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399
*8–40. Use the method of virtual work and determine the
slope at point A of the beam made from steel.
E=29(103)
ksi,
I=245
in4.
5 ft
8 k
5 ft
AB
8 k
5 ft 5 ft
C
3
Ans.
SOLUTION
0M
dx
3
5 ft
8 k
5 ft
AB
8 k
5 ft 5 ft
C
8–41. Solve Prob. 8–40 using Castigliano’s theorem.
401
8–42. Determine the displacement at point D. Use the
principle of virtual work. EI is constant.
2 m2
m
30 kN>m
B
AC
D
SOLUTION
The virtual and real moment functions shown in Figs. a and b,
respectively.
kN #∆D=
L
mM
dx =2
2 m
2 x1
(30x1)dx1
+
3 m
–
2 x2
[–(15x2
2+30x2)] dx2
kN
∆D=
∆D=
T Ans.
Ans.
SOLUTION
2 m2
m
30 kN>m
B
AC
D
8–43. Determine the displacement at point D. Use Castigliano’s
theorem. EI is constant.
Ans.
*8–44. Determine the horizontal displacement at A. Take
The moment of inertia of each segment of the
frame is indicated in the figure. Assume D is a pin support. Use
the method of virtual work. C
B
AD
mIAB 5 200(106) mm4
IBC 5 300(106) mm4
ICD 5 200(106) mm4
6 m
SOLUTION
Referring to the virtual and moment functions shown in Figs. a and b,
SOLUTION
1
C
B
AD
mIAB 5 200(106) mm4
IBC 5 300(106) mm4
ICD 5 200(106) mm4
6 m
8–45. Solve Prob. 8–44 using Castigliano’s theorem.
405
8–46. The L-shaped frame is made from two fixed-connected
segments. Determine the vertical displacement of the end C.
Use the method of virtual work. EI is constant.
B
A
12 ft
9 ft
2 k
>
ft
SOLUTION
Referring to the virtual and real moment functions shown in
Figs. a and b, respectively,
k #(∆C)y=
L
mM
dx =
9 ft
(–x1)
–
1
27
dx1
+
12 ft
(–9)(–27)dx2
k
(∆C)y=
∆C)y=
T Ans.
Ans.
∆C)y=
T
SOLUTION
Referring to the virtual and real moment functions shown in
Figs. a and b, respectively,
L
9 ft
(–1)
–
1
dx1
12 ft
8–47. The L-shaped frame is made from two fixed-connected
segments. Determine the slope at point C. Use the method of
virtual work. EI is constant.
B
A
12 ft
9 ft
2 k
>
ft
407
B
A
12 ft
9 ft
2 k
>
ft
*8–48. Solve Prob. 8–46 using Castigliano’s theorem.
SOLUTION
1
SOLUTION
1#∆=
mM
d
1
2)dx1+
640 000 lb
ft
8–49 Use the method of virtual work and determine the
horizontal and vertical displacements of point C. There is a
fixed support at A and fixed joint at B. EI is constant.
A
8 ft
B
A
8 ft
10 ft
B
8–50 Solve Prob. 8–49 using Castigliano’s theorem.
Ans.
SOLUTION
1
=0
2
=10 –x
Setting
,
Ch
=
M
0M
dx
=
1
(200x1
2)(0)dx1+
12 800(10 –x2)dx2
=
640 000 lb
ft
Ans.
1
=x1
2
=
Setting
,
Cv
=
M
0M
dx
=
1
(200x1
2)(x1)dx1+
(12 800)(8)dx2
=
1 228 000 lb
ft
Ans.
1 228 000 lb #ft3