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46. a. The computer output with the missing values filled in is as follows:
= 8.103 + 7.602 X1 + 3.111 X2
b. The p-value (2 degrees of freedom numerator and 12 denominator) corresponding to F = 71.82 is
.0000
Because the p-value ≤ α = .05, there is a significant relationship.
47. a. The regression equation is
b. F = 52.3053
p-value (2 degrees of freedom numerator and 7 degrees of freedom denominator) = .0000
Because the p-value ≤ α = .05, there is a significant relationship.
For
: the p-value corresponding to t = 4.5125 is .0028
Because the p-value is ≤ α = .05, reject H0:
= 0
48. a. The regression equation is
= 14.4 – 8.69 X1 + 13.517 X2
b. The p-value (5 degrees of freedom) corresponding to F = 22.7916 is .0031
Because the p-value is ≤ α = .05, there is a significant relationship.
c.
49. a. A portion of the Excel output follows:
Because the p-value = .000 < α = .05, there is a significant relationship.
b. The estimated regression equation provided a good fit; 84.3 % of the variability in the Buy Again
rating was explained by the linear effect of the Steering rating.
c. A portion of the Excel output follows:
The estimated regression equation is
= – 5.3877 + 0.6899 Steering + 0.9113 Treadwear
d. For the Treadwear independent variable, the p-value = .0005 < α = .05; thus, the addition of
Treadwear is significant.
50. a. A portion of the Regression tool output follows.
= 41.0534 ˗ 3.7232 Displacement
Because the p–value corresponding to F = 550.8029 is .0000 <
= .05, there is a significant
relationship.
b. A portion of the Excel Regression tool output follows.
c. For FuelPremium, the p-value corresponding to t = -6.4498 is .000 < = .05; significant. The
addition of the dummy variables is significant.
d. A portion of the Excel Regression tool output follows.
The estimated regression equation is
= 4.9090+ 10.4658 FundDE + 21.6823 FundIE
Since the p-value corresponding to F = 33.4584 is .0000 < α = .05, there is a significant relationship.
c. A portion of the Excel output follows:
Since the p-value corresponding to F = 19.5558 is .0000 < α = .05, there is a significant relationship.
For Net Asset Value ($), the p-value corresponding to t = .3950 is .6950 > = .05, Net Asset Value
($) is not significant and can be deleted from the model.
d. Morningstar Rank is a categorical variable. The data set only contains funds with four ranks (2-Star
The estimated regression equation is
= -4.6074 + 8.1713 FundDE + 19.5194 FundIE +5.5197 Expense Ratio (%) + 5.9237 3StarRank
+ 8.2367 4StarRank + 6.6241 5StarRank
At the .05 level of significance, all the independent variables are significant.
= ˗407.9703 + 4.9612 FG% + 2.3749 3P% + 0.0049 FT% + 3.4612 RBOff +
3.6853 RBDef
d. For the estimated regression equation developed in part (c), the percentage of free throws made
removing this independent variable, the Excel output is shown below:
= –407.5790 + 4.9621 FG% + 2.3736 3P%+ 3.4579 RBOff + 3.6859 RBDef
e.
= –407.5790 + 4.9621 FG% + 2.3736(35) + 3.4579(12) + 3.6859(30) = 50.86%