Chapter 10 – Pure Competition in the Short Run
10–10
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Answers: The student should end up constructing a table similar to the following.
The farmer should plant and harvest four acres.
Feedback: Consider the following example. A purely competitive wheat farmer can sell
any wheat he grows for $10 per bushel. His five acres of land show diminishing returns
because some are better suited for wheat production than others. The first acre can
produce 1,000 bushels of wheat, the second acre 900, the third 800, and so on. Also
assume the marginal cost of planting and harvesting an acre is $7,000 per acre for each of
the five acres.
Table:
The first step is to calculate the revenue generated by each acre (column 3). Each entry,
the acre’s revenue, is found by multiplying the price per bushel by the acre’s yield. The
revenue generated by the first acre is $10,000 (=$10 x 1,000), the second acre $9,000
(=$10 x 900), the third acre $8,000 (=$10 x 800), etc…
The next step is to calculate total revenue (column 4). Total revenue equals the sum of
revenue generated by each successive acre being cultivated. Total revenue for the first
acre is $10,000, total revenue for first and second acre is $19,000 (=$10,000 + $9,000),
total revenue for the first, second, and third acre is $27,000 (= $10,000 +$ 9,000 +
$8,000), etc…
The final step is to calculate marginal revenue (column 5). Marginal revenue equals the
change in total revenue as each successive acre is cultivated. Marginal revenue for the
first unit is $10,000 because as we move from cultivating zero acres to one acre out total
revenue changes by $10,000. The marginal revenue for the second acre equals $9,000,
which is the total revenue of the second acre minus the revenue generated by the first acre
(=$19,000 – $10,000). etc…
Using our MC=MR rule, the farmer should plant and harvest 4 acres. Marginal revenue
for the fourth acre equals $7,000 and the marginal cost equals $7,000.