psi 126 1.97
in2
0.751
in
141 3
28 260
lb
-53 938 2.23E+08 4505
lb
11-49
32.0
2650
1.00 2650
248
200 GPa 126 1136
20.4
130 0.82**
133 kN
-816 852 5.56E+10 75.0
–
4.00
800
800
331
207 GPa
314
5.00
3
25.06
–
56 362
5.71
11-53 0.50
40.0
1.00
40.0
50.0
29E06
107 3.37
1.51 in
26.3 3 1.239 1.0703
103
0.035
11-53a 0.50
40.0
1.00
40.0
50.0
29E06
107 5.24
2.85 in
14.0 3 1.038 1.0123
48.4
0.006
11-54 0.90
72 in 1.00
72.0
90.0
30E06
81.1
1.28
0.231
312 1 1.4289 1.4289
8319
0.386
11-54a 0.90
in
72 in 1.00
72.0
in
90.0
ksi
30E06
psi
81.1
1.28
in2
0.231
in
312 3 5.2212 1.4289
84.9
ksi
0.386
in
11-55 0.467
112
1.00
112
36.0
29
E06
126 2.64
0.486
231 3 7.821 1.4864
104
0.2272
Problem
11-56 3.00
in
126
in
0.80
100.8
in
46.0
ksi
29E06
psi
112 6.02
in2
1.41 in
71.5 3 1.2576 1.0749
46.0
ksi
0.225
in
The load for these data is 19 263 lb, found by iterating Equation 11
–
19 using the spreadsheet until the required yield strength became less
than the given 46 000 psi. Specify steel tube; HSS 4×4×1/2; c = 2.00 in.
–
4
0.0
1
0
E06
3
39.1
The load for these data is 675 lb, found by iterating Equation 11
–
21 using the spreadsheet until the required yield strength became less than
Here, buckling about the thickness of the bar is checked assuming that the load is centrally applied. The column analysis spr
eadsheet is used
–
750
750
931
200
314
7.29
3
389
2.41