8-123E Argon enters an adiabatic compressor with an isentropic efficiency of 80% at a specified state, and leaves at a
specified pressure. The exit temperature of argon and the work input to the compressor are to be determined.
Assumptions 1 This is a steady-flow process since there is no change with time. 2 Potential energy changes are negligible. 3
The device is adiabatic and thus heat transfer is negligible. 4 Argon is an ideal gas with constant specific heats.
Properties The specific heat ratio of argon is k = 1.667. The constant pressure
specific heat of argon is cp = 0.1253 Btu/lbm.R (Table A-2E).
Analysis (a) The isentropic exit temperature T2s is determined from
psia 200
70.667/1.66
/1
2
kk
s
P
/sft 25,037
2
222
The effect of kinetic energy on isentropic efficiency is very small. Therefore, we can take the kinetic energy changes for the
actual and isentropic cases to be same in efficiency calculations. From the isentropic efficiency relation, including the effect
outin
energies etc. potential,
kinetic, internal,in change of Rate
(steady ) 0
sy stem
mass and work,heat,by
nsferenergy tranet of Rate
outin 0
EE
EEE
a12a12ina,
1
2
12ina,
2
22
2
11ina,
Δke)(Δke
2
0)pe (since /2)+()2/(
TTchhwhhmW
QVhmVhmW
ap
VV
Substituting, the work input to the compressor is determined to be