I9000ˆ
J3000 ˆ
Problem 4.1 For each of the following geocentric equatorial position vectors (in kilometers) find the
right ascension and declination.
(a)
r9000ˆ
I6000ˆ
J3000 ˆ
K
Solutions Manual Orbital Mechanics for Engineering Students Third Edition Chapter 4
cos
360  cos10.534522
cos 15.5014
 
360  56.3099  303.69
Problem 4.2 At a given instant, a spacecraft is 500 km above the earth, with a right ascension of 300°
and declination of 20° relative to the geocentric equatorial frame. Its velocity is 10 km/s directly north,
normal to the equatorial plane. Find its right ascension and declination 30 minutes later.
cos
cos10.433077
cos 29.9853
 
120
Problem 4.3 Find the orbital elements of a geocentric satellite whose inertial position and velocity vec-
tors in a geocentric equatorial frame are
r2500ˆ
I16,000ˆ
J4000 ˆ
K km
 
v 3ˆ
Iˆ
J5ˆ
K km s
 
Problem 4.4 At a given instant the position
r
and velocity
v
of a satellite in the geocentric equatorial
frame are
r 13,000 ˆ
K (km)
and
v4ˆ
i5ˆ
J6ˆ
K (km/ s)
. Find the orbital elements.
(13)
360  cos1er
er
360  74.939  285.06
Problem 4.5 At time
t0
(relative to perigee passage) the position
r
and velocity
v
of a satellite in the
geocentric equatorial frame are
r6500ˆ
I7500ˆ
J2500 ˆ
K (km)
and
v4ˆ
I3ˆ
J3ˆ
K (km/ s)
. Find the or-
bital elements.
Ne
(13)
cos1er
er
134.73
Problem 4.6 Given that, with respect to the geocentric equatorial frame,
r 6000ˆ
I1000ˆ
J5000 ˆ
K
(km),
v6ˆ
I7ˆ
J2ˆ
K
(km/s)
and the eccentricity vector is
e 0.4ˆ
I0.5ˆ
J0.6 ˆ
K
,
calculate the true anomaly
of the earth-orbiting satellite.
6909.41
360  cos10.853907
 
360  31.3608  328.639
Problem 4.7 Given that, relative to the geocentric equatorial frame
r 6600ˆ
I1300ˆ
J5200 ˆ
K km
 
,
the eccentricity vector is
e 0.4ˆ
I0.5ˆ
J0.6 ˆ
K
,
and the satellite is flying towards perigee, calculate the inclination of the orbit.
i43.2661
Problem 4.8 The right-handed, primed xyz system is defined by the three points A, B and C. The x’y’
plane is defined by the plane ABC. The
x
axis runs from A through B. The
z
axis is defined by the cross
product of
A B
into
A C
, so that the
y
axis lies on the same side of the
x
axis as point C.
(a) Find the direction cosine matrix
Q
 
relating the two coordinate bases.
(b) If the components of a vector
v
in the primed system are
21 3
T
, find the components
of
v
in the unprimed system.
T
0.55709 0.063314 0.82804
2
1.3066
v 1.3066ˆ
Problem 4.9 The unit vectors in a uvw Cartesian coordinate frame have the following components in
the xyz frame:
ˆ
u0.26726ˆ
i0.53452ˆ
j0.80178 ˆ
k
ˆ
v 0.44376ˆ
i0.80684ˆ
j0.38997 ˆ
k
ˆ
w 0.85536ˆ
i0.25158ˆ
j0.45284 ˆ
k
If, in the xyz frame
V 50ˆ
i100ˆ
j75 ˆ
k
, find the components of the vector
V
in the uvw frame.
V100.22 ˆ
Solutions Manual Orbital Mechanics for Engineering Students Third Edition Chapter 4
Problem 4.10 Calculate the direction cosine matrix
Q
 
for the sequence of two rotations:
40
about the positive X axis, followed by
25
about the positive
y
axis. The result is that the XYZ axes
are rotated into the
x
y
z
axes.
Problem 4.11 For the direction cosine matrix
Q
 
0.086824 0.77768 0.62264
0.49240 0.57682 0.65178
0.86603 0.25000 0.43301
calculate,
(a) the classical Euler angle sequence
(b) the yaw, pitch and roll angle sequence.
276.37
sin 1Q13
 sin 10.62264
 
236.40
Problem 4.12 What yaw, pitch and roll sequence yields the same DCM as the classical Euler sequence
350
,
170
,
300
?
174.96
Problem 4.13 What classical Euler angle sequence yields the same DCM as the yaw-pitch-roll sequence
300
,
 80
,
30
?
84.962
Problem 4.14 At time
t0
the position
r
and velocity
v
of a satellite in the geocentric equatorial frame
are:
r 5000ˆ
I8000ˆ
J2100 ˆ
K km
 
v 4ˆ
I3.5ˆ
J3ˆ
K km s
 
Find
r
and
v
at time
t050 minutes
. (
t00!
)
8
h
0
398,600
58,963
0
0
km s