978-0128012420 Chapter 2 Part 1

Solution Manual, Chapter 2, Elements of Engineering Analysis, Exploring Engineering, Kosky, Balmer,

Keat & Wise.

Solution Manual Chapter 2: Elements of

Engineering Analysis

1. Sketch the isometric plate below and add the following dimensions: Height = 5 cm,

Length = 40 cm, Width = 20 cm. The diameter of the hole is 10 cm and it is centered 15

cm from the front.

Solution Manual, Chapter 2, Elements of Engineering Analysis, Exploring Engineering, Kosky, Balmer,

Keat & Wise.

2. Sketch and complete the orthographic drawing below.

Solution Manual, Chapter 2, Elements of Engineering Analysis, Exploring Engineering, Kosky, Balmer,

Keat & Wise.

4. If a gallon has a volume of 0.134 ft3 and a human mouth has a volume of 0.900 in3

then how many mouthfuls of water are required to fill a 5.00 (US) gallon can?

Solution Manual, Chapter 2, Elements of Engineering Analysis, Exploring Engineering, Kosky, Balmer,

Keat & Wise.

5. Identify whether you would perform the following unit conversions by definition, by

conversion factors, by geometry, or by scientific law:

a) How many square miles in a square kilometer?

b) How many microfarads in a farad?

c) What is the weight on Earth in N of an object with a mass of 10. kg?

d) How many square miles on the surface of the earth?

Need: For each part, conversion is ___________ (state whether definition,

conversion factor, geometry, or scientific law)

Know: Basic concepts of conversion factors, geometry and scientific

laws. Also the diameter of the Earth1 is 12,756 km

How: For conversions use units method

Solve: a) How many square miles in a square kilometer?

b) How many microfarads in a farad?

d) How many square miles on the surface of the earth?

1. E.g., http://hyperphysics.phy-astr.gsu.edu/hbase/solar/soldata2.html#c3

Solution Manual, Chapter 2, Elements of Engineering Analysis, Exploring Engineering, Kosky, Balmer,

Keat & Wise.

0.06

0.07

1

2

3

4

A B C D E F G

D, m h, m Area, m2$ material Seal, m $ seal Total $

0.01 =4*$I$3/(PI()*A2^2) =0.5*PI()*A2^2+PI()*A2*B2 =C2*$I$5 =B2+2*PI()*A2 =E2*$I$4 =D2+F2

=0.02+A2 =4*$I$3/(PI()*A3^2) =0.5*PI()*A3^2+PI()*A3*B3 =C3*$I$5 =B3+2*PI()*A3 =E3*$I$4 =D3+F3

=0.02+A3 =4*$I$3/(PI()*A4^2) =0.5*PI()*A4^2+PI()*A4*B4 =C4*$I$5 =B4+2*PI()*A4 =E4*$I$4 =D4+F4