Instructor’s Solution Manual 23
1.564 m is read on point X, calculate the HI and the elevation of point X.
4.30 Similar to Problem 4.28, except a plus sight of 8.98 ft is taken on BM A, elevation
606.33 ft, and a minus sight of 4.32 ft read on point X.
4.31 Describe the procedure used to test if the level vial is perpendicular to the vertical axis
4.32 A horizontal collimation test is performed on an automatic level following the
procedures described in Section 4.15.5. With the instrument setup at point 1, the rod
reading at A was 5.548 ft, and to B it was 5.126 ft. After moving and leveling the
instrument at point 2, the rod reading to A was 5.540 ft and to B was 5.126 ft. What is
the collimation error of the instrument and the corrected reading to A from point 2?
4.33 The instrument tested in Problem 4.32 was used in a survey immediately before the test
where the observed elevation difference between two benchmarks was +44.65 ft. The
sum of the plus sight distances between the benchmarks was 250 ft and the sum of the
minus sight distances was 490 ft. What is the corrected elevation difference between the
two benchmarks?
point 2. The distance between the points in the test was 100 m.
1.923 1.894 1.100 1.083 0.006 m
2
Correct reading at A = 1.083 – 2(0.006) = 1.071 m
4.35 The instrument tested in Problem 4.34 was used in a survey immediately before the test
where the observed elevation difference between two benchmarks was −13.068 m. The
sum of the plus sight distances between the benchmarks was 1540 m and the sum of the
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