Column → (1) (2) (3) (4) (5) (6)
0.40 0.04 0.360 0.1296 0.100 0.012960
0.10 0.04 0.060 0.0036 0.200 0.000720
0.00 0.04 -0.040 0.0016 0.400 0.000640
-0.05 0.04 -0.090 0.0081 0.200 0.001620
-0.10 0.04 -0.140 0.0196 0.100 0.001960
√ (Sum) = Standard Deviation (σ) =
Asset G
Column → (1) (2) (3) (4) (5) (6)
0.35 0.11 0.240 0.0576 0.400 0.023040
0.10 0.11 -0.010 0.0001 0.300 0.000030
-0.20 0.11 -0.310 0.0961 0.300 0.028830
√ (Sum) = Standard Deviation (σ) =
Asset H
Column → (1) (2) (3) (4) (5) (6)
0.40 0.10 0.300 0.0900 0.100 0.009000
0.20 0.10 0.100 0.0100 0.200 0.002000
0.10 0.10 0.000 0.0000 0.400 0.000000
0.00 0.10 -0.100 0.0100 0.200 0.002000
-0.20 0.10 -0.300 0.0900 0.100 0.009000
√ (Sum) = Standard Deviation (σ) =
Based on standard deviation, Asset G appears to have the greatest risk.
c. Coefficient of variation (CV) is given by σ , where so σ is the standard deviation of returns on
the asset and is the average return. So:
Asset F: CV = 0.1338 0.04 = 3.345 Asset H: CV = 0.1483
0.10 = 1.483
Asset G: CV = 0.2278 2.071
As measured by the coefficient of variation, Asset F has the largest relative risk.
P8-12 Normal probability distribution (LG 2; Challenge)
a. Coefficient of variation: CV = σ , where so σ is the standard deviation of returns on the asset
and is the expected return. So, given the CV (0.75) and the expected return (0.189), solve for
standard deviation: 0.75
0.189 →
0.750.189 0.14175