470
Ans.
SOLUTION
Method of Superposition: Using the method of superposition
as discussed in Chapter 4, the required displacements are
C=
PL
48EI
=
CD
3
=0.002613FCD T
Using the axial force formula,
F=
AE
=
CD
p
(0.752)(29)(103)
=0.003903FCD
The thermal contraction is
a
∆TL =6.5(10 –6)(150)(50) =0.04875 in.T
The compatibility condition requires
0.002613FCD =0.04875 +(–0.003903FCD)
Ans.
9–42. The beam AB has a moment of inertia of
and rests on the smooth supports at its ends. A 0.75-in.-diameter
rod CD is welded to the center of the beam and to the fixed
support at D. If the temperature of the rod is decreased by
150°F, determine the force developed in the rod. The beam and
rod are both made of steel for which
and
50 in.
C
D