b. For what sequence of amino acids does this mRNA code? (Assume it does not
contain introns.)
c. The chart lists five point mutations that may occur in the original strand of DNA.
What happens to the amino acid sequence or protein produced as a result of each
mutation? (Note: Position 1 refers to the first base at the 3⬘end of the transcribed
strand. The last base in the DNA strand, at the 5⬘end, is at position 21.)
Original template strand: 3⬘TAC GCA AGC AAT ACC GAC GAA 5⬘
Mutation Effect on amino acid sequence
i. Substitution of T for G at
position 8.
This changes the codon in mRNA to a stop
codon; translation stops at this point. A
shorter (truncated) polypeptide is pro-
duced and this shortened polypeptide is
likely to be nonfunctional.
iv. Substitution of T for C at
position 18.
The original mRNA codon, CUG, and the
one resulting from the substitution, CUA,
both code for leucine, so no change occurs
in the polypeptide sequence.
vi. Which of the mutations produces the greatest change in the amino acid
sequence of the polypeptide coded for by this 21-base-pair gene?
The addition of T between positions 8 and 9 still leaves the third amino
120 Activity 17.1