978-0124081369 Chapter 9 Part 2

subject Type Homework Help
subject Pages 9
subject Words 1887
subject Authors Martin H. Sadd Ph.D.

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page-pf1
9.20.*
: PlotMATLAB
3
16
1
2
tanh,10,1010
a
b
For
2
tanh
11024
3
16
:form ldimensiona-Non
2
tanh
11024
3
16
: (9.5.12) relation From
3
4
4
4
3
3
5,3,1
5
4
5
3
4
5,3,1
55
43

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9.21.
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33
1
3
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22
223
16
3
16
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page-pf2
9.22.
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322
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required as vanish willfunction stress the, cos2 and boundary onClearly
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3
21
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212
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page-pf3
9.23*.
: PlotMATLAB
2
2
)(
by given isfactor ionconcentrat thecase notch small For the
)(0 case for the valueMaximum
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be tofound werestress the17,-9 ExerciseFrom
max
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page-pf4
9.24.
stronger is tubeclosed thusand tubeopen inhigher are Stresses
1 sincebut ,6
2
2
3
torquesame For the
2
3
8
3
stress for the equation eapproximat develop toused be can (9.5.15)
relations thenand shown, as stripa form tosection theopensimply tube,open For the
centerline by tube enclosedarea where,
2
tubeclosed for the (9.6.8), relation From
2
2,3

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sc
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page-pf5
9.25.
:solution General
)12(
8)12(1
equation Governing
)12sin()()form; theofsolution function stressfor Look
,2,1,0)12sin(
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2
,5,3,1;
8
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2
11
:equation Governing
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2
2
2
2
0
0
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22
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page-pf6
9.26.
62
11
4
4
222222
1
22
1
222
1
2
1
1
22
2
1
2
22
2
1
2
11
1
2
2
144
1
24sin4sin22;4sin4sin
7
7
4sin4sin
4sin4sin4cos4sin84sin4cos8
0
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page-pf7
9.27.
2.13
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)/(
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sin,cos hereboundary w on occurs stress maximum The
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3
1
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3
2
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where,
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3
max
3
3
34
3
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page-pf8
9.28*.
:sPrediciton Two Plot the and Calculate toMATLAB Using
tan
22
)2/(
cos
3
1
cos
3
2
2
cossin
)(:22-9 Exercise From
3334
max
33
4
max
+
=
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T
r
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r
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z
z
4 5 6 7 8 9 10
0
0.01
0.02
0.03
0.04
0.05
0.06
z
Max Shear Stress / T
Max Shear Stress Comparison
Mechanics of Materials
Elasticity Theory
page-pf9
9.29.
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2
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2
2
0,0
relations above theatingDifferenti
2223
21
4
)23(
2
1
2
1
22
1
2
1
)(0
2
1
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1
),(
2
)(
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2
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relationsnt Displaceme-Strain andlaw s Hooke'Using
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21
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page-pfa
9.29. Continued
( )
fieldnt displaceme theof form thedetermines results theseCollecting
634
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)(
24
)23(
)(
62
)(
2
)(
64
3
3
2
14
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page-pfb
9.30*.
:Case )( Plot MATLAB
1
8
3
1
8
3
)(
2
Solution Materialsof Strength
cosh
cosh
)1(12
1
)1(8
1
8
3
),0(
cosh
cosh
)1(12
)1(8
1
8
3
3
4
)2)(2(
12
1
,
cosh
cosh
)1(12
)1(6
)(
2
),0(
(9.9.18) relation from solution Elasticity
2
2
2
2
2
22
1
222
2
2
1
22
2
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32
2
33
1
22
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222
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0.2
0.25
0.3
0.35
0.4
Comparison with = 0.3
page-pfc
9.31.
into form thisngSubstituti .determined be oconstant ta is where,1
form theof choose weif satisfied be can 0 conditionboundary The
in
11
becomes equation aldifferenti governing theand,on0constant0
1
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choose weif so and ,1 boundary, theOn
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2
1
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