y
4224
531135
1
x
y
y
Chapter 10
Radical Expressions, Equations, and
Functions
Exercise Set 10.1
The domain is [9,). The answer is (b).
3x
The domain is (−∞,3]. The answer is (g).
6. 9,9
18. 6.528
24. t(x)=2x+1
t(1) does not exist as a real number.
26. F(x)=x2+1
F(0) = 02+1=1=1
28. Solve: 2x+10
30. B=h×w
3600 =165 ×63
3600 1.7m
2
32.
34.
36.
y
x
y
4
224
5
3
1135
5
1
4
3
y
268 Chapter 10: Radical Expressions, Equations, and Functions
38.
40.
42.
44. 25t2=(5t)2=|5t|=5|t|
52. 4
54. 5y
1000 = (10)=10
60. g(x)=3
2x1
62. g(t)= 3
t3
64. 4
256 = 4
76. 1999
(2a+b)1999 =2a+b
82. x2+x=0
84. 2x226x+72=0
2(x4)(x9)=0
88. x3x2=0
x=0or x =1
Exercise Set 10.2
RC2. (b)
RC6. (d)
4)7=2
7= 128
Exercise Set 10.3 269
16. 7
x3y2z2=(x3y2z2)1/7
24. 163/4=1
163/4=1
(4
16)3=1
23=1
8
38. 6a
4
b=6a
b1/4
44. 35/8
31/8=3
6/8=3
3/4
54. (a3/2)2/9=a1/3=1
a1/3
60. 6
t4=t4/6=t2/3=3
t2
62. 4
a12 =a12/4=a3
a10 =a10/5=a2=1
72. 4
16x4y2=4
24x4y2=(2
4x4y2)1/4=2xy1/2=
(116·137)1/42 =42
116·137
78. 3
y5
3y=y1/3(3y)1/5=y5/15(3y)3/15 =
84. a2/3·b3/4=a8/12 ·b9/12 =(a8b9)1/12 =12
a8b9
90. |3x|= 120
The solution set is {−40,40}.
1
94. 10
5
x1555
10
x155
=x3
Exercise Set 10.3
270 Chapter 10: Radical Expressions, Equations, and Functions
4. 18 = 9·2=3
2
14. 4
32 = 4
16 ·2=24
2
16. 75p3q4=25p2q4·3p=5pq23p
24. 232 = 2·32 = 64 = 8
30. 5a715a3=75a10 =25a10 ·3=5a53
40. 30x3y418x2y5=30x3y4·18x2y5=
42. 63
5=6
1/2·51/3=6
3/6·52/6=(6
3·52)1/6=
46. 3
x26
x5=x2/3·x5/6=x3/2=x1+1/2=x·x1/2=xx
52. 4
9ab33a4b=(9ab3)1/4(3a4b)1/2
54. 98
2=98
60. 52ab3
13a=52ab3
13a=4b3=4b2·b=2bb
23=1
64a11b28
64a11b28
x
a7b4,or 15
a7
86. 3
64x7
3
64x6·x
216y6=4x23
x
x
Exercise Set 10.4 271
92. 5
32b10
5
32b10
243a20 =2b2
98. Let h= the height. Then h+ 2 = the length of the base.
100. 4x
x+5+20
x=100
x2+5x
x+5+x(x+5) ·20
x= 100
x·4x+ 20(x+ 5) = 100
4x=0 or x +5=0
102.
3
x3y3
3
xy=3
Exercise Set 10.4
10. 67+ 4
11
18. 3
27 53
8=35·2=310 = 7
24. 3
54x3
2x4=3
27 ·2x3
x3·2x=
32. 4
80x54
405x9+4
5x
34. 9y+27+y+3=9(y+3)+y+3=
38. 26+6
46. 343
63
272 Chapter 10: Radical Expressions, Equations, and Functions
60. (67)(6+7) = 6 7=1
72. (2 x)(1 x)=22xx+x=23x+x
7+ 3
6)(2 3
733
6) =
78. (3
8x3
5y)2=(23
x3
5y)2=
43
x243
5xy +3
25y2
80. a24
a÷a2
a+4 =a24
a·a+4
a2
82. y327
y29·y26y+9
y2+3y+9
=(y3)(y3)
y+3
84. 11
x
=
11
x
·x2
86.
1
a+1
b
=
1
a+1
b
·a3b3
88. |3x+7|<22
90. |3x+7|=|2x5|
3x+7=2x5or 3x+7= (2x5)
5
92. Left to the student
94. (x+2x2)2=(x+2)22x+2x2+(x2)2=
x+22x24+x2=2x2x24
98. 3+2+14
=3+2+1
Chapter 10 Mid-Chapter Review
1. False; negative numbers do not have real-number square
6. 532 318 = 516 ·239·2
f(x) 2
x
y
Chapter 10 Mid-Chapter Review 273
10. 9 does not exist as a real number because negative
11. f(x)=2x+3
12. The domain of f(x)=4xis the set of all x-values for
13. Graph f(x)=2x.
12 (1,2)
14. Graph g(x)=x+1.
x g(x) (x, g(x))
15. 36z2=(6z)2=|6z|=6|z|
27a3=3aSince (3a)3=27a3, then 3
27a3=3a
20. 10
y10 =|y|
24. 3
6m2n=(6m2n)1/3
25. 31/4·35/8=3
33/8
28. (n3/5)5/4=n3/5·5/4=n3/4=1
32. a2/3b3/5=a10/15b9/15 =(a10b9)1/15 =15
a10b9
3
80
80
40 = 3
8·5= 3
83
5=23
5
36. 49a5
b8=49a5
b8=49 ·a4·a
b8=49a4a
b8=7a2a
b4
37. 57+6
7=(5+6)
7=11
7
39. 3(2 53) = 2359=2
35·3=2
315
44. Yes; since x2is nonnegative for any value of x, the nth
45. Formulate an expression containing a radical term with an
46. Since x60 and x20 for any value of x,3
x6=x2.
274 Chapter 10: Radical Expressions, Equations, and Functions
Exercise Set 10.5
2. 8
7=8
7·7
7=56
7=4·14
7=214
7
8. 3
3
3
3
9
14. 1
3
yz =1
3
yz ·
3
y2z2
3
y2z2=
3
y2z2
7c
7c
3
70a2bc
20. 2x
5
18x8y6=2x
5
2·32·x8y6=
5
24·33·x2y4
22. 3
8+5=3
8+5·85
85=24 35
64 5=
24. 52
75=52
75·7+5
7+5=514 510
75=
26. 345
253=345
253·25+3
25+3=
28. 2+ 3
3+5=2+ 3
3+ 5·35
35=2325+ 315
35=
32. 635
327=635
327·3+2
7
3+2
7=
34. 5+x
8x=5+x
8x·8+x
8+x=
38. 72+4
3
3
2
2=
ab +b
42. 5
x1+9
x2+x+1 =15
x31,
LCM is (x1)(x2+x+1)
x=19
5or x=1
Only 19
=(2x+3)(x2)
46. a) x5=(
x+5)(x5)
x+a)(xa)
Exercise Set 10.6 275
48. 1
4+3+1
3+1
34=
133·3
3=73
39
Exercise Set 10.6
RC4. A radical equation has a variable in one or more
radicands.
This value checks.
4. 3x4=6
This value checks.
6. x13=9
8. 2y+9=5
This value checks.
10. 3
y=2
y=8
12. y3=2
14. 3
x2=3
x2=27
18. 3
3y+6+2= 3
3y+6=1
3y=5
20. 3= 1
y
22. x5=x+7
x210x+25 =x+7
24. 2x+72=x
2x+7= x+2
26. x1=x+5
x=4 or x =1
Only 4 checks. It is the solution.
28. x1=1x
x2x=0
276 Chapter 10: Radical Expressions, Equations, and Functions
30. 5x3=2x+3
32. x9+x=1
5=x
34. 4x3=2+2x5
2x5+2x5
x210x+21=0
36. 4+10 x=6+4x
1=164x
This value checks.
38. y+152y+7=1
y+7=2
2y+7
40. 6x+73x+3=1
9x2+6x3=0
42. 2m3=m+72
m228m+ 196 = 16m+ 112
44. 32y+3y+10=0
17y=17
48. 13=1.2h
50. 230 = 1.2h
230
52. At 65 mph: 65 = 25L
32.5=5L
Exercise Set 10.6 277
54. 1113 = 21.95t+ 2457
The temperature was approximately 25F.
56. 2 = 2(3.14)L
32
58. 3.1 = 2(3.14)L
32
9.61 = 39.4384 ·L
32
60. Let t= the time it takes Jeff to do the job. Then 3t=
62. Let h= the number of hours Dharma would have to work
in order to earn $1044.96.
64. 3x25x=0
2x2x21=0
68. f(a+h)f(a)
70. f(a+h)f(a)
72. We can graph y1=2x+1+
5x4 and y2=10x+9.
The first coordinate(s) of the point(s) of intersection are
the solution(s) of the equation. There is one point of in-
tersection, (4,7), so the solution is 4.
x=4or x =3
The numbers 4 and 3 check and are the solutions.
76. 6y+6y1/2=37
6y+6=37
y
36 or y =36
The numbers 1
5x=x
80. x+12
x+1 =1
x23x=0
278 Chapter 10: Radical Expressions, Equations, and Functions
82. 2x13x5=x9
23x28x+5=3x
84. Let y=7+4
3743.
Exercise Set 10.7
2. c2=8
2+10
2
4. c2=8
2+8
2
6. 52+b2=12
2
8. (45)2+b2=10
2
10. 12+b2=(
12)2
12. (n)2+b2=2
2
16. Solve d2=65
2+65
2.
w=6,980,904 ft
ADC
30 ft
h=400
PSR
40 ft
h2= 225
Exercise Set 10.8 279
22.
y
(0,y)
q
(3,0)
The points are (0,4) and (0,4).
24.
d2= 4900 + 8100
28. Let s= the length of a side of the square.
30. h2=s2+s2
h2=2s2
h=s2
32. Let r= the speed of the current. Then 3r= the speed of
34. x2+24=11x
36. 3x212=0
3(x24)=0
38. x1
x3=6
x3,LCM is x3
40. a) Tw=35.74+0.6215(40) 35.75(25)0.16+
0.4275(40)(25)0.16
29F
c) Tw=35.74+0.6215(10) 35.75(20)0.16+
d) Tw=35.74+0.6215(10) 35.75(40)0.16+
f) Tw=35.74+0.6215(15) 35.75(35)0.16+
Exercise Set 10.8
RC2. True; see page 753 in the text.
6. 20 = 1·4·5=2i5, or 25i
280 Chapter 10: Radical Expressions, Equations, and Functions
18. 76 + 125 = 1·4·19 + 1·25 ·5=
32. 16 ·64 = 4i·8i=32i2=32
50. (6+2i)2=36+24i+4i2=32+24i
60. (i)71 =(1)71(i)71 =1·i70 ·i=(i2)35 ·i=(1)35 ·
68. i29 +33i=i28 ·i+33i=(i2)14 ·i+33i=
(1)14 ·i+33i=i+33i=34i
70. 5i5+4i3=5·i4·i+4·i2·i=5·(i2)2·i+4·(1) ·i=
88. 8i
96. x22x+5= 0
(1+2i)22(1+2i)+5 ? 0
98. x2+2x+2 =0
100. x-intercept: 4 ·03x=72
3x=72