978-0133915426 Chapter 6 Part 2

subject Type Homework Help
subject Pages 14
subject Words 3623
subject Authors Russell C. Hibbeler

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page-pf1
6–17.
If the maximum force that any member can support is 8 kN
in tension and 6 kN in compression, determine the
maximum force Pthat can be supported at joint D.
SOLUTION
Method of Joints: In this case, the support reactions are not required for
determining the member forces.
Joint D:
+©F
F
DC
sin 60° -P=0F
DC
=1.1547P1T2+c©F
y
=0;
60°
60°
4m 4m
B
ED
C
A
4m
P
page-pf2
502
SOLUTION
6–18.
Determine the force in each member of the truss and state
if the members are in tension or compression. Set
P1 = 10 kN, P2 = 8 kN.
1 m 1 m2 m
2 m
A
FE
G
BCD
P1P2
page-pf3
6–18. Continued
page-pf4
504
6–19.
Determine the force in each member of the truss and state
if the members are in tension or compression. Set P1 = 8 kN,
P2 = 12 kN.
1 m 1 m2 m
2 m
A
FE
G
BCD
P1P2
page-pf5
6–19. Continued
page-pf6
506
*6–20.
Determine the force in each member of the truss and state
if the members are in tension or compression. Set P1 = 9 kN,
P2 = 15 kN.
3 m
A
BC
D
FE
3 m
4 m
P1
SOLUTION
page-pf7
*6–20. Continued
page-pf8
508
6–21.
Determine the force in each member of the truss and state
if the members are in tension or compression. Set P1 =
30 kN, P2 = 15 kN.
SOLUTION
3 m
A
BC
D
FE
3 m
4 m
P1
page-pf9
5
5
page-pfa
6–22.
3b+Pa2L
3b-(D
D
etermine the force in each member of the double scissors
t
russ in terms of the load P and state if the members are in
t
ension or compression.
BC
L/3
page-pfb
6–23.
Determine the force in each member of the truss in terms
of the load Pand state if the members are in tension or
compression.
SOLUTION
D
E
d
page-pfc
*6–24.
The maximum allowable tensile force in the members of the
truss is and the maximum allowable
compressive force is Determine the
maximum magnitude of the load Pthat can be applied to
the truss.Take d=2m.
1F
c2max =3 kN.
1F
t2max =5 kN,
SOLUTION
AC
D
E
d
d/2
Support reactions:
a
ME=0;
Axa3
2db-Pd =0Ax=0.6667P
page-pfd
6–25.
Determine the force in each member of the truss in terms of
the external loading and state if the members are in tension
or compression. Take P = 2 kN.
AB
C
D2 m
2 m
2 m
2 m
PP
30fi
page-pfe
6–26.
The maximum allowable tensile force in the members of the
truss is
(Ft)max =5 kN,
and the maximum allowable
compressive force is
(Fc)max =3 kN.
Determine the
maximum magnitude P of the two loads that can be applied
to the truss.
A
B
C
D2 m
2 m
2 m
2 m
PP
30fi
SOLUTION
page-pff
6–27.
Determine the force in members DC,HC, and HI of the
truss, and state if the members are in tension or
compression.
SOLUTION
C
G
ED
H
F
I
B
2m 2m 2 m
1.5 m
50 kN
40 kN
40 kN
30 kN
1.5 m
page-pf10
*6–28.
SOLUTION
Determine the force in members ED,EH,and GH of the
truss,and state if the members are in tension or compression.
C
G
ED
H
F
B
2m 2m 2 m
1.5 m
50 kN
40 kN
40 kN
30 kN
1.5 m
page-pf11
6–29.
Determine the force in members HG,HE,and DE of the
truss,and state if the members are in tension or compression.
SOLUTION
A
BC D EF
GHIJ
K
4 ft
3 ft 3 ft3 ft3 ft3 ft
page-pf12
6–30.
Determine the force in members CD,HI,and CJ of the truss,
and state if the members are in tension or compression.
SOLUTION
A
BCDEF
GHIJ
K
4 ft
3 ft 3 ft3 ft3 ft3 ft
page-pf13
6–31.
Determine the force in members CD,CJ, KJ,and DJof the
t
russ which serves to support the deck of a bridge. State if
t
hese members are in tension or compression.
SOLUTION
a
Ans.
a
Ans.
Ans.
Joint D:Ans.F
DJ
=0
F
CJ
=3125 lb =3.12 kip (C)
:
+©F
x
=0;-9375 +11 250 -3
5F
CJ
=0
F
CD
=9375 lb =9.38 kip (C)
M
J
=0;-9500(27) +4000(18) +8000(9) +F
CD
(12) =0
F
KJ
=11 250 lb =11.2 kip (T)
M
C
=0;-9500(18) +4000(9) +F
KJ
(12) =0
AG
HIJKL
FEDCB
4000 lb
8000 lb 5000 lb
9ft9ft9ft9ft9ft9ft
12 ft
page-pf14
*6–32.
Determine the force in members EI and JI of the truss
w
hich serves to support the deck of a bridge. State if these
m
embers are in tension or compression.
SOLUTION
a
Ans.
Ans.F
EI
=2500 lb =2.50 kip (C)
+c©F
y
=0; 7500 -5000 -F
EI
=0
F
JI
=7500 lb =7.50 kip (T)
M
E
=0;
-5000(9) +7500(18) -F
JI
(12) =0
AG
HIJKL
FEDCB
4000 lb
8000 lb 5000 lb
9ft9ft9ft9ft9ft9ft
12 ft

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