Chapter 10: Economic Growth and Business Cycles 111
make the capital stock increase at the same rate as population growth. The
second amount (the depreciation rate) represents the amount of investment
needed to replace machinery and equipment that has worn out.
For investment to occur, however, people must save. We will make the
same assumption that Solow did, namely, that savings per person (s) is a
constant fraction (v) of output per person. That is,
s = v × y. (13)
In this equation, v is the fraction of income that people save, and we
assume it is constant over time.
(14)
So, for savings to equal investment, output per person must equal a
constant times the amount of capital per person. Equations (11) and
(14) now give us two equations relating y and k, which we can use to solve
for their values.
In this model, the equilibrium values of y and k depend on the growth rate
of labor ( g ), the depreciation rate ( d ), and the savings rate ( v ). A higher
value of g or d, or a lower value of v , would mean that the right-hand side
of equation (14) would be higher for any given value of k .
There is some good intuition for these results. Consider two economies that
are identical in every way, except that one has greater population growth
than the other. With greater population growth, it takes more savings to
maintain a given ratio of capital to labor. Because savings is a .xed
proportion of output, an economy with greater population growth would
have a lower ratio of capital to labor, and hence a lower ratio of output to
labor. Similarly, an economy in which capital depreciates faster will also
have lower k and y in equilibrium.
On the other hand, an economy that has a higher savings rate out of
income will invest more, and in equilibrium will have a higher ratio of capital
to labor and output to labor.