978-0123865496 Chapter 3 Solution Manual

subject Type Homework Help
subject Pages 9
subject Words 1789
subject Authors Jean-Pierre Danthine, John B. Donaldson

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page-pf1
CHAPTER 4.
4.1 Risk Aversion: (Answers to a), b), c), and d) are given together here)
0
Y
2
Y
R
2R Y
2
R
0
Y
2
)Y(''U
0
Y
1
)Y('U
Y
1
)Y(U )1(
2
A
R
A
3
2
0
Y
1
Y
R
1R Y
1
R
0
Y
1
)Y(''U
0
Y
1
)Y('U
Yln)Y(U )2(
2
A
R
A
2
1
2
A
R
A2
(3) U(Y) Y
U'(Y) Y 0 0
U''(Y) 1 Y 0
1
R Y
R 1
R1
0
YY




0
Y
R
YR
R
0Yexp)Y(''U
00Yexp)Y('U
Yexp)Y(U )4(
R
R
A
2
0
Y
1
Y
R
1R Y
1
R
10Y1)Y(''U
Y)Y('U
Y
)Y(U )5(
2
A
R
A
2
1
0RY
Y
R
YR
YY
R
0
Y2
4
Y
R
0Y
Y2
2
R
0
Y2
2
R
02)Y(''U
2
Y0Y2)Y('U
0,0,YY)Y(U )6(
A
A
A
R
2
2
A
R
A
2
page-pf2
AR
AR
AR
RR
1
U Y Y 1
Y
RR
U Y exp Y 1 Y
RR
Y1
U Y 1
Y






 
In the last utility function above, we should better use 1-, so that
(look at RR = 1- = ). After this change,
every derivative w.r.t. is positive. If we increase , we increase the level of risk
aversion (both absolute and relative).
4.2. Certainty equivalent .
The problem to be solved is: find x such that
xUYUYU 1
22
1
11
where
1
i
Y
denotes outcome of lottery L1 in state i and
i denotes the probability of state i.
page-pf3
4.3. Risk premium.
The problem to be solved (indifference between insurance and no insurance) is
i
i
EU Y lnY (i) ln 100,000 P
where P is the insurance premium, Yi is the worth in state i and
)i(
is the probability of
state i. The solution to the problem is
P 100,000 exp EU Y
page-pf4
A
111
Ex (2) (4) (9) 4.75
424
%
5)861(
3
1
x
~
EB
2 2 2 2
A
111
(2 4.75) (4 4.75) (9 4.75) 6.6875
424
2222
B)58(
3
1
)56(
3
1
)51(
3
1
= 26/3 =
3
2
8
.
So,
AB
Ex Ex
%%
,
2
B
2
A
Thus we cannot compare the two investment opportunities using the mean-variance
criterion.
(ii) Now let’s compare them under FSD.
Let F(
A
x
~
) be denoted
~
page-pf5
page-pf6
4''24)''1(6''10.5
1.1''2
,
55.
2
1.1
''
Thus the probability premium is
05.50.55.
The probability premium has fallen became the agent is wealthier in the case and is
4.7 No. Reworking the data of Table 3.3 shows that it is not always the case that
0dt)t(F)t(F
x
034
.
4.8 a) State by state dominance : no.
b) FSD : yes. See graph
Probability
1
1/3
2/3
10 20
z
~
z
~
y
~
y
~
and
These two notions are not equivalent.
4.9 Certainty equivalent.
The problem to be solved is: find Y such that
-
1
0
-
1
0
0
1
0
page-pf7
2000Y
Y500Y1000Y
500Y
2
1000Y
Y2
500Y
2
1000Y1000Y
1000Y1000Y
500Y
2
1000Y
1
1000Y
1
500YU1000YU
2
1
1000YU
2
1
222
22
4.10. Risk premium.
The problem to be solved is: find P such that
.expYP
1000Yln1000Yln
2
1
expPY
PYln1000Yln1000Yln
2
1
where P is the insurance premium.
50.0100000YP
13.5010000YP
The utility function is DARA, so the outcome (smaller premium associated with higher
wealth) was expected.
4.11. Case 1 Case 2 Case 3
ba
ba
EE
ba
ba
EE
ba
ba
EE
Case 1: cannot conclude with FSD, but B SSD A
Case 2: A FSD B, A SSD B
Case 3: cannot conclude (general case)
4.12 a.
))(LY(EU)CEY(U
)000,2000,10(
)000,1000,10(
)CE000,10( 2.2.2.
page-pf8
2.
)000,6000,10(
15.
2.
)000,5000,10(
20.
2.
)000,3000,10(
35. 2.2.2.
173846.)CE000,10(2.
752.5
173846.
1
)CE000,10(2.
CE = -3702.2
3450
)6000(15.)5000(2.)3000(35.)2000(2.)1000(1.L
~
E
)z
~
,y()z
~
(E)y,z
~
(CE
2.252)z
~
,y(
If the agent were risk neutral the CE = - 3450
b. If
0)y(''U,0)y('U
, the agent loves risk. The premium would be negative here.
4.13 Current Wealth :
Y+
-L
0
1
Insurance Policy :
- ph
h
0
1
Certainly
1p
a. Agent solves
)phyln()1()hLphyln(max
h
The F.O.C. is
phy
)1(p
)p1(hLy
)p1(
, which solves for
)LY(
p1
1
p
Yh
Note : if p = 0, h =
; if
Yph,1
.
b. expected gain is
Lph
page-pf9
c.
L)LY(
p1
1
p
Ypph
p
d.
)LY(
p1
1
p
Yh
)LY(
1
1
Yh
= L.
The agent will perfectly insure. None ; this is true for all risk averse individuals.
4.14
)x
~
(,x
~
)z
~
(,z
~
a.
4.64.2321)2(.12)3(.10)4(.5)1(.10x
~
E
7.538.5.14.)1(.30)2(.4)5(.3)2(2.z
~
E
22222
x
~)4.612(2.)4.610(3.)4.65(4.)4.610(1.
= 26.9 + .78 + 3.9 + 6.27
= 37.85
15.6
x
~
22222
z
~)7.530(1.)7.54(2.)7.53(5.)7.52(2.
= 2.74 + 3.65 + .58 + 59.04
= 66.01
12.8
z
~
There is mean variance dominance in favor of
x
~
:
z
~
x
~
and z
~
Ex
~
E
. The latter is due to the large outlying payment of 30.
b. 2nd order stochastic dominance :
r
)r(Fx
~
r
0xdt)t(F
)r(Fz
~
r
0zdt)t(F
r
0zx dt)t(F)t(F
-10
.1
.1
0
0
.1
-9
.1
.2
0
0
.2
-8
.1
.3
0
0
.3
-7
.1
.4
0
0
.4
-6
.1
.5
0
0
.5
-5
.1
.6
0
0
.6
-4
.1
.7
0
0
.7
-3
.1
.8
0
0
.8
-2
.1
.9
0
0
.9
-1
.1
1.0
0
0
1.0
0
.1
1.1
0
0
1.1
1
.1
1.2
0
0
1.2
2
.1
1.3
.2
.2
1.1
3
.1
1.4
.7
.9
.5
page-pfa
4
.1
1.5
.9
1.8
-.3
4.15
Y
G
B
1
lottery
initial wealth
a. If he already owns the lottery,
s
P
must satisfy
)BY(U)1()GY(U)PY(U s
page-pfb
b
P
:
)BPY(U)1()GPY(U)Y(U bb
)BPY)(1()GPY(Y bb
B)1(GPb
4.16 Mean-variance: Ex1 = 6.75,
22.15)( 2
1
; Ex2 = 5.37,
25.4)( 2
2
; no dominance.
FSD: No dominance:
1
4321
2/3
1/4
1/3
1/2
1
98765
1 and 2
2
121110
3/4
SSD:
x
dt)t(f
x
01
dt)t(F
x
01
dt)t(f
x
02
dt)t(F
x
02
dt)t(F)t(F
x
021
0
0
0
0
0
0
1
.25
.25
0
0
.25
2
.25
.50
0
0
.50
3
.25
.75
0
0
.75
4
.25
1
.33
.33
.67
5
.25
1.25
.33
.66
.67
6
.25
1.50
.66
1.32
.18
7
.50
2
.66
1.98
.02
8
.50
2.50
1
2.98
-.48
x
0
21 )()(
Using Expected utility. Generally speaking, one would expect the more risk averse individuals to prefer investment
2 while less risk averse agents would tend to favor investment 1

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