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6–33.
SOLUTION
a
Ans.
a
Ans.
Joint C:
Ans.+c©Fy=0; FGC =0
FCD =6.67 kN (T)
+©MG=0; 9.5(4) -2(4) -5(2) -FCD(3) =0
FGF =12.5 kN (C)
+©MD=0; -4
5FGF (1.5) -2(2) +9.5(2) =0
The Howe truss is subjected to the loading shown.
Determine the force in members GF,CD, and GC, and
state if the members are in tension or compression.
3 m
2 kN
5 kN
5 kN
A
BCD
F
G
H
E
2 kN
5 kN
6–34.
The Howe truss is subjected to the loading shown.
Determine the force in members GH,BC, and BG of the
truss and state if the members are in tension or compression.
Ans.
a
Ans.
a
Ans.FBC =6.67 kN (T)
+©MH=0; -7.5(4) +5(2) +FBC(3) =0
FBG =6.01 kN (T)
+©MA=0; -5 (2) +FBG sin 56.31°(2) =0
FGH =12.5 kN (C)
3 m
2 kN
5 kN
5 kN
A
F
G
H
E
2 kN
5 kN
6–35.
Determine the force in members EF, CF, and BC, and state
if the members are in tension or compression.
1.5 m
2 m
F
8 kN
4 kN ED
C
Support Reactions. Not required.
Method of Sections.
FBC
and
FEF
can be determined directly by writing the moment
*6–36.
Determine the force in members AF, BF, and BC, and state
if the members are in tension or compression.
1.5 m
2 m
F
8 kN
4 kN ED
C
6–37.
Determine the force in members EF, BE, BC and BF of the
truss and state if these members are in tension or
compression. Set P1 = 9 kN, P2 = 12 kN, and P3 = 6 kN.
FE
B
AD
C
3 m
3 m 3 m3 m
P1P2
P3
SOLUTION
6–38.
Determine the force in members BC, BE, and EF
of the truss and state if these members are in tension
or compression. Set P1 = 6 kN, P2 = 9 kN, and P3 = 12 kN.
F
E
B
AD
C
3
m
3 m 3 m3 m
P1P2
P3
6–39.
SOLUTION
Determine the force in members BC, HC, and HG. After
the truss is sectioned use a single equation of equilibrium
for the calculation of each force. State if these members are
in tension or compression.
ACD
H
G
F
4 kN
3 m
2 m
5 m5 m5 m 5 m
BE
4 kN
5 kN
3 kN
2 kN
*6–40.
SOLUTION
+ΣFx=0; Ex=0
Determine the force in members CD, CF, and CG and state
if these members are in tension or compression.
ACD
H
G
F
4 kN
3 m
2 m
5 m5 m5 m 5 m
BE
4 kN
5 kN
3 kN
2 kN
6–41.
Determine the force developed in members FE, EB, and
BC of the truss and state if these members are in tension or
compression.
11 kN
B
AD
C
FE
22 kN
2 m 1.5 m
2 m
2 m
SOLUTION
6–42.
Determine the force in members BC, HC, and HG. State if
these members are in tension or compression.
6 kN
12 kN
9 kN
4 kN 6 kN
1.5 m 1.5 m
2 m
1
m1
m
1.5 m 1.5 m
A E
B
H
G
J
CD
SOLUTION
6–43.
Determine the force in members CD, CJ, GJ, and CG and
state if these members are in tension or compression.
6 kN
12 kN
9 kN
4 kN 6 kN
1.5 m 1.5 m
2 m
1
m1
m
1.5 m 1.5 m
A E
B
H
G
J
CD
SOLUTION
*6–44.
Determine the force in members BE, EF,and CB,and state
if the members are in tension or compression.
Ans.
a
Ans.
a
Ans.FEF =25 kN (C)
+©MB=0; -5 (8) -10 (4) -5 (4) +FEF (4) =0
FCB =5 kN (T)
+©ME=0;
-5 (4) +FCB (4) =0
FBE =21.2 kN (T)
:
4m
4m
4m
4m
A
C
G
E
D
10 kN
5kN
5kN
6–45.
Determ
i
ne t
h
e force
i
n mem
b
ers BF,BG,an
d
AB,an
d
state
if the members are in tension or compression.
SOLUTION
Ans.
Section:
Ans.
a
Ans.FAB =45 kN (T)
+©MG=0; FAB (4) -10 (4) -10 (8) -5 (12) =0
FBG =35.4 kN (C)
:
+©Fx=0; 5 +10 +10 -FBG cos 45° =0
:
4m
4m
4m
B
A
C
F
G
E
D
10 kN
5kN
5kN
6–46.
Determine the force in members BC, CH, GH, and CG of
the truss and state if the members are in tension or
compression.
A
CD
H
G
F
8 kN
3 m
2 m
4 m4 m
4 m 4 m
B
E
4 kN 5 kN
SOLUTION
SOLUTION
6–47.
Determine the force in members CD, CJ, and KJ and state
if these members are in tension or compression.
6 kN
A
BCDE
G
I
H
F
12 m, 6 @ 2 m
J
K
L
6 kN
6 kN
6 kN
6 kN
3 m
*6–48.
Determine the force in members JK,CJ,and CD of the truss,
and state if the members are in tension or compression.
SOLUTION
a
Method of Sections: Using the left portion of the free - body diagram, Fig. a.
a
Ans.
a
Ans.
Ans.FCJ =1.602 kN =1.60 kN (C)
+c©Fy=0; 10.33 -4-5-FCJ sin 56.31° =0
FCD =12 kN (T)
+©MJ=0; FCD(3) +5(2) +4(4) -10.33(6) =0
FJK =11.111 kN =11.1 kN (C)
+©MC=0; FJK(3) +4(2) -10.33(4) =0
Ay=10.33 kN
+©MG=0 6(2) +8(4) +5(8) +4(10) -Ay(12) =0
:
A
BCDF
E
G
H
I
J
L
K
6kN
8kN
5kN
4kN
3m
2m 2m 2 m2 m2 m2 m
6–49.
SOLUTION
Method of Sections: Using the right portion of the free - body diagram, Fig. b.
a
Ans.
a
Ans.
a
Ans.FHI =21.11 kN =21.1 kN (C)
+©MF=0; 12.67(2) -FHI a3
5b(2) =0
FFI =7.211 kN =7.21 kN (T)
+©MG=0; -FFI sin 56.31°(2) +6(2) =0
FEF =12.89 kN =12.9 kN (T)
+©MI=0; 12.67(4) -6(2) -FEF(3) =0
NG=12.67 kN
Determine the force in members HI,FI, and EF of the truss,
and state if the members are in tension or compression.
A
BCDF
E
G
H
I
J
L
K
6kN
8kN
5kN
4kN
3m
2m 2m 2 m2 m2 m2 m
SOLUTION
*6–52.
Determine the force in each member of the space truss and
state if the members are in tension or compression. The truss
is supported by ball-and-socket joints at A, B, C, and D.
G
A
6 kN
4 kN
B
C
z
D2 m
4 m
2 m
