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August 7, 2019
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CHAPTER 4.
4.1
Risk Aversion: (Answers to a), b), c), and d) are given together here)
0
Y
2
Y
R
2
R
Y
2
R
0
Y
2
)
Y
(
‘
‘
U
0
Y
1
)
Y
(
‘
U
Y
1
)
Y
(
U
)
1
(
2
A
R
A
3
2
0
Y
1
Y
R
1
R
Y
1
R
0
Y
1
)
Y
(
‘
‘
U
0
Y
1
)
Y
(
‘
U
Y
ln
)
Y
(
U
)
2
(
2
A
R
A
2
1
2
A
R
A
2
(3
)
U
(
Y
)
Y
U
‘
(
Y
)
Y
0
0
U
‘
‘
(
Y
)
1
Y
0
1
R
Y
R
1
R
1
0
YY
0
Y
R
Y
R
R
0
Y
ex
p
)
Y
(
‘
‘
U
0
0
Y
ex
p
)
Y
(
‘
U
Y
ex
p
)
Y
(
U
)
4
(
R
R
A
2
0
Y
1
Y
R
1
R
Y
1
R
1
0
Y
1
)
Y
(
‘
‘
U
Y
)
Y
(
‘
U
Y
)
Y
(
U
)
5
(
2
A
R
A
2
1
0
R
Y
Y
R
Y
R
Y
Y
R
0
Y
2
4
Y
R
0
Y
Y
2
2
R
0
Y
2
2
R
0
2
)
Y
(
‘
‘
U
2
Y
0
Y
2
)
Y
(
‘
U
0
,
0
,
Y
Y
)
Y
(
U
)
6
(
A
A
A
R
2
2
A
R
A
2
AR
AR
AR
RR
1
U
Y
Y
1
Y
RR
U
Y
exp
Y
1
Y
RR
Y1
U
Y
1
Y
In the last utility function above, we should better use
1-
, so that
1
R
,
Y
1
R
and
,
1
Y
Y
Y
U
R
A
1
(look at R
R
= 1-
=
). After this change,
every derivative w.r.t.
is positive. If we increase
, we increase the level of risk
aversion (both absolute and relative).
4.2.
Certainty equivalent .
The problem to be solved is: find x such that
x
U
Y
U
Y
U
1
2
2
1
1
1
where
1
i
Y
denotes outcome of lottery L
1
in state i and
i
denotes the probability of state i.
4.3.
Risk premium.
The problem to be solved (indifference between insurance and no insurance) is
i
i
EU
Y
ln
Y
(i)
ln
1
00
,
00
0
P
where P is the insurance premium, Y
i
is the worth in state i and
)
i
(
is the probability of
state i. The solution to the problem is
P
100
,
000
exp
EU
Y
A
111
Ex
(2)
(4)
(9)
4
.75
424
%
5
)
8
6
1
(
3
1
x
~
E
B
2
2
2
2
A
111
(2
4.75
)
(4
4.75
)
(9
4
.75
)
6.6
875
424
2
2
2
2
B
)
5
8
(
3
1
)
5
6
(
3
1
)
5
1
(
3
1
= 26/3 =
3
2
8
.
So,
AB
Ex
Ex
%%
,
2
B
2
A
Thus we cannot compare the two investment opportunities using the mean-variance
criterion.
(ii) Now let’s compare them under FSD.
Let F(
A
x
~
) be denoted
~
A
x
~
B
x
~
4
‘
‘
2
4
)
‘
‘
1
(
6
‘
‘
10
.
5
1
.
1
‘
‘
2
,
55
.
2
1
.
1
‘
‘
Thus the probability premium is
05
.
50
.
55
.
The probability premium has fallen became the agent is wealthier in the case and is
4.7
No. R
eworking the data of Table 3.3 shows that it is not always the case that
0
dt
)
t
(
F
)
t
(
F
x
0
3
4
.
4.8 a) State by state dominance : no.
b) FSD : yes. See graph
P
ro
babili
t
y
1
1/3
2/3
10
20
z
~
z
~
y
~
y
~
and
These two notions are not equivalent.
4.9
Certainty equivalent.
The problem to be solved is: find Y such that
–
1
0
–
1
0
0
1
0
20
00
Y
Y
50
0
Y
10
00
Y
50
0
Y
2
10
00
Y
Y
2
50
0
Y
2
10
00
Y
10
00
Y
10
00
Y
1
00
0
Y
50
0
Y
2
10
00
Y
1
10
00
Y
1
50
0
Y
U
1
00
0
Y
U
2
1
10
00
Y
U
2
1
2
2
2
2
2
4.10.
Risk premium.
The problem to be solved is: find P such that
.
ex
p
Y
P
10
0
0
Y
ln
10
0
0
Y
ln
2
1
ex
p
P
Y
P
Y
ln
10
0
0
Y
ln
10
0
0
Y
ln
2
1
where P is the insurance premium.
50
.
0
10000
0
Y
P
13
.
50
10000
Y
P
The utility function is DARA, so the outcome (smaller premium associated with higher
wealth) was expected.
4.11.
Case 1 Case 2 Case 3
b
a
b
a
E
E
b
a
b
a
E
E
b
a
b
a
E
E
Case 1: cannot conclude with FSD, but B SSD
A
Case 2: A FSD
B, A SSD
B
Case 3: cannot conclude (general case)
4.12
a.
))
(
L
Y
(
EU
)
CE
Y
(
U
)
000
,
2
000
,
10
(
)
000
,
1
000
,
10
(
)
CE
000
,
10
(
2
.
2
.
2
.
2
.
)
000
,
6
000
,
10
(
15
.
2
.
)
000
,
5
000
,
10
(
20
.
2
.
)
000
,
3
000
,
10
(
35
.
2
.
2
.
2
.
173846
.
)
CE
000
,
10
(
2
.
752
.
5
173846
.
1
)
CE
000
,
10
(
2
.
CE = -3702.2
3450
)
6000
(
15
.
)
5000
(
2
.
)
3000
(
35
.
)
2000
(
2
.
)
1000
(
1
.
L
~
E
)
z
~
,
y
(
)
z
~
(
E
)
y
,
z
~
(
CE
2
.
252
)
z
~
,
y
(
If the agent were risk neutral the CE = – 3450
b. If
0
)
y
(
‘
‘
U
,
0
)
y
(
‘
U
, the agent loves risk. The premium would be negative here.
4.13
Current Wealth :
Y+
-L
0
1
Insurance Policy :
– p
h
h
0
1
Certainly
1
p
a.
Agent solves
)
ph
y
ln(
)
1
(
)
h
L
ph
y
ln(
ma
x
h
The F.O.C. is
ph
y
)
1
(
p
)
p
1
(
h
L
y
)
p
1
(
, which solves for
)
L
Y
(
p
1
1
p
Y
h
Note : if p = 0, h =
; if
Y
ph
,
1
.
b.
expected gain is
L
ph
c.
L
)
L
Y
(
p
1
1
p
Y
p
ph
p
d.
)
L
Y
(
p
1
1
p
Y
h
)
L
Y
(
1
1
Y
h
= L.
The agent will perfectly insure. None ; this is true for all risk averse individuals.
4.14
)
x
~
(
,
x
~
)
z
~
(
,
z
~
a.
4
.
6
4
.
2
3
2
1
)
2
(.
12
)
3
(.
10
)
4
(.
5
)
1
(.
10
x
~
E
7
.
5
3
8
.
5
.
1
4
.
)
1
(.
30
)
2
(.
4
)
5
(.
3
)
2
(
2
.
z
~
E
2
2
2
2
2
x
~
)
4
.
6
12
(
2
.
)
4
.
6
10
(
3
.
)
4
.
6
5
(
4
.
)
4
.
6
10
(
1
.
= 26.9 + .78 + 3.9 + 6.27
= 37.85
15
.
6
x
~
2
2
2
2
2
z
~
)
7
.
5
30
(
1
.
)
7
.
5
4
(
2
.
)
7
.
5
3
(
5
.
)
7
.
5
2
(
2
.
= 2.74 + 3.65 + .58 + 59.04
= 66.01
12
.
8
z
~
There is mean variance dominance in favor of
x
~
:
z
~
x
~
and
z
~
E
x
~
E
. The latter is due to the large outlying payment of 30.
b.
2
nd
order stochastic dominance :
r
)
r
(
F
x
~
r
0
x
dt
)
t
(
F
)
r
(
F
z
~
r
0
z
dt
)
t
(
F
r
0
z
x
dt
)
t
(
F
)
t
(
F
-10
.1
.1
0
0
.1
-9
.1
.2
0
0
.2
-8
.1
.3
0
0
.3
-7
.1
.4
0
0
.4
-6
.1
.5
0
0
.5
-5
.1
.6
0
0
.6
-4
.1
.7
0
0
.7
-3
.1
.8
0
0
.8
-2
.1
.9
0
0
.9
-1
.1
1.0
0
0
1.0
0
.1
1.1
0
0
1.1
1
.1
1.2
0
0
1.2
2
.1
1.3
.2
.2
1.1
3
.1
1.4
.7
.9
.5
4
.1
1.5
.9
1.8
-.3
4.15
Y
G
B
1
lot
t
e
r
y
ini
t
ia
l w
eal
t
h
a.
If he already owns the lottery,
s
P
must satisfy
)
B
Y
(
U
)
1
(
)
G
Y
(
U
)
P
Y
(
U
s
s
P
)
B
Y
(
U
)
1
(
)
G
Y
(
U
)
P
Y
(
U
s
b
P
:
)
B
P
Y
(
U
)
1
(
)
G
P
Y
(
U
)
Y
(
U
b
b
)
B
P
Y
)(
1
(
)
G
P
Y
(
Y
b
b
B
)
1
(
G
P
b
4.16
Mean
-variance: Ex
1
= 6.75,
22
.
15
)
(
2
1
; Ex
2
= 5.37,
25
.
4
)
(
2
2
; no dominance.
FSD: No dominance:
1
4
3
2
1
2
/
3
1
/
4
1
/
3
1
/
2
1
9
8
7
6
5
1 an
d
2
2
12
11
10
3
/
4
SSD:
x
dt
)
t
(
f
x
0
1
dt
)
t
(
F
x
0
1
dt
)
t
(
f
x
0
2
dt
)
t
(
F
x
0
2
dt
)
t
(
F
)
t
(
F
x
0
2
1
0
0
0
0
0
0
1
.25
.25
0
0
.25
2
.25
.50
0
0
.50
3
.25
.75
0
0
.75
4
.25
1
.33
.33
.67
5
.25
1.25
.33
.66
.67
6
.25
1.50
.66
1.32
.18
7
.50
2
.66
1.98
.02
8
.50
2.50
1
2.98
-.48
x
0
2
1
)
(
)
(
Using Expected utility. Generall
y speaking, one would expect
the more risk averse individuals to prefer investm
ent
2 while less risk averse age
nts would
tend to favor investm
e
nt 1