18. We can use the equation for the NPV we constructed in Problem 17. Using the sales figure of 3,310
units and solving for P, we get:
NPV = 0 = –[($81)(3,280) – ($47)(3,310 – 3,280)] + [(P – 47)(3,310) – ($81 – 47)(3,280)]/.023
0 = –$265,680 – 1,410 + $143,913.04P – 6,763,913.04 – 4,848,695.65
$143,913.04P = $11,879,698.70
P = $82.55
19. From Problem 15, the incremental cash flow from the new credit policy will be:
Incremental cash flow = Q(P – v) – Q(P – v)
And the cost of the new policy is:
Cost of new policy = –[PQ + Q(v – v) + v(Q – Q)]
Setting the NPV equal to zero and solving for P, we get:
NPV = 0 = –[($131)(1,320) + ($98 – 96)(1,320) + ($98)(1,340 – 1,320)] + [(1,340)(P – 98) –
(1,320)($131 – 96)]/.0085
0 = –[$172,920 + 2,640 + 1,960] + $157,647.06P – 15,449,411.76 – 5,435,294.12
$157,647.06P = $21,062,225.88
P = $133.60
20. Since the company sells 700 suits per week, and there are 52 weeks per year, the total number of
suits sold is:
Total suits sold = 700 × 52
Total units sold = 36,400
And, the EOQ is 500 suits, so the number of orders per year is:
Orders per year = 36,400/500
Orders per year = 72.80
To determine the day when the next order is placed, we need to determine when the last order was
placed. Since the suits arrived on Monday and there is a three-day delay from the time the order was
placed until the suits arrive, the last order was placed Friday. Since there are approximately five days
between the orders, the next order will be placed on Wednesday
Alternatively, we could consider that the store sells 100 suits per day (700 per week/7 days). This
implies that the store will be at the safety stock of 100 suits on Saturday when it opens. Since the
suits must arrive before the store opens on Saturday, they should be ordered three days prior to
account for the delivery time, which again means the suits should be ordered on Wednesday.