350.
(4) In long-run equilibrium, Y 1400 and r 0.08, so L 1750 0.75Y 8750(r e)
1750 (0.75 1400) [8750 (0.08 0.02)] 1925. Since M/P = L 1925, we have M
1925 P. To attain P 6 in long-run equilibrium with I 320 and G 350, the nominal
4. (a) The IS curve is given by Y Cd Id G 300 0.5(Y 100) 300r 100 100r 100 450
0.5Y 400r. This can be rewritten as 0.5Y 450 400r, or Y 900 800r. The LM curve is
2Y (25,200/P). Then substitute this in the IS curve: Y 900 800r 900 [2Y (25,200/P)].
This can be rewritten as 3Y 900 (25,200/P), or Y 300 (8400/P).
0.25. The LM curve then is 6300/P (0.5 700) (200 0.25) 300, which has the solution P
21. Consumption is C 300 0.5(700 100) (300 0.25) 525. Investment is I 100
5. (a) Setting w MPN,
This is the labor demand curve.
or 2
P.
(c) Y 20
10P, or P (1/10) Y, as shown in Figure 11.14 by the SRAS curve.
Figure 11.14
(d) The IS curve is Y 120 500r. The LM curve is M/P 0.5Y 500r, which can be rewritten as
500r 0.5Y (M/P). Plugging the LM curve into the IS curve to eliminate r gives Y 120
500r 120 [0.5Y (M/P)]. This can be rewritten as 1.5Y 120 (M/P). This is the AD curve.
With M 300, the AD curve is 1.5Y 120 (300/P), or Y 80 (200/P). The AD curve is
shown in Figure 11.14.
(e) To find the intersection of the SRAS curve (Y 10P) and the AD curve [Y 80 (200/P)], find
the price level such that 10P 80 (200/P). This can be rewritten as 10P2 80P 200 0, or